thực hiện phép tính
128-[68+8(37-35) mũ 2]:4
Thực hiện phép tính :
a) 2014 + (-1999) + 1986 + 175 + (-2001)
b) 59 x 73 - 30^2 + 27 x 59
c) 128 - ( 68 + 8 x ( 37 - 35 )^2) : 4
a , 2014+(-1999)+1986+175+(-2001) = (2014+1986)+(-1999+-2001)+175
= 4000 + -4000 +175
= 175
roi tu lam nhe minh ban roi phai day
nice to meet you
Bài 1: Thực hiện phép tính:
a) 3.52 + 15.22 – 26:2
b) 53.2 – 100 : 4 + 23.5
c) 62 : 9 + 50.2 – 33.3
d) 2345 – 1000 : [19 – 2(21 – 18)2]
e) 128 – [68 + 8(37 – 35)2] : 4
f) 568 – {5[143 – (4 – 1)2] + 10} : 10
e: \(=128-\left[68+8\cdot4\right]:4=128-25=103\)
\(a.3.5^2+15.2^2-26:2\) \(b.5^3.2-100:4+2^3.5\)
\(=75+60-13\) \(=250-25+40\)
\(=135+13=148\) \(=265\)
\(c.6^2:9+50.2-3^3.3\) \(d.2345-1000:\left[19-2.\left(21-18\right)^2\right]\)
\(=4+100-81\) \(=2345-1000:\left[19-2.3^2\right]\)
\(=23\) \(=2345-1000:\left[19-18\right]\)
\(=2345-1000:1\)
\(=2345-1000=1345\)
\(e.128-\left[68+8.\left(37-35\right)^2\right]:4\)
\(=128-\left[68+8.2^2\right]:4\)
\(=128-\left[68+32\right]:4\)
\(=128-100:4\)
\(=128-25=103\)
\(f.568-\left\{5.\left[143-\left(4-1\right)^2\right]+10\right\}:10\)
\(=568-\left\{5.\left[143-3^2\right]+10\right\}:10\)
\(=568-\left\{5.134+10\right\}:10\)
\(=568-\left\{670+10\right\}:10\)
\(=568-680:10\)
\(=568-68=500\)
Bài 1:
a, 2.31.12 +4.6.42 + 8.27.3
b, 2020 mũ 0 + 5 mũ 4 : 5 mũ 2 - 9.2
c, (-38) - ( -147 ) + ( -115 )
d, 2 mũ 4. - [ 68 + 8.( 37 - 35 ) mũ 2 ] :4
\(b, 2020^ 0 + 5^ 4 : 5^ 2 - 9.2 \)
\(=1+25-18\)
\(= 26-18=8\)
a)
(2.31.12)+(4.6.42)+(8.27.3)
=(24.31)+(24.42)+(24.27)
=24.(31+42+27)=24.100=2400
Thực hiện phép tính:
a) 2010 - 2000 : [486 - 2(72 - 6)]
b) 2345 - 1000 : [19 - 2(21 - 18)2 ]
c) 128 - [68 + 8(37 - 35)2 ] : 4
d) 568 - {5[143 - (4 - 1)2 ] + 10} : 10
a) 2010 - 2000 : [486 - 2(72 - 6)]
= 2010 - 2000 : [486 - 2(49 - 6)]
= 2010 - 2000 : [486 - 2 . 43]
= 2010 - 2000 : [486 - 86]
= 2010 - 2000 : 400
= 2010 - 5
= 2005
b) 2345 - 1000 : [19 - 2(21 - 18)2 ]
= 2345 - 1000 : [19 - 2 . 32 ]
= 2345 - 1000 : [19 - 18]
= 2345 - 1000 : 1
= 2345 - 1000
= 1345
c) 128 - [68 + 8(37 - 35)2 ] : 4
= 128 - [68 + 8 . 22 ] : 4
= 128 - [68 + 32 ] : 4
= 128 - 100 : 4
= 128 - 25
= 103
d) 568 - {5[143 - (4 - 1)2 ] + 10} : 10
= 568 - {5[143 - 9 ] + 10} : 10
= 568 - {5 . 134 + 10 } : 10
= 658 - {670 + 10 } : 10
= 658 - 680 : 10
= 658 - 68
= 590
Thực hiện phép tính:
1, -7/12. 11/8- 37/8. 7/12+ 1/2
2, ( 2/3- 1/4- 5/6 ). ( -2) mũ 2 + 3/2: -15/4
3, -2/5+ 3/10- 3/5+ 7/10- 3/2
\(\left(1\right)\dfrac{-7}{12}.\dfrac{11}{8}-\dfrac{37}{8}.\dfrac{7}{12}+\dfrac{1}{2}=-\dfrac{7}{12}.\left(\dfrac{11}{8}+\dfrac{37}{8}\right)+\dfrac{1}{2}=-\dfrac{7}{12}.6+\dfrac{1}{2}=-3.\)
\(\left(2\right)\left(\dfrac{2}{3}-\dfrac{1}{4}-\dfrac{5}{6}\right).\left(-2\right)^2+\dfrac{3}{2}:\dfrac{-15}{4}=\dfrac{-5}{12}.4-\dfrac{2}{5}=\dfrac{-5}{3}-\dfrac{2}{5}=\dfrac{-31}{15}.\)
\(\left(3\right)\dfrac{-2}{5}+\dfrac{3}{10}-\dfrac{3}{5}+\dfrac{7}{10}-\dfrac{3}{2}=1-1-\dfrac{3}{2}=-\dfrac{3}{2}.\)
1. \(\dfrac{-7}{12}.\dfrac{11}{8}-\dfrac{37}{8}.\dfrac{7}{12}+\dfrac{1}{2}=\dfrac{-7}{12}\left(\dfrac{11}{8}+\dfrac{37}{8}\right)+\dfrac{1}{2}=\dfrac{-7}{12}.\dfrac{6}{1}+\dfrac{1}{2}=\dfrac{-7}{2}+\dfrac{1}{2}=\dfrac{-6}{2}=-3\)2.
