a) x = 2 

b) x = 2     

c) x = 2

d) x = 1.

a) Ta có:  ( 2 x + 1 ) 3 = 3 3 nên 2x + 1 = 3. Do đó x = 1.

b) Ta có: ( 2 x - 1 ) 3 = 5 3 nên 2x - 1 = 5. Do đó x = 3.

(2x + 1)³ = 125 = 5³

=> 2x + 1 = 5

=> 2x = 4

=> x = 2

(2x+1)³ = 125 = 5³

=> 2x + 1 = 5

2x = 4

x = 2 

\(\left(2x+1\right)^3=125\)

\(\Leftrightarrow2x+1=15\)

\(\Leftrightarrow2x=14\Leftrightarrow x=7\)

\(\left(2x+1\right)^3=125\) 

\(\left(2x+1\right)^3=5^3\) 

\(2x+1=5\) 

\(x=2\)

\(\left(2x+1\right)^3=125\Leftrightarrow\left(2x+1\right)^3=5^3\)

\(\Leftrightarrow2x+1=5\Leftrightarrow x=2\)

\(a,2^x.4=128\\2^x.2^2=2^7\\ 2^x=\dfrac{2^7}{2^2}=2^{7-2}=2^5\\ Vậy:x=5\\ ----\\ b,\left(2x+1\right)^3=125=5^3\\ \Rightarrow 2x+1=5\\ 2x=5-1=4\\ x=\dfrac{4}{2}=2\\ ----\\ c,2x-2^6=6\\ 2x=6+2^6=6+64\\ 2x=70\\ x=\dfrac{70}{2}=35\\ ----\\ d,49.7^x=2401\\ 7^x=\dfrac{2401}{49}=49=7^2\\ Vậy:x=2\)

(2x+1)3=125

=> 2x + 1 = 41,666667

=> 2x = 42,66667

=> x =  21,33333

\(\left(2x+1\right)3=125\)

\(2x+1=125.3\)

\(2x+1=375\)

\(2x=375-1\)

\(2x=374\)

\(x=374:2\)

\(x=187\)

(2x+1)3 = 125

2x+1     = 125 : 3

2x+1     = 41,6666

2x         = 41,6666-1

2x         = 40,6666

Ta có: \(^{\left(2x+1\right)^3=125}\)
=> \(\left(2x+1\right)^3=5^3\)(vì \(5^3\)= 125)
=> 2x+1 = 5

=> 2x = 5-1 = 4

=> x = 4:2
=>x = 2

Vậy x = 2

\(\left(2x+1\right)^3=125\)

\(\left(2x+1\right)^3=5^3\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow2x=4\)

\(\Rightarrow2\)

[2x+1]³=125

<=>[2x+1]³

<=>2x+1=5

<=>2x=4

<=>x = 2

(2x + 1)³ = 125 = 5³

=> 2x + 1 = 5

2x = 5 - 1

2x = 4

x = 4:2

x = 2

( 2x + 1 )³ = 125

5³=125

=> 2x = 5-1

2x=4

x=4:2

x=2

x=2

tích đúng cho mình nha

3:

a: 3^x*3=243

=>3^x=81

=>x=4

b; 2^x*16^2=1024

=>2^x=4

=>x=2

c: 64*4^x=16^8

=>4^x=4^16/4^3=4^13

=>x=13

d: 2^x=16

=>2^x=2^4

=>x=4

a) \(3\left(2x-5\right)+125=134\)

\(\Leftrightarrow3\left(2x-5\right)=9\)

\(\Leftrightarrow2x-5=3\)

\(\Leftrightarrow2x=8\Leftrightarrow x=4\)

b) \(\left(2x+5\right)+\left(2x+3\right)+\left(2x+1\right)=27\)

\(\Leftrightarrow6x+9=27\)

\(\Leftrightarrow6x=18\Leftrightarrow x=3\)

d) \(27\left(x-27\right)-27=0\)

\(\Leftrightarrow27\left(x-27\right)=27\)

\(\Leftrightarrow x-27=1\Leftrightarrow x=28\)

3.(x+5)-2x=27
3.x+3.5-2x=27
3x+15-2x=27
x.(3-2)+15=27
x.  1    +15=27
  x       +15=27
  x             =27-15
  x             =12