TÍNH
a,(\(\frac{7}{30}\)x\(\frac{12}{37}\)+\(\frac{12}{30}\)x\(\frac{23}{37}\))x\(\frac{13}{31}\)-\(\frac{-25}{37}\)x\(\frac{18}{31}\)
b,\(\frac{25^2-7x9}{10x15x21}\)
Những câu hỏi liên quan
\(\frac{7}{30}.\frac{12}{37}+\frac{12}{30}.\frac{23}{37}.\frac{13}{31}-\frac{-25}{37}.\frac{18}{31}\)
tính
a)\(\left(-\frac{31}{37}\right)^5.\left(\frac{37}{62}\right)\)
b)\(\left(x-\frac{3}{5}\right)^2+|\frac{-7}{23}|+\left(-\frac{4}{25}\right)\)
giúp mình nhé !!!
bài 1 tính bằng cách hợp lí nếu có thểfrac{-5}{12}-frac{-3}{24}b) 5frac{5}{13}-(1frac{1}{2}+3frac{5}{13})c)frac{-13}{37}.frac{5}{23}+frac{-13}{37}.frac{18}{23}+frac{50}{37}d)(0,5 -frac{3}{2}):1frac{1}{6}+75%bài 2 tìm x biết-7/5 +x -3/4-7/4 + 1/4 : x 3/2
Đọc tiếp
bài 1 tính bằng cách hợp lí nếu có thể
\(\frac{-5}{12}\)-\(\frac{-3}{24}\)=
b) 5\(\frac{5}{13}\)-(1\(\frac{1}{2}+3\frac{5}{13}\))
c)\(\frac{-13}{37}.\frac{5}{23}+\frac{-13}{37}.\frac{18}{23}+\frac{50}{37}\)
d)(0,5 -\(\frac{3}{2}\)):1\(\frac{1}{6}+75\%\)
bài 2 tìm x biết
-7/5 +x = -3/4
-7/4 + 1/4 : x = 3/2
bài 1:
a, (1-frac{3}{6}2)+/frac{-7}{23}/+(-frac{4}{25})
b, sqrt{25}-sqrt{100}+sqrt{36}
c,(frac{-31}{37})5.(frac{37}{62})5
bài 2:
a,(x-frac{3}{5})24
b,2x+2x+3144
xg trc tick cho
Đọc tiếp
bài 1:
a, (1-\(\frac{3}{6}\)2)+/\(\frac{-7}{23}\)/+(-\(\frac{4}{25}\))
b, \(\sqrt{25}\)-\(\sqrt{100}\)+\(\sqrt{36}\)
c,(\(\frac{-31}{37}\))5.(\(\frac{37}{62}\))5
bài 2:
a,(x-\(\frac{3}{5}\))2=4
b,2x+2x+3=144
xg trc tick cho
a)\(\left(1-\frac{3}{6}^2\right)+\left|\frac{-7}{23}\right|+\left(-\frac{4}{25}\right)\\ =\frac{3}{4}+\frac{7}{23}+\left(-\frac{4}{25}\right)\\ =\frac{2057}{2300}\)
b)\(\sqrt[]{25}-\sqrt[]{100}+\sqrt[]{36}\\ =5-10+6\\ =1\)
c)\(\left(\frac{-31}{37}\right)^5.\left(\frac{37}{62}\right)^5\\ =\left(\frac{-31}{37}.\frac{37}{62}\right)^5\\ =\left(\frac{-1}{2}\right)^2\\ =\frac{1}{4}\)
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Bài 1:1. Rút gọn:a) Afrac{9^3.25^3}{18^2.125^2}b) Bfrac{18}{37}+frac{8}{2017}+frac{19}{37}-1frac{2009}{2017}+frac{2017}{2018}2.CHO Mfrac{2}{5.14}+frac{2}{7.18}+frac{2}{9.22}+frac{2}{11.26}+frac{2}{13.30}.so sánh M &frac{3}{46}Bài 2: Tim x,biết:a) left(2x-1right)^2-25b)frac{148-x}{25}+frac{164-x}{23}+frac{186-x}{21}+frac{199-x}{19}10
Đọc tiếp
Bài 1:1. Rút gọn:
a) \(A=\frac{9^3.25^3}{18^2.125^2}\)
b) \(B=\frac{18}{37}+\frac{8}{2017}+\frac{19}{37}-1\frac{2009}{2017}+\frac{2017}{2018}\)
