voi x > 1/2
tim gtnn cua D=x/3 + 5/2x-1
Voi x>=-2.Tim GTNN cua bieu thuc N=x^2+2x+1/(x+2)
A=2x2+y mu 2 voi x+2y=1
Tinh gtnn cua A
A=2x/√x-2 tim GTNN cua A voi x>4
ap dung bdt co si tim gtnn cua bieu thuc y=x/3 +5/2x+1;x>1/2
Tim GTLN hoac( GTNN )cua bieu thuc ;
A=|2x-3/5|+1,(3)
B=1/3-|x-2| (B>0)00
C=-2|1/3x+4|+3/2
D=|x-3|+|x+2/3|
B=/2x-100/ +/200-2x/ tìm GTNN cua B
C=/x-70/+/20+x/ timf GTNN cua C
D=/x-80/+/x-200/ timfGTTN cua D
tim GTNN cua (x+5/x-4)+x voi x>4
Tim GTNN cua (2x + 1).(x - 5) Mn giup e
\(\left(2x+1\right)\left(x-5\right)=2x^2-9x-5=2\left(x^2-\frac{9}{2}x+\frac{81}{16}\right)-\frac{121}{8}=2\left(x-\frac{9}{4}\right)^2-\frac{121}{8}\ge-\frac{121}{8} \)
Vậy GTNN của biểu thức là \(-\frac{121}{8}\)khi x = \(\frac{9}{4}\)
1tim x ∈ Z thoa man
a)/x/+/-5/=/-37/ b)/-6/./x/=/54/
c)/x/>21 d)/x/<-1
2tim x
a)x+3=/-3/+/-7/ b)-2</x/<2
a) |x| + |-5| = |-37|
<=> |x| + 5 = 37
<=> |x| = 37 - 5 = 32
=> x \(\in\) {32 ; -32}
b)|-6| . |x| = |54|
<=> 6 . |x| = 54
|x| = 54 : 6 = 9
=> x \(\in\){9;-9}
c) |x| > 21
Có |x| \(\ge\) 0 > 21
=> |x| \(\in\) { 22 ; 23 ; 24 ; 25 ; ....}
=> x \(\in\) { 22; -22 ; 23; -23; 24; -24; 25; -25; ....}