1, a) tinh nhanh : 20,1 x 134,77 + 6,7 x 24,6 x 3 - 6x 59,37 x 3,35 b) tim y , biet : 5/12 x ( 8+y ) -1/5 x ( 15/4 + y ) = 15
Những câu hỏi liên quan
1.a/tinh nhanh
1,8 x 9 - x 0,8
b/tim y
y : 6,7 = 7,8 + 8
a) 1,8 x 9 - 0,8
= ( 1,8 - 0,8 ) x 9
= 1 x 9
= 9
b) y : 6,7 = 7,8 + 8
y : 6,7 = 8,6
y = 8,6 x 6,7
y = 57,62
Kết bn với mik nha!
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Bài a) ko rỏ em rỏ lại anh trả lời sau
Bài B) y : 6,7 =7,8 + 8
y : 6,7 =15,8
y=15,8 X 6,7
y=105,86
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a,tim x biet |x-2|+|3-2x|=2x+1
b,tim x,y thuoc Z biet xy+2x-y=5
c, tinh A=(1-1/15)(1-1/21)(1-1/28).....(1-1/210)
1. tim x biet :
a, (x-2)(x+3) > 2x\(^2\) -x -5
b, x( x-5) > x-4
2. cho 2 so x va y thoa man : x+y = 7 va xy=2 . khong tinh x va y , hay tinh gia tri cua bieu thuc A= x - y ( biet x< y)
Câu 1:
a: \(\Leftrightarrow2x^2-x-5< x^2+x-6\)
\(\Leftrightarrow x^2-2x+1< 0\)
hay \(x\in\varnothing\)
b: \(\Leftrightarrow x^2-5x-x+4>0\)
\(\Leftrightarrow x^2-6x+4>0\)
\(\Leftrightarrow\left(x-3\right)^2>5\)
hay \(\left[{}\begin{matrix}x>\sqrt{5}+3\\x< -\sqrt{5}+3\end{matrix}\right.\)
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Tính giá trị của biểu thức:
a)(95,74 –21,67) : 3,75 + 0,368
b)198,35 + 13,45 : 0,125 –104,75
c)24,6 : 0,75 + 12,5 x 13,48
d)3 + 20,1 x 12,5 : 0,125
Tim x biet Bai 1: Tim cap so (x,y) biet: frac{1+3y}{12}frac{1+5y}{5x}frac{1+7y}{4x}Bai 2; Cho frac{a}{b}frac{b}{c}frac{c}{a}va a,b,c khac ; a2012. tinh b,cBai 3: tim cac so x,y,z biet :frac{y+x+1}{x}frac{x+z+2}{y}frac{x+y-3}{z}frac{1}{x+y+z}Bai 4: Tim x, biet rang:frac{1+2y}{18}frac{1+4y}{24}frac{1+6y}{6x} giup minh di minh dang rat gap cam on
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Tim x biet
Bai 1: Tim cap so (x,y) biet: \(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
Bai 2; Cho \(\frac{a}{b}\)=\(\frac{b}{c}\)=\(\frac{c}{a}\)va a,b,c khac ; a=2012. tinh b,c
Bai 3: tim cac so x,y,z biet :
\(\frac{y+x+1}{x}\)=\(\frac{x+z+2}{y}\)=\(\frac{x+y-3}{z}\)=\(\frac{1}{x+y+z}\)
Bai 4: Tim x, biet rang:\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
giup minh di minh dang rat gap cam on
bài 4 : Ta có : \(\frac{1+2y}{18}=\frac{1+4y}{24}\left(1\right)\)
\(\Rightarrow24+48y=18+72y
\)
\(\Rightarrow y=\frac{1}{4}\)
\(\frac{1+4y}{24}=\frac{1+6y}{6x}\left(2\right)\)
Thay y = \(\frac{1}{4}\) vào (2) ta được x = 5 (thõa mãn )
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Ta có VT=\(\frac{y+z+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
=\(\frac{2\left(x+y+z\right)}{x+y+z}\)=2 (1) => x+y+z=\(\frac{1}{2}\) <=> \(y+z=\frac{1}{2}-x\)
<=> \(x+z=\frac{1}{2}-y\)
<=> \(x+y=\frac{1}{2}-z\)
Thay \(y+z=\frac{1}{2}-x\)vào (1) ta có:.................................................................
