giúp mình câu 5 vs ak
X-1/2 = y/3 = z-3/5 và x-2+3z=40
Giúp mình vs ak🥺
giải phương trình:
(x-1)*(x+3)+2*(x-1)*căn((x+3)/(x-1))=8
giúp mình câu này vs ak. mình đang cần gấp
ĐẶT x-1=a , x+3=b (a,b cùng dấu)
\(PT\Leftrightarrow ab+2a\sqrt{\frac{b}{a}}=8\)
\(\Leftrightarrow2a\sqrt{\frac{b}{a}}=8-ab\)
\(\Leftrightarrow4a^2\frac{b}{a}=64-16ab+a^2b^2\)
\(\Leftrightarrow a^2b^2-20ab+64=0\)
\(\Leftrightarrow\left(ab-10\right)^2-36=0\)
\(\Leftrightarrow\left(ab-4\right)\left(ab-16\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}ab=4\\ab=16\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x-1\right)\left(x+3\right)=4\\\left(x-1\right)\left(x+3\right)=16\end{cases}}\)
Đến đây đơn giản rồi bn tự giải nhé
ĐK:....\(\frac{x+3}{x-1}\ge0\)
<=> \(\left(x-1\right)\left(x+3\right)+2\sqrt{\left(x-1\right)\left(x+3\right)}+1=9\)
<=> \(\left(\sqrt{\left(x-1\right)\left(x+3\right)}+1\right)^2=9\)
\(\Leftrightarrow\orbr{\begin{cases}\sqrt{\left(x-1\right)\left(x+3\right)}=2\\\sqrt{\left(x-1\right)\left(x+3\right)}=-4\left(loai\right)\end{cases}}\)
\(\Leftrightarrow\left(x-1\right)\left(x+3\right)=4\)
Em tự làm tiếp nhé
5x+1+5x+2=750
Giải giúp mình vs ak
\(5^{x+1}+5^{x+2}=750\)
\(\Leftrightarrow5^x.5^1+5^x.5^2=750\)
\(\Leftrightarrow5^x.5+5^x.25=750\)
\(\Leftrightarrow5^x.\left(5+25\right)=750\)
\(\Leftrightarrow5^x.30=750\)
\(\Leftrightarrow5^x=750:30\)
\(\Leftrightarrow5^x=25\)
\(\Leftrightarrow5^x=5^2\)
\(\Rightarrow x=2\)
5x + 1 + 5x + 2 = 750
=> 5x . 5 + 5x . 52 = 750
=> 5x . (5 + 52) = 750
=> 5x . (5 + 25) = 750
=> 5x . 30 = 750
=> 5x = 750 : 30
=> 5x = 25
=> 5x = 52
=> x = 2
Vậy x = 2
\(5^{x+1}+5^{x+2}=750.\)
\(5^x.5+5^x.5^2=750\)
\(5^x.\left(5+5^2\right)=750\)
\(5^x.\left(5+25\right)=750\)
\(5^x.30=750\)
\(5^x=750:30\)
\(5^x=25\)
\(\Rightarrow x=2\)
Giúp mình vs ak mình mơn nhìuuuuu
Mình cần gấp giúp mình vs ak
a, \(V_{CO}=\left(\dfrac{2,8}{28}\right).22,4=2,24l\\ V_{NO}=0,1.22,4=2,24l\\ V_{hh}=2,24+2,24=4,48l\)
b, \(V_{hh}=1,12+8,96=10,08l\)
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é tui thấy tờ giấy hình như you vẽ truyện đằng sau >:D
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