B = -1/3 + 1/3^2 - 1/3^3 +...+ 1/3^50 - 1/3^51
tính B
Những câu hỏi liên quan
B = -1/3 + 1/3^2 - 1/3^3 +...+ 1/3^50 - 1/3^51
Tính B = -1/3 + 1/3^2 - 1/3^3 + ....+ 1/3^50 - 1/3^51
B=-1/3+1/3^2-.....-1/3^51
3B=-1/3^2+1/3^3-.....-1/3^52
3B-B=(-1/3^2+1/3^3-....-1/3^52)-(-1/3+1/3^2-....-1/3^51)
2B= -1/3^52-1/3
2B= -1/3^52-3^51/3^52
2B= -1-3^51/3^52
B= -3^51-1/3^52x2
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TÍNH B= -1/3+1/3^2-1/3^3+.....+1/3^50-1/3^51
B=1/3+1/3 mũ 2 +1/3 mũ 3 + ...... +1/3 mũ 50
B = \(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^{50}}\)
3B = \(1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{49}}\)
2B = 3B - B = \(1-\frac{1}{3^{50}}\)
=> B = \(\frac{1-\frac{1}{3^{50}}}{2}\)
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tính \(B=\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+...+\dfrac{1}{3^{50}}-\dfrac{1}{3^{51}}\)
\(B=\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+...+\dfrac{1}{3^{50}}-\dfrac{1}{3^{51}}\)
\(=\dfrac{1}{\left(-3\right)}+\dfrac{1}{\left(-3\right)^2}+\dfrac{1}{\left(-3\right)^3}+...+\dfrac{1}{\left(-3\right)^{50}}+\dfrac{1}{\left(-3\right)^{51}}-\dfrac{1}{3}\)
\(=\dfrac{1}{\left(3\right)^2}+\dfrac{1}{\left(3\right)^3}+...+\dfrac{1}{\left(-3\right)^{51}}+\dfrac{1}{\left(-3\right)^{52}}\)
\(\Rightarrow\dfrac{4}{3}B=\dfrac{1}{-3}-\dfrac{1}{\left(-3\right)^{52}}=\dfrac{-3^{51}-1}{3^{52}}\Rightarrow B=\dfrac{-3^{51}-1}{4.3^{51}}\)
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Giúp mình giải câu này với Tính B= -1/3+1/3^2-1/3^3+1/3^4-1/3^5+...+1/3^50-1/3^51
\(B=-\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+....+\dfrac{1}{3^{50}}-\dfrac{1}{3^{51}}\)
=> \(3B=-1+\dfrac{1}{3}-\dfrac{1}{3^2}+...+\dfrac{1}{3^{49}}-\dfrac{1}{3^{50}}\)
=> \(4B=-1-\dfrac{1}{3^{51}}\)
=> \(B=\dfrac{-1-\dfrac{1}{3^{51}}}{4}\)
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Bài 1: Tính nhanh:
a) \(\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{50}}\)
b)\(\dfrac{5}{3}+\dfrac{5}{3^2}+\dfrac{5}{3^3}+...+\dfrac{5}{3^{50}}\)
\(A=\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{50}}\)
\(3.A=1+\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{49}}\)
\(2A=3A-A=1-\dfrac{1}{3^{49}}\)
\(\Rightarrow A=\dfrac{1-\dfrac{1}{3^{50}}}{2}\)
\(B=\dfrac{5}{3}+\dfrac{5}{3^2}+...+\dfrac{5}{3^{50}}=5\left(\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{50}}\right)\)
Căn cứ vào câu A thì các trong ngặc bằng \(\dfrac{1-\dfrac{1}{3^{50}}}{2}\)
suy ra \(B=\dfrac{5\left(1-\dfrac{1}{3^{50}}\right)}{2}\)
tick mik nha
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Tính
1)A=1×2×3+2×3×4+.....+48×49×50
2)B=1×2+2×3+3×4+......+49×50
A = 1 × 2 × 3 + 2 × 3 × 4 + .....+ 48 × 49 × 50
ta có 4 x A = 1 x 2 x 3 x 4 + 2 x 3 x 4 x (5 -1) + .....+ 48 × 49 × 50 x (51 - 47)
= 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 - 1 x 2 x 3 x 4 + ... + 48 x 49 x 50 x 51 - 47 x 48 x 49 x 50
= 48 x 49 x 50 x 51
suy ra A = (48 x 49 x 50 x 51) : 4
= 12 x 49 x 50 x 51
nhớ k cho mik nha rùi mik lm nốt cho
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A = 1 × 2 × 3 + 2 × 3 × 4 + .....+ 48 × 49 × 50
ta có 4 x A = 1 x 2 x 3 x 4 + 2 x 3 x 4 x (5 -1) + .....+ 48 × 49 × 50 x (51 - 47)
= 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 - 1 x 2 x 3 x 4 + ... + 48 x 49 x 50 x 51 - 47 x 48 x 49 x 50
= 48 x 49 x 50 x 51
suy ra A = (48 x 49 x 50 x 51) : 4
= 12 x 49 x 50 x 51
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A=1×1+2×2+3×3+....+50×50
B=1×3+5×7+9×11+...+99×101
