a, 674 - { 12 + x } =427
Tìm x :
a) 674 - ( 12 + x ) = 427 b) 685936 - x = 43488 : 8
c) x + 6734 = 3478 + 5782 d) 2054 + x = 4725 - 279
g) 2975 + x = 12856 - 8436 e) 18954 : x = 8653 - 86747
Các bạn giúp mình với!
Tìm x :
a) 674 - ( 12 + x ) = 427 b) 685936 - x = 43488 : 8
c) x + 6734 = 3478 + 5782 d) 2054 + x = 4725 - 279
g) 2975 + x = 12856 - 8436 e) 18954 : x = 8653 - 86747
Các bạn giúp mình đi mà mai mình nộp rồi huhu
a) 674 - ( 12 + x ) = 427 b) 685936 - x = 43488 : 8
12 + x = 674 - 427 685936 - x = 5436
12 + x = 247 x = 685936 - 5436
x = 247 - 12 x = 680500
x = 235
c) x + 6734 = 3478 + 5782 d) 2054 + x = 4725 - 279
x + 6734 = 9260 2054 + x = 4446
x = 9260 - 6734 x = 4446 - 2054
x = 1526 x = 2392
g) 2975 + x = 12856 - 8436 Câu e) chép sai đề bài
2975 + x = 4420
x = 4420 - 2975
x = 1145
cai nay viet ra dai dong lam nhung minh lam duoc
Tính bằng cách thuận tiện: 427 x 12 – 427
\(=427\times\left(12-1\right)\\ =427\times11\\ =4697\)
Tính nhanh: 674 x 99 + 674 và 978 x 101 - 978
674 x 99 + 674 978 x 101 - 978
= 674 x ( 99 + 1 ) = 978 x ( 101 - 1 )
= 674 x 100 = 978 x 100
= 67400 = 97800
674 x 99 + 674
= 674 x 99 + 674 x 1
= 674 x ( 99 + 1 )
= 674 x 100
= 67400
978 x 101 - 978
= 978 x 101 - 978 x 1
= 978 x ( 101 - 1 )
= 978 x 100
= 97800
1 . 25 x { 32 : [ 12 - 4 + 4 x ( 16 : 8 ) ] }
2. 2195 x 1952 - 952 x 427 - 1952 x 1768
`Answer:`
1. \(25.\left\{32:[12-4+4.\left(16:8\right)]\right\}\)
\(=25.\left\{32:[12-4+4.2]\right\}\)
\(=25.\left\{32:[12-4+8]\right\}\)
\(=25.\left\{32:[8+8]\right\}\)
\(=25.\left\{32:16\right\}\)
\(=25.2\)
\(=50\)
2. \(2195.1952-952.427-1952.1768\)
\(=2195.1952-1952.1768-952.427\)
\(=\left(2195-1768\right).1925-952.427\)
\(=427.1952-952.427\)
\(=\left(1952-952\right).427\)
\(=1000.427\)
\(=427000\)
Số ‘‘ba triệu không trăm hai mươi lăm nghìn sáu trăm bảy mươi tư’’ viết là:
A. 3 000 000 25 000 674 B. 3 000 000 25 674
C. 3 025 674 D. 325 674
Tìm x :
a) x - 5 = 49 : 7
b) 2 \(\times\) x + 6 = 24
c) \(\frac{1}{3}:x+\frac{1}{2}=5\)
d) \(\frac{1}{6}\times x-\frac{1}{3}=2\)
e)\(\frac{x}{27}=\frac{3}{x}\left(vớix\in N\right)\)
g) 1200 : 24 - ( 17 - x ) = 36
h) 674 - ( 12 + x ) = 427
k) 36 \(\times\)( x - 9 ) = 900
m) 1,2 : x + 3,8 : x = 2,5
n) \(\left(\frac{1}{2\times4}+\frac{1}{4\times6}+\frac{1}{6\times8}+\frac{1}{8\times10}\right)\times x=\frac{1}{3}\)
Mik đang cần gấp
Tìm x :
a) \(x-5=49:7\)
\(\Leftrightarrow x-5=7\)
\(\Leftrightarrow x=7+5\)
\(\Leftrightarrow x=12\)
Vậy : \(x=12\)
b) \(2x+6=24\)
\(\Leftrightarrow2x=24-6=18\)
\(\Leftrightarrow x=18:2\)
\(\Leftrightarrow x=9\)
Vậy : \(x=9\)
c) \(\frac{1}{3}:x+\frac{1}{2}=5\)
\(\Leftrightarrow\frac{1}{3}:x=5-\frac{1}{2}=\frac{9}{5}\)