Lúc nào tớ rảnh thì gửi thêm!!!!!!!!!!!!!!!!!!!!!!!!!
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tim x biet: a) |x+2| - 6x=7 b) |x-3|+|x+2|=7
bai 3 : khong lam tinh hay tim a trong cac phep tinh sau :
a] 95 x [ a - 75 ] = 95 x [ 100 - 75 ]
b ] 2003 + a x 15 = 2003 + 10 x 3 x5
minh biet la no bang nhau nhung khong biet trinh bay
ai giai nhanh duoc 3 like
a) a = 100
câu b đề sai
2003 mà bằng 10 x 3 x 5 à
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CHO HAM SO : y=x \(^2\) - 5x +6
a) tim cac gia tri cua x sao cho ve phai cua cong thuc co nghia
b) tinh y ; biet x= -\(\frac{1}{3}\) ; x= 0,5 ; x=0 ; x=1
c) tim x khi biet y = 0
BAI 1.phan tich cac da thuc sau thanh nhan tu:
a,2x^2-2xy-5x+5y
b,8x^2+4xy-2ax-ay
c,x^3-4x^2+4x
d,2xy-x^2-y^2+16
e,x^2-y^2-2yz-z^2
g,3a^2-6ab+3b^2-12c^2
BAI 2.tinh nhanh
a,37,5.8,5-7,5.3,4-6,6.7,5+1,5.37,5
b,35^2+40^2-25^2+80.35
BAI 3. Tim x biet:
a,x^3-1/9x0
b,2x-2y-x^2+2xy-y^20
c,x(x-3)+x-30
d,x^2(x-3)+27-9x0
BAI 4.Phan tich cac da thuc sau thanh nhan tu
a,x^2-4x+3
goi y :tach-4x-x3xhoac tach3-1+4
b,x^2+x-6
c,x^2-5x+6
d,x^4+4 (goi y:them va bot 4x^2)
BAI 5.Chung minh rang;...
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BAI 1.phan tich cac da thuc sau thanh nhan tu:
a,2x^2-2xy-5x+5y
b,8x^2+4xy-2ax-ay
c,x^3-4x^2+4x
d,2xy-x^2-y^2+16
e,x^2-y^2-2yz-z^2
g,3a^2-6ab+3b^2-12c^2
BAI 2.tinh nhanh
a,37,5.8,5-7,5.3,4-6,6.7,5+1,5.37,5
b,35^2+40^2-25^2+80.35
BAI 3. Tim x biet:
a,x^3-1/9x=0
b,2x-2y-x^2+2xy-y^2=0
c,x(x-3)+x-3=0
d,x^2(x-3)+27-9x=0
BAI 4.Phan tich cac da thuc sau thanh nhan tu
a,x^2-4x+3
goi y :tach-4x=-x3xhoac tach3=-1+4
b,x^2+x-6
c,x^2-5x+6
d,x^4+4 (goi y:them va bot 4x^2)
BAI 5.Chung minh rang;
(3n+4)^2-16 chia het cho 3 voi moi so nguyen n.
