3972036,001 hoặc 3976023,985

-)1998*1990+3978=3976020+3978= 3979998

-)1992*1991-3984=3966072-3984=3962088

tich ủng hộ mình nha

AI NHANH MÌNH K CHO

=1.004520344

Thấy đúng k cho tui

1 nha bạn

giup mik voi

bn án vào đúng 0 sẽ ra kết quả mình giải rồi

3962094

           3962088 nhé bạn

1998*1991+3978

=3978018 + 3978

=3981996

Bài 2 :

 1992*1991-3984

 = 3966072-3978

=3962094

$\left(1989.1990+3978\right):\left(1992.1991-3984\right)$

$=\left[1989.\left(1990+2\right)\right]:\left[1992\left(1991-2\right)\right]=\left(1989.1992\right):\left(1992.1989\right)=1$

\(\left(1989.1990+3978\right):\left(1992.1991-3984\right)\)

\(=\left[1989.\left(1990+2\right)\right]:\left[1992\left(1991-2\right)\right]=\left(1989.1992\right):\left(1992.1989\right)=1\)

1989 . 1990 + 3978 1992 . 1991 − 3984  ⇒  1989 . 1990 + 1989 . 2 1992 . 1991 − 1992 . 2  ⇒  1989 . ( 1990 + 2 ) 1992 . ( 1991 + 2 )    ⇒  1989 . 1992 1992 . 1989  ⇒  1

dấu chấm là dấu nhân

\(=\dfrac{1989\left(1990+2\right)}{1992\left(1991-2\right)}=\dfrac{1989}{1989}\cdot\dfrac{1992}{1992}=1\)

\(\dfrac{1989\times1990+3978}{1992\times1991-3984}\)

\(=\dfrac{1989\times1990+1989\times2}{1992\times1991-1992\times2}\)

\(=\dfrac{1989\times\left(1990+2\right)}{1992\times\left(1991+2\right)}\)

\(=\dfrac{1989\times1992}{1992\times1989}\)

\(=1\)

\(\left(1989\times1990+3978\right):\left(1992\times1991-3984\right)\\ =\left(1989\times1990+1989\times2\right):\left(1992\times1991-1992\times2\right)\\ =\left(1989\times1992\right):\left(1992\times1989\right)\\ =1\)