\(\Leftrightarrow x=\frac{1}{3}:\frac{9}{5}\)
\(\Leftrightarrow x=\frac{5}{27}\)
Vậy : \(x=\frac{5}{27}\)
d) \(\frac{1}{6}.x-\frac{1}{3}=2\)
\(\Leftrightarrow\frac{1}{6}.x=2-\frac{1}{3}=\frac{5}{3}\)
\(\Leftrightarrow x=\frac{5}{3}:\frac{1}{6}\)
\(\Leftrightarrow x=10\)
Vậy : \(x=10\)
e) \(\frac{x}{27}=\frac{3}{x}\)
\(\Leftrightarrow x.x=27.3\)
\(\Leftrightarrow x^2=81\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-9\\x=9\end{matrix}\right.\) mà \(x\in N\)
\(\Rightarrow x=9\)
Vậy : \(x=9\)
g) \(1200:24-\left(17-x\right)=36\)
\(\Leftrightarrow50-17+x=36\)
\(\Leftrightarrow33+x=36\)
\(\Leftrightarrow x=36-33\)
\(\Leftrightarrow x=3\)
Vậy : \(x=3\)
h) \(674-\left(12+x\right)=427\)
\(\Leftrightarrow12+x=674-427=247\)
\(\Leftrightarrow x=247-12\)
\(\Leftrightarrow x=230\)
Vậy : \(x=230\)
k) \(36.\left(x-9\right)=900\)
\(\Leftrightarrow x-9=900:36\)
\(\Leftrightarrow x-9=25\)
\(\Leftrightarrow x=25+9\)
\(\Leftrightarrow x=34\)
m) \(1,2:x+3,8:x=2,5\)
\(\Leftrightarrow\left(1,2-3,8\right):x=2,5\)
\(\Leftrightarrow-2,6:x=2,5\)
\(\Leftrightarrow x=\frac{-2,6}{2,5}=-\frac{26}{25}\)
Vậy : \(x=-\frac{26}{25}\)
n) \(\left(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+\frac{1}{8.10}\right).x=\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{2}.\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+\frac{2}{8.10}\right).x=\frac{1}{3}\)
\(\Leftrightarrow\left[\frac{1}{2}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+\frac{1}{8}-\frac{1}{10}\right)\right].x=\frac{1}{3}\)
\(\Leftrightarrow\left[\frac{1}{2}.\left(1-\frac{1}{10}\right)\right].x=\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{2}.\frac{9}{10}.x=\frac{1}{3}\)
\(\Leftrightarrow\frac{9}{20}.x=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{3}:\frac{9}{20}\)
\(\Leftrightarrow x=\frac{20}{27}\)
Vậy : \(x=\frac{20}{27}\)
c)\(\frac{2}{27}\)
d)21
e)81
g)3
k)34
m)2
n)\(\frac{5}{3}\)
bài 4:không thực hiện phép tính,hãy tìm x
a) x + 674 + 52 =674 + 6042 + 52
b) (58 + x) + 4270 =58 +4270 + 476
Tìm X :
a. 6 ( x - 12 ) + 18 = 60
b.( x - 40 ) - 270 = 12
c. 427 - ( x + 100 ) = 227
d. 9 x - 13 = 671
e. { 231 - ( x - 6) } . 13 = 1339
Nhớ trình bày cách làm
Dấu chấm là dấu nhân
a) 6 ( x - 12 ) + 18 = 60
6 ( x - 12 ) = 60 - 18 = 42
x - 12 = 42 : 6 = 7
x = 7 + 12
x = 19
b) ( x - 40 ) - 270 = 12
x - 40 = 12 + 270 = 282
x = 282 + 40
x = 322
c) 427 - ( x + 100 ) = 227
x + 100 = 427 - 227 = 200
x = 200 - 100
x = 100
d) 9x - 13 = 671
9x = 671 + 13 = 684
x = 684 : 9
x = 76
a, 6 ( x - 12 ) + 18 = 60
6 ( x - 12 ) = 60 - 18
x - 12 = 42 : 6
x - 12 = 7
x = 7 + 12
x = 19
Câu a đại khái là rứa, mấy câu sau dễ lăm, tự mần!
^^ Cố gắng làm nhask!