BAI 6.Tinh gia tri cua bieu thuc sau:
M=a^3-a^2b-ab^2+b^3 voi a=5,75:b=4,25
BAI 7.Tim x biet:
a,x^2+x=6
b,6x^3+x^2=2x
Bài 1 câu g bạn kia làm sai mình sửa lại nhá
\(3a^2-6ab+3b^2-12c^2\)
\(=3\left(a^2-2ab+b^2\right)-12c^2\)
\(=3\left(a-b\right)^2-12c^2\)
\(=3\left[\left(a-b\right)^2-4c^2\right]\)
\(=3\left(a-b-2c\right)\left(a-b+2c\right)\)
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Để mình làm tiếp cho :))
Bài 2 :
Câu a : \(37,5.8,5-7,5.3,4-6,6.7,5+1,5.37,5\)
\(=\left(37,5.8,5+1,5.37,5\right)-\left(7,5.3,4+6,6.7,5\right)\)
\(=37,5\left(8,5+1,5\right)-7,5\left(3,4+6,6\right)\)
\(=37,5.10-7,5.10\)
\(=10.30=300\)
Câu b : \(35^2+40^2-25^2+80.35\)
\(=\left(35^2+80.35+40^2\right)-25^2\)
\(=\left(30+45\right)^2-25^2\)
\(=75^2-25^2\)
\(=\left(75+25\right)\left(75-25\right)\)
\(=100.50=5000\)
Bài 3 :
Câu a : \(x^3-\dfrac{1}{9}x=0\)
\(\Leftrightarrow x\left(x^2-\dfrac{1}{9}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x^2-\dfrac{1}{9}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\pm\dfrac{1}{3}\end{matrix}\right.\)
Câu b : \(2x-2y-x^2+2xy-y^2=0\)
\(\Leftrightarrow2\left(x-y\right)-\left(x-y\right)^2=0\)
\(\Leftrightarrow\left(x-y\right)\left(2-x+y\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-y=0\\2-x+y=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=y\\x+y=2\Rightarrow x=2-y\end{matrix}\right.\)
Câu c :
\(x\left(x-3\right)+x-3=0\)
\(\Leftrightarrow\left(x-3\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
\(x^2\left(x-3\right)+27-9x=0\)
\(\Leftrightarrow x^2\left(x-3\right)-9\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x^2-9\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x^2-9=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=\pm3\end{matrix}\right.\)
Bài 4 :
Câu a :
\(x^2-4x+3\)
\(=x^2-x-3x+3\)
\(=\left(x^2-x\right)-\left(3x-3\right)\)
\(=x\left(x-1\right)-3\left(x-1\right)\)
\(=\left(x-1\right)\left(x-3\right)\)
Câu b :
\(x^2+x-6\)
\(=x^2-2x+3x-6\)
\(=x\left(x-2\right)+3\left(x-2\right)\)
\(=\left(x-2\right)\left(x+3\right)\)
Câu c :
\(x^2-5x+6\)
\(=x^2-2x-3x+6\)
\(=\left(x^2-2x\right)-\left(3x-6\right)\)
\(=x\left(x-2\right)-3\left(x-2\right)\)
\(=\left(x-2\right)\left(x-3\right)\)
Câu d :
\(x^4+4\)
\(=x^4+4x^2+4-4x^2\)
\(=\left(x^2+2\right)^2-\left(2x\right)^2\)
\(=\left(x^2+2-2x\right)\left(x^2+2+2x\right)\)
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Bài 1:
a) \(2x^2-2xy-5x+5y\)
\(=\left(2x^2-2xy\right)-\left(5x-5y\right)\)
\(=2x\left(x-y\right)-5\left(x-y\right)\)
\(=\left(x-y\right)\left(2x-5\right)\)
b) \(8x^2+4xy-2ax-ay\)
\(=\left(8x^2+4xy\right)-\left(2ax+ay\right)\)
\(=4x\left(2x+y\right)-a\left(2x+y\right)\)
\(=\left(2x+y\right)\left(4x-a\right)\)
c) \(x^3-4x^2+4x\)
\(=x\left(x^2-4x+4\right)\)
\(=x\left(x-2\right)^2\)
d) \(2xy-x^2-y^2+16\)
\(=-\left[\left(x^2-2xy+y^2\right)-16\right]\)
\(=-\left[\left(x-y\right)^2-4^2\right]\)
\(=-\left[\left(x-y-4\right)\left(x-y+4\right)\right]\)
e) \(x^2-y^2-2yz-z^2\)
\(=-\left[\left(z^2+2yz+y^2\right)-x^2\right]\)
\(=-\left[\left(z+y\right)^2-x^2\right]\)
\(=-\left[\left(z+y+x\right)\left(z+y-x\right)\right]\)
g) \(3a^2-6ab+3b^2-12c^2\)
\(=\left(3a^2-6ab+3b^2\right)-12c^2\)
\(=\left(\sqrt{3a}+\sqrt{3b}\right)^2-12c^2\)
\(=\left(\sqrt{3a}+\sqrt{3b}+\sqrt{12c}\right)\left(\sqrt{3a}+\sqrt{3b}-\sqrt{12c}\right)\)
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