ngày mai mik làm đc ko

ok ai giải được giúp mik nha chiều mai mik phải nộp rồi

Ta có: \(-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{2}{3}+\frac{1}{5}\right|\)

hay \(-\frac{22}{15}x=\frac{7}{15}-\frac{1}{3}=\frac{2}{15}\)

\(\Leftrightarrow x=\frac{2}{15}:\frac{-22}{15}=\frac{2}{15}\cdot\frac{15}{-22}=\frac{-2}{22}=\frac{-1}{11}\)

Vậy: \(x=\frac{-1}{11}\)

\(-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{2}{3}+\frac{1}{5}\right|\)

\(\Rightarrow-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{7}{15}\right|\)

\(\Rightarrow-\frac{22}{15}x+\frac{1}{3}=\frac{7}{15}\)

\(\Rightarrow-\frac{22}{15}x=\frac{7}{15}-\frac{1}{3}\)

\(\Rightarrow-\frac{22}{15}x=\frac{2}{15}\)

\(\Rightarrow x=\frac{2}{15}:\left(-\frac{22}{15}\right)\)

\(\Rightarrow x=-\frac{1}{11}\)

Vậy \(x=-\frac{1}{11}.\)

Chúc bạn học tốt!

\(e,\frac{22}{15}-x=-\frac{8}{27}\)

=> \(x=\frac{22}{15}-\left[-\frac{8}{27}\right]\)

=> \(x=\frac{22}{15}+\frac{8}{27}\)

=> \(x=\frac{198}{135}+\frac{40}{135}=\frac{198+40}{135}=\frac{238}{135}\)

\(g,\left[\frac{2x}{5}-1\right]:\left[-5\right]=\frac{1}{4}\)

=> \(\left[\frac{2x}{5}-\frac{1}{1}\right]=\frac{1}{4}\cdot\left[-5\right]\)

=> \(\left[\frac{2x}{5}-\frac{5}{5}\right]=-\frac{5}{4}\)

=> \(\frac{2x-5}{5}=-\frac{5}{4}\)

=> \(2x-5=-\frac{5}{4}\cdot5=-\frac{25}{4}\)

=> \(2x=-\frac{5}{4}\)

=> \(x=-\frac{5}{8}\)

\(h,-2\frac{1}{4}x+9\frac{1}{4}=20\)

=> \(-\frac{9}{4}x+\frac{37}{4}=20\)

=> \(-\frac{9}{4}x=20-\frac{37}{4}=\frac{43}{4}\)

=> \(x=\frac{43}{4}:\left[-\frac{9}{4}\right]=\frac{43}{4}\cdot\left[-\frac{4}{9}\right]=\frac{43}{1}\cdot\left[-\frac{1}{9}\right]=-\frac{43}{9}\)

\(i,-4\frac{3}{5}\cdot2\frac{4}{23}\le x\le-2\frac{3}{5}:1\frac{6}{15}\)

=> \(-\frac{23}{5}\cdot\frac{50}{23}\le x\le-\frac{13}{5}:\frac{21}{15}\)

=> \(-\frac{1}{1}\cdot\frac{10}{1}\le x\le-\frac{13}{5}\cdot\frac{15}{21}\)

=> \(-10\le x\le-\frac{13}{1}\cdot\frac{3}{21}\)

=> \(-10\le x\le-\frac{13}{1}\cdot\frac{1}{7}\)

=> \(-10\le x\le-\frac{13}{7}\)

Đến đây tìm x

\(\left(\frac{-2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)

\(=\left(\frac{-2}{3}+\frac{3}{7}+\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)

\(=\left[\left(\frac{-2}{3}+\frac{-1}{3}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)\right]:\frac{4}{5}\)

\(=\left[\left(-1+1\right)\right]:\frac{4}{5}\)

\(=0:\frac{4}{5}=0\)

~ Hok tốt ~

cau A= o nha ban con cau B minh ko chac vi so minh ra hoi lon 1 ti

a,\(\left(-\frac{2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(-\frac{1}{3}+\frac{4}{7}\right):\frac{4}{5}\)

=\(\left[\left(-\frac{2}{3}+\frac{3}{7}\right)+\left(-\frac{1}{3}+\frac{4}{7.}\right)\right]:\frac{4}{5}\)

=\(\left[-\frac{5}{21}+\frac{5}{21}\right]:\frac{4}{5}\)

=\(0:\frac{4}{5}=0\)

b,\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)

=\(\frac{5}{9}:\left[\left(\frac{1}{11}-\frac{5}{22}\right)+\left(\frac{1}{15}-\frac{2}{3}\right)\right]\)

=\(\frac{5}{9}:\left[-\frac{3}{22}-\frac{3}{5}\right]\)

=\(\frac{5}{9}:\left[-\frac{81}{110}\right]\)

=\(-\frac{550}{729}\)

#hok tốt#

\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)

\(=\frac{5}{9}:\frac{-3}{22}+\frac{5}{9}:\frac{-3}{5}\)

\(=\frac{5}{9}\cdot\frac{-22}{3}+\frac{5}{9}\cdot\frac{-5}{3}\)

\(=\frac{5}{9}\cdot\left(\frac{-22}{3}+\frac{-5}{3}\right)\)
\(=\frac{5}{9}\cdot\left(-9\right)\)

\(=-5\)

Đúng rồi em ạ :)

đúng đó nhưng bạn nên nhóm \(\frac{-22}{3}\)và \(\frac{-5}{3}\)vào với nhau và đặt \(\frac{5}{9}\)ra ngoài sẽ tính nhanh hơn

Đúng r đấy e