VI . Rewrite the following sentences without changing their original meanings.
1 . I am not happy when children lie to their parents
-> Children ____________shouldn't lie to their parents___________________________
2 . It's good if you say " Thank you " to a person who has helped you
-> You __________should say " Thank you " to a person who has helped you _______________________________
3 . Why don't you go out with your friends?
-> You _________should go out with your friends_______________________________
4 . Shhh ! Don't talk too loud. My sister is sleeping
-> We ___________should not talk loud because my sister is sleeping_________________________
Tổng vận tốc của `2` bạn đó :
`15 + 12 = 27` (km/giờ)
Thời gian Tú và Khôi gặp nhau:
`54:27= 2(giờ)`
Vậy...
Số `x` cần tìm :
`(12 + 4)/2 = 8`
Số `y` cần tìm :
`12-8=4`
Ta cóL
`(x + y) + (x - y) = 12 + 4`
`=> x + y + x - y = 12 + 4`
`=> 2x = 16`
`=> x = 16 : 2`
`=> x = 8`
`=> 8 + y = 12`
`=> y = 12 - 8`
`=> y = 4`
Tổng số phần bằng nhau: `3 + 1 = 4 (phần)`
Số a là: `20 : 4 xx 3 = 15`
Số b là: `20 - 15 = 5`
BASE FORM | PAST SIMPLE | PARTICIPLE |
go | went | gone |
see | saw | seen |
meet | met | met |
eat | ate | eaten |
drink | drank | drunk |
have | had | had |
buy | bought | bought |
do | did | done |
make | made | made |
swim | swam | swum |
cut | cut | cut |
1. saw, seen
2. met, met
3. ate, eaten
4. drank, drunk
5. had, had
6. bought, bought
7. did, done
8. made, made
9. (swin là j?)
10. cut, cut
\(n_{MgO}=\dfrac{1,6}{40}=0,04\left(mol\right)\)
\(n_{HCl}=0,2.4=0,8\left(mol\right)\)
PTHH: \(MgO+2HCl\rightarrow MgCl_2+H_2O\)
Xét tỉ lệ: \(\dfrac{0,04}{1}< \dfrac{0,8}{2}\) => MgO hết, HCl dư
PTHH: \(MgO+2HCl\rightarrow MgCl_2+H_2O\)
0,04--->0,08-----.0,04
\(\left\{{}\begin{matrix}C_{M\left(MgCl_2\right)}=\dfrac{0,04}{0,2}=0,2M\\C_{M\left(HCl.dư\right)}=\dfrac{0,8-0,08}{0,2}=3,6M\end{matrix}\right.\)
\(n_{MgO}=\dfrac{1,6}{40}=0,04\left(mol\right)\\
n_{HCl}=0,2.4=0,8\left(mol\right)\\
pthh:MgO+2HCl\rightarrow MgCl_2+H_2O\)
\(LTL:\dfrac{0,04}{1}< \dfrac{0,8}{2}\)
-> HCl dư
\(n_{HCl\left(p\text{ư}\right)}=2n_{MgO}=0,08\left(mol\right)\\
n_{MgCl_2}=n_{MgO}=0,04\left(mol\right)\\
C_{M\left(HCl\left(d\right)\right)}=\dfrac{0,8-0,04}{0,2}=3,8M\\
C_{M\left(MgCl_2\right)}=\dfrac{0,04}{0,2}=0,2M\)
Số gà trống:
`(135xx2)/(2+3)=54(con)`
Số gà mái :
`135-54=81(con)`
Số gà trống:
`135 : (2+3) xx 2 = 54` con
Số gà mái
`135 - 54 = 81` con
Tổng số phần bằng nhau:
`2+3=5(phần)
Số gà trống có :
`135:5xx32=54 (con)`
Số gà mái có :
`135-54=81(con)`