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ngô ngọc khánh linh
Đinh Minh Đức
18 tháng 3 2022 lúc 23:29

ảnh lỗi

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trần thảo my
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_thewindbear
14 tháng 3 2022 lúc 6:59

1.A
2.A
3.B
4.C
5.B
6.C
7.A
8.A
9.B
10.A
11.B
12.A
13.C
14.B
15.B
16.A
17.A
18.A
19.A
20.C

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Mina Anh
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Nguyễn Lê Phước Thịnh
23 tháng 12 2021 lúc 10:07

e: \(E=\dfrac{x^2-9-x^2+4-x^2+9}{\left(x+3\right)\left(x-2\right)}\)

\(=\dfrac{x+2}{x+3}\)

a: \(A=\dfrac{4x^2+x^2-2x+1+x^2+2x+1}{\left(x-1\right)\left(x+1\right)}\)

\(=\dfrac{6x^2+2}{\left(x-1\right)\left(x+1\right)}\)

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Nguyễn Hoàng Minh
23 tháng 12 2021 lúc 11:54

\(A=\dfrac{-4x^2+x^2-2x+1-x^2-2x-1}{\left(1-x\right)\left(1+x\right)}=\dfrac{-4x\left(x+1\right)}{\left(1-x\right)\left(1+x\right)}=\dfrac{4x}{x-1}\\ C=\dfrac{-x^2-4x-4+x^2-4x+4-4x^2}{\left(x-2\right)\left(x+2\right)}=\dfrac{-4x\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{4x}{2-x}\\ E=\dfrac{x^2-9-x^2+4x-4-x^2+9}{\left(x-2\right)\left(x+3\right)}=\dfrac{-\left(x-2\right)^2}{\left(x-2\right)\left(x+3\right)}=\dfrac{2-x}{x+3}\)

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Ngọc Nhi
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Đỗ Thanh Hải
5 tháng 7 2021 lúc 12:07

1 are

2 am

3 is

4 are

5 are

6 are

7 is

8 is

9 is

10 are

IV

1 is writing

2 are losing

3 is having

4 is staying

5 am not lying

6 is always using

7 are having

8 Are you playing

9 are not touching

10 Is - listening

11 Is- winning

12 am not staying

13 is not working

14 is not reading

15 isn't raining

16 am not listening

17 Are they making

18 Are you doing

19 Is - sitting

20 is - doing

21 are-putting

22 are-wearing

23 is-studying

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Phạm Vĩnh Linh
5 tháng 7 2021 lúc 12:14

2, am

3, is

4,are

5,are

6,are

7,is

8,is

9,is

10,are

IV

1,2,7 OK

3,is having

4,has stayed

5,am not lying

6,always uses

8,Are-playing

9,not to touch

10,Is-listening

11,Are-winning

12,am not staying

13,isn't working

14,isn't reading

15,isn't raining

16,am not listening

17,Are-making

18,Are-doing

19,Is-sitting

20,is-doing

21,do-putting

22,do-wear

23,is-studying

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Phan Thị Linh Chi
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Nguyễn Lê Phước Thịnh
29 tháng 12 2021 lúc 19:53

5: \(=\dfrac{1}{2}\cdot10-\dfrac{1}{2}=\dfrac{1}{2}\cdot9=\dfrac{9}{2}\)

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Linh Trương
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Đỗ Thanh Hải
4 tháng 6 2021 lúc 10:57

Bài 1 mình chỉ viết cái cần điền thôi nha

1 such a beautiful girl

2 so hot that

3 surprised that

4 a heavy box

5 so naughty 

6 such an important language

7 so young 

8 such poor people

9 so well

10 so much

12 so many

Bài 2

1 such 

2 so

3 so

4 such

5 such

6 so

7 such

8 so

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Đỗ Thanh Hải
4 tháng 6 2021 lúc 11:03

3

1 This detective story is so good that I can't put it down

It is such a good detective story that I can't put it down

2 The waiters were so rude that we complained to the manager about them

They are such rude waiters that we complained to the manager about them

3 The lifts were so old that they didn't work

They were such old lifts that they didn't work

4 The food was so awful that we were ill for 3 days

It was such awful food that we were ill for 3 days

Bài 4

1 enough

2 too

3 too

4 enough

5 enough

6 too

7 enough

8 enough

 

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Đỗ Thanh Hải
4 tháng 6 2021 lúc 11:07

Bài 5

1 The film was so sad that everyone cried

2 He speaks too fast for me to unterstand

3 Have we got enough money to pay for the tickets

4 It was such a good meal that we ate far too much

5 The teacher was stupid enough to believed the children

6 They were such cheap trousers that I bought six pairs

7 Is there enough food for us to feed everyone?

8 The film was so bad that most people walked out

9 He is too old to walk far

10 My boss was kind enough to pay for the meal

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Foxy láu cá
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RuiSayBye
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Ru Yêw Dấu
24 tháng 4 2022 lúc 21:35

a. f(\(\dfrac{-1}{2}\)) = \(4.\left(\dfrac{-1}{2}\right)^2+3.\left(\dfrac{-1}{2}\right)-2\) 

               = \(4.\dfrac{1}{4}-\left(\dfrac{-3}{2}\right)-\dfrac{4}{2}\)

               = \(\dfrac{2}{2}+\dfrac{3}{2}-\dfrac{4}{2}\)

               = \(\dfrac{1}{2}\)

 

     

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nguyễn bảo hoàng
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Nguyễn Cẩm Uyên
14 tháng 10 2021 lúc 20:20

bạn tự vẽ hình giúp mik nha

a.ta có \(\Delta\)ABC nội tiếp (O) và AB là đường kính nên \(\Delta\)ABC vuông tại C

trong \(\Delta ABC\) vuông tại C có

AC=AB.cosBAC=10.cos30=8,7

BC=AB.sinCAB=10.sin30=5

ta có Bx là tiếp tuyến của (O) nên Bx vuông góc với AB tại B

trong \(\Delta\)ABE vuông tại B có

\(cosBAE=\dfrac{AB}{AE}\Rightarrow AE=\dfrac{AB}{cosBAE}=\dfrac{10}{cos30}=11,5\)

mà:CE=AE-AC=11,5-8,7=2,8

b.áp dụng pytago vào \(\Delta ABE\) vuông tại B có

\(BE=\sqrt{AE^2-AB^2}=\sqrt{11,5^2-10^2}=5,7\)

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