\(\left(\dfrac{2}{3}-\dfrac{1}{4}-\dfrac{5}{6}\right).\left(-2\right)^2+\dfrac{3}{2}:\dfrac{-15}{4}=\dfrac{-5}{12}.4+\dfrac{-2}{5}=\dfrac{-5}{3}+\dfrac{-2}{5}=\dfrac{-31}{15}\)
3.
\(\dfrac{-2}{5}+\dfrac{3}{10}-\dfrac{3}{5}+\dfrac{7}{10}-\dfrac{3}{2}=\dfrac{-4}{10}+\dfrac{3}{10}-\dfrac{6}{10}+\dfrac{7}{10}-\dfrac{15}{10}=\dfrac{-15}{10}=\dfrac{-3}{2}\)
Thực hiện phép tính:
1, -7/12. 11/8- 37/8. 7/12+ 1/2
2, ( 2/3- 1/4- 5/6 ). ( -2) mũ 2 + 3/2: -15/4
3, -2/5+ 3/10- 3/5+ 7/10- 3/2
\(\dfrac{-7}{12}.\dfrac{11}{8}-\dfrac{37}{8}.\dfrac{7}{12}+\dfrac{1}{2}=\dfrac{-7}{12}.\left(\dfrac{11}{8}+\dfrac{37}{8}\right)+\dfrac{1}{2}=-\dfrac{7}{12}.6+\dfrac{1}{2}=-\dfrac{7}{2}+\dfrac{1}{2}=-3.\)
\(\left(\dfrac{2}{3}-\dfrac{1}{4}-\dfrac{5}{6}\right).\left(-2\right)^2+\dfrac{3}{2}:\dfrac{-15}{4}=\dfrac{8-3-10}{12}.4+\dfrac{-2}{5}=\dfrac{-5}{12}.4-\dfrac{2}{5}=\dfrac{-5}{3}-\dfrac{2}{5}=-\dfrac{31}{15}.\)
\(\dfrac{-2}{5}+\dfrac{3}{10}-\dfrac{3}{5}+\dfrac{7}{10}-\dfrac{3}{2}=\left(\dfrac{3}{10}+\dfrac{7}{10}\right)+\left(\dfrac{-2}{5}-\dfrac{3}{5}\right)-\dfrac{3}{2}=1-1-\dfrac{3}{2}=\dfrac{-3}{2}.\)
Thực hiện phép tính:
1, -7/12. 11/8- 37/8. 7/12+ 1/2
2, ( 2/3- 1/4- 5/6 ). ( -2) mũ 2 + 3/2: -15/4
3, -2/5+ 3/10- 3/5+ 7/10- 3/2
1: \(=\dfrac{7}{12}\left(-\dfrac{11}{8}+\dfrac{37}{8}\right)+\dfrac{1}{2}=\dfrac{7}{12}\cdot\dfrac{26}{8}+\dfrac{1}{2}=\dfrac{115}{48}\)
2: \(=\dfrac{8-3-10}{12}\cdot4+\dfrac{3}{2}\cdot\dfrac{-4}{15}\)
\(=\dfrac{-5}{3}+\dfrac{-12}{30}=\dfrac{-5}{3}+\dfrac{-2}{5}=\dfrac{-25-6}{15}=-\dfrac{31}{15}\)
3: \(=\dfrac{-2}{5}-\dfrac{3}{5}+\dfrac{3}{10}+\dfrac{7}{10}-\dfrac{3}{2}=-\dfrac{3}{2}\)
Thực hiện phép tính
a, ( -2)3 . 3 + ( -4) . ( -5) - 11 .0 -17
b, ( 135 - 35) . ( -37) + 37 . ( -42 -58)
c, -4/9 + 8/15 + -2/11 + 5/-9 + 7/15
a/ -21
b/ -7400
c/-2/11
KB vs tích hộ mk nhá
Bài 2; thực hiện các phép tính
a) 2 mũ 4 nhân 38 - 2 mũ 4 nhân 37
b) 4 mũ 2 nhân 444446 - 4 mũ 3 nhân 111111
c) (2 mũ 9 nhân 3 + 2 mũ 9 nhân 5) : 2 mũ 12
d) 13 mũ 2 - (5 mũ 2 nhân 4 + 2 mũ 2 nhân 15)
a) 2^4 * 38 - 2^4 * 37 = 16 * 38 - 16 * 37 = 608 - 592 = 16
b) 4^2 * 444446 - 4^3 * 111111 = 16 * 444446 - 64 * 111111 = 7107136 - 7106944 = 192
c) (2^9 * 3 + 2^9 * 5) / 2^12 = (512 * 3 + 512 * 5) / 4096 = (1536 + 2560) / 4096 = 4096 / 4096 = 1
d) 13^2 - (5^2 * 4 + 2^2 * 15) = 169 - (25 * 4 + 4 * 15) = 169 - (100 + 60) = 169 - 160 = 9
đề cô em ra sao thì em viết v thôi
a) \(...=2^4.\left(38-37\right)=2^4.1=16\)
b) \(...=4^2.\left(444446-4.111111\right)=16.\left(444446-444444\right)=16.2=32\)
c) \(...=2^9\left(3+5\right):2^{12}=2^9.8:2^{12}=2^9.2^3:2^{12}=2^{9+3-12}=2^0=1\)
d) \(...=13^2-\left(5^2.2^2+2^2.5.3\right)=13^2-2^2.5\left(5+3\right)=169-4.5.8=169-160=9\)