\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\frac{-3}{22}+\frac{5}{9}:\frac{-3}{5}\)
\(=\frac{5}{9}\cdot\frac{-22}{3}+\frac{5}{9}\cdot\frac{-5}{3}\)
\(=\frac{5}{9}\cdot\left(\frac{-22}{3}+\frac{-5}{3}\right)\)
\(=\frac{5}{9}\cdot\left(-9\right)\)
\(=-5\)
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left(\frac{-3}{22}\right)+\frac{5}{9}:\left(-\frac{3}{5}\right)\)
\(=\frac{5}{9}.\left(\frac{-22}{3}\right)+\frac{5}{9}.\left(-\frac{5}{3}\right)\)
\(=-\frac{110}{27}+-\frac{25}{27}\)
\(=-5\)
Em làm thế đúng không các anh chị?
đúng đó nhưng bạn nên nhóm \(\frac{-22}{3}\)và \(\frac{-5}{3}\)vào với nhau và đặt \(\frac{5}{9}\)ra ngoài sẽ tính nhanh hơn
a.\(\left(\frac{-2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
b. \(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
Tính
a) \(\left(-\frac{2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(-\frac{1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
b) \(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(\left(\frac{-2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
\(=\left(\frac{-2}{3}+\frac{3}{7}+\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
\(=\left[\left(\frac{-2}{3}+\frac{-1}{3}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)\right]:\frac{4}{5}\)
\(=\left[\left(-1+1\right)\right]:\frac{4}{5}\)
\(=0:\frac{4}{5}=0\)
~ Hok tốt ~
cau A= o nha ban con cau B minh ko chac vi so minh ra hoi lon 1 ti
a,\(\left(-\frac{2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(-\frac{1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
=\(\left[\left(-\frac{2}{3}+\frac{3}{7}\right)+\left(-\frac{1}{3}+\frac{4}{7.}\right)\right]:\frac{4}{5}\)
=\(\left[-\frac{5}{21}+\frac{5}{21}\right]:\frac{4}{5}\)
=\(0:\frac{4}{5}=0\)
b,\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
=\(\frac{5}{9}:\left[\left(\frac{1}{11}-\frac{5}{22}\right)+\left(\frac{1}{15}-\frac{2}{3}\right)\right]\)
=\(\frac{5}{9}:\left[-\frac{3}{22}-\frac{3}{5}\right]\)
=\(\frac{5}{9}:\left[-\frac{81}{110}\right]\)
=\(-\frac{550}{729}\)
#hok tốt#
Thực hiện phép tính
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left(\frac{-3}{22}\right)+\frac{5}{9}:\left(\frac{-3}{5}\right)\)
\(=\frac{5}{9}.\left(-\frac{22}{3}\right)+\frac{5}{9}.\left(-\frac{5}{3}\right)\)
\(=\frac{5}{9}.\left[-\frac{22}{3}+\left(-\frac{5}{3}\right)\right]\)
\(=\frac{5}{9}.\left(-9\right)\)
\(=-5\)
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left[\left(\frac{1}{11}-\frac{5}{22}\right)+\left(\frac{1}{15}-\frac{2}{3}\right)\right]\)
\(=\frac{5}{9}:\left[-\frac{3}{22}-\frac{3}{5}\right]\)
\(=\frac{5}{9}:\frac{-81}{110}=\frac{5}{9}.\frac{-110}{81}\)
\(=-\frac{550}{729}\)
1 tính
b)\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
tính :
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(\frac{5}{9}:\frac{-3}{22}+\frac{5}{9}:\frac{-3}{5}\)
=\(\frac{5}{9}.\frac{-22}{3}+\frac{5}{9}.\frac{-5}{3}\)
=\(\frac{5}{9}.\left(\frac{-22}{3}-\frac{5}{3}\right)\)
=\(\frac{5}{9}.\left(-9\right)\)
=-5
cái ảnh của minh anh coi truong
gớm
Thực hiện phép tính
\(\frac{5}{9}:\:\left(\frac{1}{11}-\frac{5}{22}\right)+\:\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
Ta có: \(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left(\frac{2}{22}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{10}{15}\right)\)
\(=\frac{5}{9}:\frac{-3}{22}+\frac{5}{9}:\frac{-9}{15}=\frac{5}{9}\cdot\frac{-22}{3}+\frac{5}{9}\cdot\frac{-5}{3}\)
\(=\frac{5}{9}\left(-\frac{22}{3}+\frac{-5}{3}\right)=\frac{5}{9}\cdot-9=-5\)
Thực hiện phép tính
\(\frac{5}{9}.\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}.\left(\frac{1}{15}-\frac{2}{3}\right)\)
BT = \(\frac{5}{9}\left(\frac{2}{22}-\frac{5}{22}\right)+\frac{5}{9}\left(\frac{1}{15}-\frac{10}{15}\right)\)
= \(\frac{5}{9}.\frac{-3}{22}+\frac{5}{9}.\frac{-3}{5}\)
= \(\frac{-5}{3}\left(\frac{1}{22}+\frac{1}{5}\right)\) = \(\frac{-5}{3}\left(\frac{5}{110}+\frac{22}{110}\right)\) = \(\frac{-5}{3}.\frac{27}{110}=\frac{-9}{22}\)
\(\frac{5}{9}.\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}.\left(\frac{1}{15}-\frac{2}{3}\right)\)
= \(\frac{5}{9}.\left(-\frac{3}{22}\right)+\frac{5}{9}.\left(-\frac{3}{5}\right)\)
= \(\frac{5}{9}.\left(-\frac{3}{22}+\frac{-3}{5}\right)\)
= \(\frac{5}{9}.\left(-\frac{81}{110}\right)\)
= \(-\frac{9}{22}\)