2.CHO \(M=\frac{2}{5.14}+\frac{2}{7.18}+\frac{2}{9.22}+\frac{2}{11.26}+\frac{2}{13.30}\).so sánh M &\(\frac{3}{46}\)
Bài 2: Tim \(x\),biết:
a) \(\left(2x-1\right)^2-25\)
b)\(\frac{148-x}{25}+\frac{164-x}{23}+\frac{186-x}{21}+\frac{199-x}{19}=10\)
bài 1.a)\(A=\frac{9^3.25^3}{18^2.125^2}=\frac{3^6.5^6}{2^2.3^4.5^6}=\frac{9}{4}\)
b) \(B=\frac{18}{37}+\frac{19}{37}+\frac{8}{2017}-\frac{4026}{2017}+\frac{2017}{2018}\)
\(=1-\frac{4014}{2017}+\frac{2017}{2018}=\frac{1997}{2017}+\frac{2017}{2018}\)
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So sánh các số hữu tỉ sau :
a)\(\frac{-17}{23}va\frac{-25}{31}\)
b)\(\frac{-18}{91}va\frac{-23}{114}\)
c)\(\frac{-33}{37}va\frac{-34}{35}\)
\(\frac{49}{48}x\frac{64}{63}x\frac{81}{80}x\frac{100}{99}x\frac{121}{120}\)
\(\frac{7}{6}+\frac{13}{12}+\frac{21}{20}+\frac{31}{30}+\frac{43}{42}+\frac{57}{56}\)
a)
\(=\frac{7\cdot7\cdot8\cdot8\cdot9\cdot9\cdot10\cdot10\cdot11\cdot11}{6\cdot8\cdot7\cdot9\cdot8\cdot10\cdot9\cdot11\cdot10\cdot12}\)
\(=\frac{7\cdot11}{6\cdot12}\)
\(=\frac{77}{72}\)
b)
\(=1+\frac{1}{6}+1+\frac{1}{12}+1+\frac{1}{20}+1+\frac{1}{30}+1+\frac{1}{42}+1+\frac{1}{56}\)
\(=6+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}\)
\(=6+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{7}-\frac{1}{8}\)
\(=6+\frac{1}{2}-\frac{1}{8}\)
\(=6+\frac{3}{8}\)
\(=\frac{51}{8}\)
Chia thành...a và b nhé.
Bg
a)Ta có: \(\frac{49}{48}.\frac{64}{63}.\frac{81}{80}.\frac{100}{99}.\frac{121}{120}\)
= \(\frac{49.64.81.100.121}{48.63.80.99.120}\)
= \(\frac{7.7.8.8.9.9.10.10.11.11}{6.8.7.9.8.10.9.11.10.12}\)
= \(\frac{7.11}{6.12}\) (chịt tiêu trên dưới)
= \(\frac{77}{72}\)
b) Ta có: \(\frac{7}{6}+\frac{13}{12}+\frac{21}{20}+\frac{31}{30}+\frac{43}{42}+\frac{57}{56}\)
Có 6 số hạng (đếm)
= \(1+\frac{1}{6}+1+\frac{1}{12}+1+\frac{1}{20}+1+\frac{1}{30}+1+\frac{1}{42}+1+\frac{1}{56}\)
= \(1+1+...+1+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\)
= \(1.6+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)
= \(6+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
= \(6+\frac{1}{2}-\frac{1}{8}\)
= \(\frac{13}{2}-\frac{1}{8}\)
= \(\frac{51}{8}\)
Hơi dài....
Bài 1:
\(a,\frac{-5}{14}-\frac{37}{14}\le x
Tìm x biết :
a) \(\frac{1}{2013}\times x+1+\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{2012\times2013}=2\)
b)\(2x+\frac{7}{6}+\frac{13}{12}+\frac{21}{20}+\frac{31}{30}+\frac{43}{42}+\frac{57}{56}+\frac{73}{72}+\frac{91}{90}=10\)