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`Answer:`

`\frac{x-1}{34}+\frac{x-2}{34}=\frac{x-3}{32}+\frac{x-4}{31}`

`<=>\frac{x-1}{34}-1+\frac{x-2}{33}-1=\frac{x-3}{32}-1+\frac{x-4}{31}-1`

`<=>\frac{x-35}{34}+\frac{x-35}{33}=\frac{x-35}{32}+\frac{x-35}{31}`

`<=>(x-35)(\frac{1}{34}+\frac{1}{33}-\frac{1}{32}-\frac{1}{31})=0`

`<=>x-35=0`

`<=>x=35`

a: \(=\dfrac{18}{51}\cdot\dfrac{34}{9}\cdot\dfrac{17}{18}=\dfrac{17}{51}\cdot\dfrac{34}{9}=\dfrac{1}{3}\cdot\dfrac{34}{9}=\dfrac{34}{27}\)

b: \(=\dfrac{21}{32}\cdot\dfrac{4}{7}\cdot25\cdot\dfrac{4}{5}=\dfrac{21}{7}\cdot\dfrac{4}{32}\cdot20=60\cdot\dfrac{1}{8}=\dfrac{15}{2}\)

x - ( 32 - 9 ) = 5 - ( 34 - 9 )

x - 23 = 5 - 25

x - 23 = -20

      x = -20 + 23

      x = 3

Vậy x = 3

x-(32-9)=5-(34-9)

x-(32-9)=5-25

x-23=-20

x = -20+23

x = 3 

x-(32-9)=5-(34-9)

x - 23 = 5 - 25

x - 23 = -30

x = -30 +23

x= - 7

`1,`

`538 - x = 275`

`\Rightarrow x = 538 - 275`

`\Rightarrow x = 263`

Vậy, `x = 263`

`2,`

`45 - 9x = 18`

`\Rightarrow 9x = 45 - 18`

`\Rightarrow 9x = 27`

`\Rightarrow x = 27 \div 9`

`\Rightarrow x = 3`

Vậy, `x = 3`

`3,`

`(5x - 9) \div 3 = 12`

`\Rightarrow 5x - 9 = 12. 3`

`\Rightarrow 5x - 9 = 36`

`\Rightarrow 5x = 36 + 9`

`\Rightarrow 5x = 45`

`\Rightarrow x = 45 \div 5`

`\Rightarrow x = 9`

Vậy, `x = 9.`

1) \(538-x=275\)

\(x=538-275\)

\(x=263\)

2) \(45-9x=18\)

\(9x=27\)

\(x=3\)

3) \(\left(5x-9\right)\div3=12\)

\(\left(5x-9\right)=12\times3\)

\(5x-9=36\)

\(5x=45\)

\(x=9\)

1. \(538-x=275\)

\(x=538-275\)

\(x=263\)

2.\(45-9x=18\)

\(9x=45-18\)

\(9x=27\)

\(x=27:9\)

\(x=3\)

1. \(x-8+32=68\)

\(x-8=68-32\)

\(x-8=36\)

\(x=36+8\)

\(x=44\)

_____

2. \(x+8+32=68\)

\(x+8=68-32\)

\(x+8=36\)

\(x=36-8\)

\(x=28\)

_____

3. \(98-x+34=43\)

\(98-x=43-34\)

\(98-x=9\)

\(x=98-9\)

\(x=89\)

_____

4. \(98+x-34=43\)

\(98+x=43+34\)

\(98+x=77\)

\(x=77-98\)

\(x=-21\)

_____

5. \(x:5:4=800\)

\(x:5=800.4\)

\(x:5=3200\)

\(x=3200.5\)

\(x=16000\)

_____

6. \(18+x=384:8\)

\(18+x=48\)

\(x=48-18\)

\(x=30\)

_____

7. \(\left(84,6-2\times x\right):3,02=5,1\)

\(84,6-2.x=5,1.3,02\)

\(84,6-2.x=15,402\)

\(2.x=84,6-15,402\)

\(2.x=69,198\)

\(x=69,198:2\)

\(x=34,599\)

_____

8. \(x\times5=120:6\)

\(x.5=20\)

\(x=20:5\)

\(x=4\)

_____

9. \(\left(15\times24-x\right):0,25=100:0,25\)

\(\left(15.24-x\right):0,25=400\)

\(15.24-x=400.0,25\)

\(15.24-x=100\)

\(360-x=100\)

\(x=360-100\)

\(x=260\)

1,x-8+32=68

=>x-8=68-32=36

=>x=36+8=42

2,x+8+32=68

=>x+8=68-32=36

=>x=36-8=28

3,98-x+34=43

=>98-x=43-34=9

=>x=98-9=89

4,98+x-34=43

=>98+x=43+34=77

=>x=77-98=-21

5,x:5:4=800

=>x:20=800

=>x=800x20=16000

6,18+x=384:8=48

=>x=48-18=30

7,(84,6-2x):3,02=5,1

=>84,6-2x=5,1x3,02=15,402

=>2x=84,6-15,402=69,198

=>x=69,198:2=34,599

8,5x=120:6=20

=>x=20:5=4

9,(15x24-x):0,25=100:0,25=400

=>360-x=400x0,25=100

=>x=360-100=260.

1. \(...\Rightarrow x+24=68\Rightarrow x=68-24=44\)

2. \(...\Rightarrow x+40=68\Rightarrow x=68-40=28\)

3. \(...\Rightarrow3^{2\left(8+x\right)}=9=3^2\Rightarrow2\left(8+x\right)=2\Rightarrow8+x=1\Rightarrow x=-7\)

4. \(...\Rightarrow3^{2\left(8+x\right)}=77\) (bạn xem lại đề)

5. \(...\Rightarrow x:5=800.4\Rightarrow x:5=3200\Rightarrow x=3200.5=16000\)

6. \(...\Rightarrow18+x=48\Rightarrow x=48-18=30\)

7. \(...\Rightarrow84,6-2x=5,1.3,02=15,402\Rightarrow2x=84,6-15,402\Rightarrow2x=69,198\Rightarrow x=34,599\)

8. \(...\Rightarrow5.x=20\Rightarrow x=20:5=4\)

9. \(\left(360-x\right):0,25=400\Rightarrow360-x=400.0,25=100\Rightarrow x=400-100=300\)

a) 

x – 8 + 32 = 68

x – 8 = 68 – 32 

x – 8 = 36

x = 36 + 8

x = 44

b) 

x + 8 + 32 = 68

x + 8 = 68 – 32

x + 8 = 36

x = 36 – 8

x = 28

c) 

98 – x + 34 = 43

98 – x = 43 – 34

98 – x = 9

x = 98 – 9 

x = 89 

d) 

98 + x – 34 = 43

98 + x  = 43 + 34 

98 + x = 77

x = 98 – 77 

x = 21

tick cho mink nhé!

A) 34 + ( 9 - 21 ) = 3417 - (0 + 3417)

B) 9 - ( 55  - ( 49 + (-28 - 5 ))) = 13 -( 47 + -25 - 32 - 8 ))

C) |-1 - 1| - 1 + 1 = 0

D) |2 - 2| + 2 = 2

BÀI 3 : 

Để \(A=\frac{3n-5}{n+4}\)là giá trị nguyên 

\(\Rightarrow3n-5⋮n+4\)

\(\Rightarrow3n+12-17⋮n+4\)

\(\Rightarrow3\left(n+4\right)-17⋮n+4\)

\(\Rightarrow n+4\inƯ\left(17\right)=\left\{\pm1;\pm17\right\}\)

\(\Rightarrow n\in\left\{-3;-5;18;-10\right\}\)