{189-[34+(20-5)]} : 20
{189-[34+(20+5)]}:20
\(\left\{189-\left[34+\left(25+5\right)\right]\right\}:20\\ =\left[189-\left(34+25\right)\right]:20\\ =\left(189-59\right):2\\ =130:20\\ =6,5\)
Câu 1 : Tính :
a, (-115)+(-40)+115+|-35|
b, [ 189 - [34+20-5)]] : 20
Câu 2 : Tìm số nguyên x biết :
a, x - 15 = 20 . 2 mũ 2
b, 48 + 5(x-3)=63
c, |x| - 2 = 7-(-8)
a, (-115)+(-40)+115+|-35|
=[(-115) +115] + [(-40) +35]
=-5
b)[ 189 - (34+20-5)] : 20
= (189-49) :20
= 140:20 =7
2.a) x-15= 20.22
<=> x-15 = 80
<=> x=80 + 15
<=> x=95
VẬy x=95
b) 48 +5(x-3) = 63
<=> 5(x-3) = 63-48
<=> 5(x-3) =15
<=> x-3 = 15:5
<=>x-3 = 3
<=> x=6
Vậy x=6
c) |x| -2 = 7-(-8)
<=> |x| -2 = 15
<=> |x| =15+2
<=> |x| = 17
<=>\(\left[{}\begin{matrix}x=17\\x=-17\end{matrix}\right.\)
Vậy x=17 hoặc x=-17
bài 1 : thục hiện phép tính
20:[24-(32.4-34)2]-20
bài 2: tìm x,biết :
14+5x=46:43
189-2.(93-x)=59
bai 1
20:(24-(3^2.4-34)^2)-20
=20:(24-(9.4-34)^2)-20
=20:(24-2^2)-20
=20:20-20
=-19
bai 2
a
14+5x=4^6:4^3
14+5x=4^3
14+5x=64
5x=64-14
5x=50
x=50:5
x=10
b
189-2.(93-x)=59
2..(93-x)=189-59
2.(93-x)=130
(93-x)=130:2
93-x=65
x=93-65
x=28
1) \(20:\left[24-\left(3^2.4-34\right)^2\right]-20\)
\(=20:\left[24-\left(9.4-34\right)^2\right]-20\)
\(=20:\left[24-4\right]-20\)
\(=20:20-20\)
\(=1-20\)
\(=-19\)
2)a.\(14+5x=4^6:4^3\)
\(14+5x=64\)
\(5x=64-14\)
\(5x=50\)
\(\Rightarrow x=10\)
b) 189-2(93-x)=59
2(93-x) =189-59
2(93-x) =130
93-x =130:2
93-x =65
x =93-65
x =28
Học tốt nha!!!
SO SÁNH:a) 3 mũ 34 và 5 mũ 20 b) 71 mũ 5 và 17 mũ 20
so sánh:
a) 3^34 và 5^20
b) 71^5 và 17^20
a) 520<330<334
520=(52)10=2510
330=(33)10=2710
vi 2510 <2710 nen 520 <330 va330<334
=> 520<334
b) 715<725<1620<1720
725 = (8.9)5=85.95=85. 310
1620=(8.2)20=820.220=820.410
vi 85 <820 va 310<410
nen 725<1620
-> 715<1720
1.Tính nhanh nếu có thể:
1) (+15)+(+17)
2) (-3)+(-7)
3) (-25)+(+4)
4) (-6)+(-54)
5) (-15)+20
6)(-5)+8+7+5
7) (-8)+(-11)+(-2)
8) 15+(-5)+(-14)+(-16)
9) (-20)+(-14)+3+(-86)
10)(-136)+123+(-264)+(-83)+240
11) (-596)+2001+1999+(-404+189)
12, ( 314 + ( -153) +64 +121+(-247)+218
1) \(\left(+15\right)+\left(+17\right)=15+17=32\)
2) \(\left(-3\right)+\left(-7\right)=-3-7=-\left(3+7\right)=-10\)
3) \(\left(-25\right)+\left(+4\right)=-25+4=-\left(25-4\right)=-21\)
4) \(\left(-6\right)+\left(-54\right)=-6-54=-\left(6+54\right)=-60\)
5) \(\left(-15\right)+20=20-15=5\)
6) \(\left(-5\right)+8+7+5\)
\(=\left(-5+5\right)+\left(8+7\right)\)
\(=15\)
7) \(\left(-8\right)+\left(-11\right)+\left(-2\right)\)
\(=\left[\left(-8\right)+\left(-2\right)\right]+\left(-11\right)\)
\(=\left(-10\right)+\left(-11\right)\)
\(=-21\)
8) \(15+\left(-5\right)+\left(-14\right)+\left(-16\right)\)
\(=\left[15+\left(-5\right)\right]+\left[\left(-14\right)+\left(-16\right)\right]\)
\(=10+\left(-30\right)\)
\(=-20\)
9) \(\left(-20\right)+\left(-14\right)+3+\left(-86\right)\)
\(=\left[\left(-20\right)+3\right]+\left[\left(-14\right)+\left(-86\right)\right]\)
\(=\left(-17\right)+\left(-100\right)\)
\(=-117\)
10) \(\left(-136\right)+123+\left(-264\right)+\left(-83\right)+240\)
\(=\left[\left(-136\right)+\left(-264\right)\right]+\left[123+\left(-83\right)\right]+240\)
\(=\left(-400\right)+40+240\)
\(=\left(-360\right)+240\)
\(=-120\)
11) \(\left(-596\right)+2001+1999+\left(-404+189\right)\)
\(=\left(-596\right)+2001+1999-404+189\)
\(=\left[\left(-596\right)-404\right]+\left(2001+189\right)+1999\)
\(=\left(-1000\right)+2190+1999\)
\(=1190+1999\)
\(=3189\)
12) \(314+\left(-153\right)+64+121+\left(-247\right)+218\)
\(=\left(314+64+121\right)+\left[\left(-153\right)+\left(-247\right)\right]+218\)
\(=\left(378+121\right)+\left(-400\right)+218\)
\(=499-400+218\)
\(=99+218\)
\(=317\)
\(\text{#}Toru\)
5 tan +20 ta +34 yen
(so sánh
a.3^34 va 5^20
b.7^15 va 17^20
So sánh: a) 334và 520 b) 715 và 1720
b/ Ta có: 1720 = (174)5 = 835215
Vì 715 < 835215 nên 715 < 1720.