`9/2xx7/3-4/3xx9/2`

`=9/2xx(7/3-4/3)`

`=9/2xx3/3`

`=9/2xx1`

`=9/2`

a) 9 x 2 + 4 = 18 + 47 = 65

b) 9 x 4 x 2 = 36 x 2 = 72

c) 9 x 9 – 18 = 81 – 18 = 63

d) 9 x 6 : 3 = 54 : 3 = 18

9 x 1 = 9        9 x 3 = 27       9 x 5 = 45       9 x 7 = 63       9 x 9 = 81

9 x 2 = 18       9 x 4 = 36       9 x 6 = 54       9 x 8 = 72       9 x 10 = 90

9 x 1 = 9

9 x 5 = 45

9 x 4 = 32

9 x 10 = 90

9 x 2 = 18

9 x 7 = 63

9 x 8 = 72

9 x 0 = 0

9 x 3 = 27

9 x 9 = 81

9 x 6 = 54

0 x 9 = 0

= 9                            = 45                                      = 36

dễ mà bạn gì ơi

9 x 4 = 36

9 x 2 = 18

9 x 5 = 40

9 x 10 = 90

9 x 1 = 9

9 x 7 = 63

9 x 8 = 72

0 x 9 = 0

9 x 3 = 27

9 x 6 = 54

9 x 9 = 81

9 x 0 = 0

a) 9 x 1=9                   9 x 4=36                   9 x 7=63

b) 9 x 2=18                 9 x 5=45                   9 x 8=72

c) 9 x 3=27                 9 x 6=54                   9 x 981

d) 9 x 10=90               9 x 0=0                     0 x 9=0

9 x 2 = 18              9 x 3 = 27                  9 x 4 = 36                      9 x 5 = 45

18 : 9 = 2               27 : 9 = 3                  36 : 9 = 4                        45 : 9 = 5

9 x 6 = 54              9 x 7 = 63                  9 x 8 = 72                       9 x 9 = 81

54 : 9 = 6               63 : 9 = 7                   72 : 9 = 8                       81 : 9 = 9

a: \(\dfrac{5x+y^2}{x^2y}-\dfrac{5y-x^2}{xy^2}\)

\(=\dfrac{5xy+y^3-x\left(5y-x^2\right)}{x^2y^2}\)

\(=\dfrac{5xy+y^3-5xy+x^3}{x^2y^2}=\dfrac{x^3+y^3}{x^2y^2}\)

b: \(\dfrac{x+9}{\left(x-3\right)\left(x+3\right)}-\dfrac{3}{x\left(x+3\right)}\)

\(=\dfrac{x^2+9x-3x+9}{x\left(x-3\right)\left(x+3\right)}=\dfrac{\left(x+3\right)^2}{x\left(x-3\right)\left(x+3\right)}=\dfrac{x+3}{x^2-3x}\)

`!`

\(a,\dfrac{8}{9}\times\dfrac{7}{5}-\dfrac{7}{9}\times\dfrac{2}{5}+\dfrac{2}{9}\\ =\dfrac{8}{9}\times\left(\dfrac{7}{5}-\dfrac{2}{5}\right)+\dfrac{2}{9}\\ =\dfrac{8}{9}\times\dfrac{5}{5}+\dfrac{2}{9}\\ =\dfrac{8}{9}+\dfrac{2}{9}\\ =\dfrac{10}{9}\)

\(b,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}\\ =\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}\\ =\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\\ =\dfrac{1}{4}\times\dfrac{9}{9}\\ =\dfrac{1}{4}\)