= 0,8

= 1.42857142857

Máy tính cả thôi, hi hi

h cho minh nha 

a= -7/156

b=1/12

c=-7/55

d=17/21

e=10/7

cho minh nhé

\(\frac{-1}{39}+\frac{-1}{52}=\frac{-7}{156}\)

\(\frac{-6}{9}+\frac{12}{16}=\frac{-2}{3}+\frac{3}{4}=\frac{1}{12}\)

\(\frac{-2}{5}-\frac{-3}{11}-\frac{34}{37}-\frac{74}{-85}=\frac{-1215}{6919}\)

\(\frac{-5}{9}:\frac{-7}{18}=\frac{-5}{9}.\frac{-18}{7}=\frac{10}{7}\)

bấm mt

-1/39 + -1/52 = -7/156

-6/9 + -12/16 = -17/12

-2/5 - - 3/11 [ (-) + ( -) = +] = -2/5 + 3/11 = -7/55

-34/37 - 74/ -85 = -152/3145

-5/9 : -7/18 = 10/7

 -7/156

-17/12

-7/55

-152/3145

10/7

Quy đồng rồi tính là ra ngay mà

\(2575+37-2576-29\)

\(=2612-2576-29\)

\(=36-29=7\)'

\(35+35+36+37-14-15-16-17\)

\(=70+\left(36-16\right)+\left(37-17\right)-14-15\)

\(=70+20+20-14-15\)

\(=90+6-15\)

\(=96-15=81\)

\(13\cdot\left(-12\right)+87.\left(-12\right)\)

\(=\left(-12\right)\cdot\left(13+87\right)\)

\(=\left(-12\right)\cdot100=-1200\)

\(26\cdot17+17\cdot74\)

\(=\left(26+74\right)\cdot17\)

\(=100\cdot17=1700\)

\(25\cdot\left(-18\right)+25\left(-82\right)\)

\(=25\cdot\left[\left(-18\right)+\left(-82\right)\right]\)

\(=25\cdot\left(-100\right)=\left(-2500\right)\)

\(25+37-48-25-37\)

\(=\left(25-25\right)+\left(37-37\right)-48\)

\(=0+0-48\)

\(=0-48=\left(-48\right)\)

\(\left(-16\right)+24+16-34\)

\(=\left[\left(-16\right)+16\right]+\left(24-34\right)\)

\(=0+\left(-10\right)=\left(-10\right)\)

a) \(\dfrac{-1}{39}+\dfrac{-1}{52}=\dfrac{-4}{156}+\dfrac{-3}{156}=\dfrac{-7}{156}\)

b) \(\dfrac{-6}{9}+\dfrac{-12}{16}=\dfrac{-2}{3}+\dfrac{-3}{4}=\dfrac{-8}{12}+\dfrac{-9}{12}=\dfrac{-17}{12}\)

c) \(\dfrac{-2}{5}-\dfrac{-3}{11}=\dfrac{-22}{55}-\dfrac{-15}{55}=\dfrac{-7}{55}\)

d) \(\dfrac{-34}{37}.\dfrac{74}{-85}=\dfrac{4}{5}\)

e) \(\dfrac{-5}{9}:\dfrac{-7}{18}=\dfrac{-5}{9}.\dfrac{18}{-7}=\dfrac{10}{7}\)

Bài 3 là hỗn số hả em?

Bài 1: 

a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)

\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)

\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)

hay \(x=-\dfrac{1}{3}\)

Vậy: \(x=-\dfrac{1}{3}\)

b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)

\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)

hay \(x=\dfrac{50}{9}\)

Vậy: \(x=\dfrac{50}{9}\)

c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)

\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)

\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)

hay \(x=\dfrac{22}{15}\)

Vậy: \(x=\dfrac{22}{15}\)

d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)

\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)

\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)

hay \(x=\dfrac{15}{19}\)

Vậy:\(x=\dfrac{15}{19}\)

\(27.332+93.43+57.61+69.57\\ =27.332+93.43+57.\left(61+69\right)\\ =27.332+93.43+57.130\\ =8964+3999+7410=20373\\ 34.75+75.66-65.100\\ =\left(34+66\right).75-65.100\\ =100.75-65.100\\ =100.\left(75-65\right)\\ =100.10=1000\\ \left(456.11+912\right).37:13:74\\ =5928:13:\left(74:37\right)\\ =456:2=228\\ 6^2:4.3+2.5^2\\ =36:4.3+2.25\\ =9.3+50=27+50=77\\ 5.4^2-18:3^2\\ =5.16-18:9\\ =80-2=78\\\left[\left(315+372\right).3+\left(372+315\right).7\right]:\left(26.13+74.14\right)\\ =687.\left(3+7\right):\left(338+1036\right)\\ 687.10:1374\\ =6870:1374=5\\ 12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\\ =12:\left[390:\left(500-370\right)\right]\\ =12:\left(390:130\right)=12:3=4\\ 192000-\left(1500.2+1800.3+1800.2:3\right)\\ =192000-\left(3000+5400+1200\right)\\ =192000-9600=182400\)