=> [ (x - 300)² - 280 ] . 2 = 5938

=> (x - 300)² - 280 = 2969

=> (x - 300)² = 3249

=> x - 300 = 57 => x = 357

hoặc x - 300 = -57 => x = 243

Vậy x = 357 ; x = 

b, 2 + 4 + 6 +.....+2x =210

    =>2*(1+2+3+....+x) =210

  => 1+2+3+....+x = 105

   => (x+1)*x : 2 = 105

   => (x+1)*x  = 210

   => (x+1)*x  = 15*14

=>x=14

c) [(x  - 300)^2 - 280 ] * 2 = 19440

           => (x  - 300)^2 - 280  = 9720

           => (x  - 300)^2   = 10000 =100²

           => x  - 300 =100

=> x=400

a, 3^x-1+ 5* 3^x-1 = 162

             3^x-1 * (5 + 1) = 162

                    3^x-1 * 6 = 162

                               3^x-1  = 27 = 3³

                                   => x-1=3

                                            => x=4

A.200 ạ                                                      

Trả lời:   Câu A.200

Hok tốt !

#Tử Thần

 tl 200 nha bạn

câu 1

(27-x).2017=0

=>27-x=0

vậy x=27

câu 2

(x-40).15=15.3

x-40=3

vậy x=43

câu 3

x-280:35=5.54

x-280:35=270

x-8=270

vậy x=278

a) (15678 + 5938) x 4 = 21616 x 4    b) 9347 – 25636 : 4 = 9347 – 6409

   = 86464    = 2938

c) 21156 : 3 x 4 = 7052 x 4     d) 2450 : (825 – 820) = 2450 : 5

    = 28208    = 490

Bài 1:tìm x thuộc Z

a)x.(x-1)=0

\(\Leftrightarrow\left[\begin{matrix}x=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Vậy: \(x=0;1\)

b)(x-3).(x+4)=0

\(\Leftrightarrow\left[\begin{matrix}x-3=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=3\\x=-4\end{matrix}\right.\)

Vậy: \(x=3;-4\)

c)(2x-4).(x+2)=0

\(\Leftrightarrow2\left(x-2\right).\left(x+2\right)=0\)

\(\Leftrightarrow\left[\begin{matrix}x-2=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=2\\x=-2\end{matrix}\right.\)

Vậy: \(x=2;-2\)

d)(x+1)^2.(x-2)^2=0

\(\Leftrightarrow\left[\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=-1\\x=2\end{matrix}\right.\)

Vậy: \(x=-1;2\)

e) x(x+1).(x+2)^2.(x+3)^3=0

\(\Leftrightarrow\left[\begin{matrix}x=0\\x+1=0\\x+2=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=0\\x=-1\\x=-2\\x=-3\end{matrix}\right.\)

Vậy: \(x=0;-1;-2;-3\)

f)(x-9)^5.(x-5)^8=0

\(\Leftrightarrow\left[\begin{matrix}x-9=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=9\\x=5\end{matrix}\right.\)

Vậy: \(x=9;5\)

g)x(x+100)^10.(x+2000)^20.(x+300)^300=0

\(\Leftrightarrow\left[\begin{matrix}x=0\\x+100=0\\x+200=0\\x+300=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=0\\x=-100\\x=-200\\x=-300\end{matrix}\right.\)

Vậy: \(x=0;-100;-200;-300\)

h)(x-2)^2=0

\(\Leftrightarrow x-2=0\)

\(\Leftrightarrow x=2\)

Vậy: \(x=2\)

1)\(\left(x-280\right):35=56.5\)

\(\left(x-280\right):35=280\)

\(x-280=280.35\)

\(x-280=9800\)

\(x=9800+280\)

\(x=10080\)

2) \(\left(x-128+20\right):192=0\)

\(\Rightarrow\left(x-148\right):192=0\)

\(\Rightarrow x-148=0\)

\(\Rightarrow x=0+148\)

\(\Rightarrow x=148\)

3) \(460+85.4=\left(x+200\right).4\)

\(\Rightarrow\left(x+200\right).4=460+340\)

\(\Rightarrow\left(x+200\right).4=800\)

\(\Rightarrow x+200=800:4=200\)

\(\Rightarrow x+200=200\)

\(\Rightarrow x=200-200=0\)

4) \(x+5.2-\left(32+16.3:16-15\right)=0\)

\(\Rightarrow x+10-\left(32+3-15\right)=0\)

\(\Rightarrow x+10-20=0\)

\(\Rightarrow x+10=20\)

\(\Rightarrow x=20-10=10\)

nha m.n

a) 120 x 40 > 120 : 40

b) 280 + 70 < 280 x 70

c) 320 – 80 > 320 : 80

d) 610 + 0 = 610 – 0