2x^2-8x

=2x(x-4)

a: \(x^4-2x^3+x^2-2x\)

\(=\left(x^4-2x^3\right)+\left(x^2-2x\right)\)

\(=x^3\left(x-2\right)+x\left(x-2\right)\)

\(=x\left(x-2\right)\left(x^2+1\right)\)

b: \(x^4+x^3-8x-8\)

\(=\left(x^4+x^3\right)-\left(8x+8\right)\)

\(=x^3\left(x+1\right)-8\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3-8\right)\)

\(=\left(x+1\right)\left(x-2\right)\left(x^2+2x+4\right)\)

hai biểu thức ko thể p/t dc

a) x⁴+2x-4= x⁴+2x+1-5

               =(x²+1)²-5

              =(x²+1-\(\sqrt{5}\))(x²+1+\(\sqrt{5}\))

​​b) 4x² -8x +1

=4x²-8x+4-3

=(2x-2)²-3

=(2x-2+\(\sqrt{3}\))(2x-2-\(\sqrt{3}\))

mik đồng ý vs trieu dang

Trả lời:

x³ - 8x + 2x ( x - 2 )

= x³ - 8x + 2x² - 4x

= x ( x² - 8 + 2x - 4 )

= x ( x² + 2x - 12 )

cần gấp nha , mik chọn cho

2x³ - x² - 8x + 4 = x²(2x - 1) - 4(2x - 1) = (2x - 1)(x - 2)(x + 2)

2x³-x² -8x+4=(2x³-x²)-(8x+4)

                     =x²(2x-1)-4(2x-1)

                     = (2x-1)(x²-4)

                    = (2x-1)(x-2)(x+2)

a) 2x.( 4x - 1)

b),c) mik ko biết

Ko mong bạn tk cho mik

nhưng mik vẫn hi vọng b sẽ làm vậy

x³ - 2x² - 8x

= x( x² - 2x - 8 )

= x( x² - 4x + 2x - 8 )

= x[ x( x - 4 ) + 2( x - 4 ) ]

= x( x - 4 )( x + 2 )

\(x^3-2x^2-8x=x\left(x^2-2x-8\right)=x\left(x^2-2x+1-9\right)=x\left[\left(x-1\right)^2-3^2\right]=x\left(x-4\right)\left(x+2\right)\)