tim x biet
a)2^x+2 -2^x=96
b)x-(50x/100+25x/200)=111/4
c) (x-5).30/100=200x/100+5
Tìm x:
a) \(x-\left(\frac{50x}{160}+\frac{25x}{200}\right)=11\frac{1}{4}\)
b)\(\left(x-5\right)\cdot\frac{30}{100}=\frac{200x}{100}+5\)
Giúp mình nhanh với, cảm ơn các bạn rất nhiều!
Tìm x:
a) x - (\(\frac{50x}{100}+\frac{25x}{200}\)) = \(11\frac{1}{4}\)
b) (x - 5) . \(\frac{30}{100}\) = \(\frac{200x}{100}\) + 5
Tìm x:
a) x - (\(\frac{50x}{100}\) + \(\frac{25x}{100}\)) = \(11\frac{1}{4}\)
b) (x-5) . \(\frac{30}{100}\) = \(\frac{200x}{100}\) + 5
- Help me!.
tìm x biết rằng :
a) x - \(\left(\frac{50x}{100}+\frac{25x}{200}\right)=11\frac{1}{4}\) c) ( x - 5 ) . \(\frac{30}{100}=\frac{20x}{100}+5\)
a) x-\(\left(\frac{50x}{100}+\frac{25x}{200}\right)\)=\(11\frac{1}{4}\)
<=>x - \(\frac{1}{2}x-\frac{1}{8}x\)=\(\frac{11.4+1}{4}\)
<=>\(\frac{3}{8}x=\frac{45}{4}\)
<=>x=\(\frac{45}{4}:\frac{3}{8}\)
<=>x=30
Vậy x=30
c) (x-5).\(\frac{30}{100}\)=\(\frac{20x}{100}+5\)
<=>(x-5).\(\frac{3}{10}\)=\(\frac{x}{5}\)+5
<=>\(\frac{3x}{10}-\frac{15}{10}=\frac{x}{5}+5\)
<=>\(\frac{3x}{10}-\frac{x}{5}=5+\frac{15}{10}\)
<=>\(\frac{x}{10}=\frac{13}{2}\)
<=>x=\(\frac{13.10}{2}\)
<=>x=65
Vậy: x=65
Tìm x, biết:
a, \(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=11\frac{1}{4}\) b,\(\left(x-5\right).\frac{30}{100}=\frac{200x}{100}+5\)
c,\(\frac{x+1}{2}=\frac{8}{x+1}\) d, \(x:\left(9\frac{1}{2}-\frac{3}{2}\right)=\frac{0,4+\frac{2}{9}-\frac{2}{11}}{1,6+\frac{8}{9}-\frac{8}{11}}\)
\(c,\frac{x+1}{2}=\frac{8}{x+1}\)
\(\Rightarrow(x+1)(x+1)=2.8\)
\(\Rightarrow(x+1)^2=16\)
\(\Rightarrow(x+1)^2=4^2\)
\(\Rightarrow x+1=4\)
\(\Rightarrow x=4-1\)
\(\Rightarrow x=3\)
\(a,x-(\frac{50x}{100}+\frac{25x}{200})=11\frac{1}{4}\)
\(\Rightarrow x-\frac{50x+25x}{100}=\frac{45}{4}\)
\(\Rightarrow\frac{100x}{100}-\frac{75x}{100}=\frac{45}{4}\)
\(\Rightarrow\frac{100x-75x}{100}=\frac{1125}{100}\)
\(\Rightarrow25x=1125\)
\(\Rightarrow x=45\)
\(b,(x-5)\frac{30}{100}=\frac{200x}{100}+5\)
\(\Rightarrow\frac{30x}{100}-\frac{3}{2}=\frac{200x}{100}+5\)
\(\Rightarrow\frac{30x}{100}-\frac{200x}{100}=5+\frac{3}{2}\)
\(\Rightarrow\frac{-170x}{100}=\frac{13}{2}\)
\(\Rightarrow\frac{-170x}{100}=\frac{650}{100}\)
\(\Rightarrow-170x=650\)
\(\Rightarrow x=\frac{-65}{17}\)
x-(50x/100+25x/200)=45/4
Cố đợi sang năm nhe
\(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=\frac{45}{4}\)
\(x-\left(\frac{1x}{2}+\frac{1x}{8}\right)=\frac{45}{4}\)
\(x-\left(\frac{4x}{8}+\frac{1x}{8}\right)=\frac{45}{4}\)
\(x-\frac{5x}{8}=\frac{45}{4}\)
\(\frac{8x}{8}-\frac{5x}{8}=\frac{45}{4}\)
\(\frac{3x}{8}=\frac{45}{4}\Leftrightarrow x=\frac{45}{4}:\frac{3}{8}=30\)
Vậy \(x=30\)
[x-5] x 30/100= 200x : 100+5
(x-5) x \(\frac{30}{100}\)= 200x : 100 + 5
(x-5) x \(\frac{3}{10}\)= 200x : 100 + 5
\(\frac{x.3-15}{10}\)= 2x + 5
\(\frac{x.3-15}{10}-2x=5\)
\(\frac{x.3-15}{10}-\frac{20x}{10}=5\)
\(\frac{3x-15-20x}{10}=5\)
3x - 20x - 15 = 50
-17x - 15 = 50
-17x = 65
x = 65 : -17
x = \(\frac{-65}{17}\)
tìm x
a) -3/x-1 b) -4/2x-1
c) 13/x-5 d) x-(50x/100+25x/200)=45/4
e) (x-5).30/100=200x/100+5 f) (3x-1)/(-1/2x+5)=0
a/-3/x-1
-3/x=1
x=-3
b/-4/2x-1
-2x=1
x=-1/2
c/13/x-5
13/x=5
x=13/5
d/x-(50x/100+25x/200)=45/4
x-(x/2+x/8)=45/4
x-5/8x=45/4
3/8x=45/4
x=30
e/(x-5).30/100=200x/100+5
(x-5).3/10=2x+5
3x/10-3/2=2x+5
2x-3x/10=-3/2-5
17x/10=-13/2
17x=-65
x=-65/17
f/(3x-1)/(-1/2x+5)=0
=>3x-1=0
3x=1
x=1/3
x - \(\text{}\text{}\left(\dfrac{50x}{100}+\dfrac{25x}{200}\right)\)= \(11\dfrac{1}{4}\)
\(x-\left(\dfrac{50x}{100}+\dfrac{25x}{100}\right)=11\dfrac{1}{4}\)
\(x-\dfrac{3x}{4}=\dfrac{45}{4}\)
\(\dfrac{x}{4}=\dfrac{45}{4}\Rightarrow x=45\)
Ta có: \(x-\left(\dfrac{50x}{100}+\dfrac{25x}{200}\right)=11\dfrac{1}{4}\)
\(\Leftrightarrow x-\dfrac{1}{2}x-\dfrac{1}{8}x=\dfrac{45}{4}\)
\(\Leftrightarrow x\cdot\dfrac{3}{8}=\dfrac{45}{4}\)
hay x=30