3^x+1+3^x+2+3^x+3=9477
[(x^2+54)-42]×2=224
Tìm x:
3^x + 3^x+1 + 3^x+2 = 9477
Ta có 3^x + 3^x+1 + 3^x+2 = 9477 <=> 3^x ( 1+3 + 9 ) = 9477 <=> 13 * 3^x = 9477 <=> 3^x = 729 <=> 3^x = 3^6 <=> x=6
Vậy x=6
tìm x:
a} 3x +15=18
b} {3x3+4}2=32+23+83
c} [ {x2+54} -42] .2 =224
AI GIẢI NHANH NHẤT THÌ MÌNH TICK 3 CÁI .GIẢI HẮN RA NHÉ .
a) 3x + 15 = 18
3x = 18 - 15
3x = 3
3x = 31
=> x = 1
Vậy x =1
1) 54 : x - x : x = 3 x 2 - 1
2) 42 : x + x - x = 4 x 3 - 4
3) 24 : x - 2 x 4 = 24 - 2 x 3 x 4
1, 54 : x - 1 = 5
54 : x = 5+1 = 6
x = 54 : 6 = 9
2, 42 : x + 0 = 8
x = 42 : 8 = 21/4
3, 24 : x - 8 = 0
24 : x = 0 + 8 = 8
x = 24 : 8 = 3
Tk mk nha
1) 54:x-x:x=3x2-1
54:x- 1 =6-1
54:x- 1=5
54:x =6
x=54:6=9
Tìm các số x và y biết
1) 4/x= y/21=28/49. 2) x/2=3/y. 3)42/54=7/x
4) 2/3 =y/15. 5)6/10 = 3/x =y/20
\(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{28}{49}=\dfrac{28:7}{49:7}=\dfrac{4}{9}\\ Vậy:x=\dfrac{4.9}{4}=9\\ y=\dfrac{4.21}{9}=\dfrac{28}{3}\)
\(\dfrac{x}{2}=\dfrac{3}{y}\\ \Leftrightarrow x.y=2.3=6\\ Vậy:\left[{}\begin{matrix}\left(x;y\right)=\left(1;6\right)=\left(6;1\right)\\\left(x;y\right)=\left(2;3\right)=\left(3;2\right)\end{matrix}\right.\)
\(3,\\ \dfrac{42}{54}=\dfrac{42:6}{54:6}=\dfrac{7}{9}\\ \dfrac{42}{54}=\dfrac{7}{x}=\dfrac{7}{9}\\ Vậy:x=\dfrac{7.9}{7}=9\)
`A)2/3=x/60`
`=>40/60=x/60`
`=>x=40`
`B)-1/2=y/18`
`=>-9/18=y/18`
`=>y=-9`
`C)3/x=y/35=-36/84`
Mà `-36/84=(-3 xx 12)/(7 xx 12)=-3/7`
`=>3/x=-3/7`
`=>x=-7`
`y/35=-3/7=-15/35`
`=>y=-15`
`D)7/x=y/27=-42/54`
Mà `-42/54=(-7 xx 6)/(9 xx 6)=-7/9`
`=>7/x=-7/9`
`=>x=-9`
`y/27=-7/9=-21/27`
`=>y=-21`
a) Ta có: \(\dfrac{2}{3}=\dfrac{x}{60}\)
\(\Leftrightarrow x=\dfrac{2\cdot60}{3}=40\)
Vậy: x=40
Tìm x thuộc N, biết :
[(46-32)^2-(54-42)^2].2.x-1872=0
(x-7)^7=(c-7)^8
1+2^3+3^3-4^2.x=20
[(46-32)^2-(54-42)^2]*36-1872
=(14^2-12^2)*36-1872
=(196-144).36-1872
=52.36-1872
=1872-1872
=0
(x-7)^7=(x-7)^8
=>(x-7)^7-(x-7)^8=0
=>(x-7)^7.1-(x-7)^7.(x-7)=0
=>(x-7)^7.[1-(x-7)]=0
\(\Rightarrow\orbr{\begin{cases}x-7=0\\1-\left(x-7\right)=0\end{cases}\Rightarrow\orbr{\begin{cases}x=7;-7\\x=0\end{cases}}}\)
Vậy x={7;-7;0}
1+2^3+3^3-4^2.x=20
=>36-4^2.x=20
=>4^2.x=16=4^2
=>2.x=2
=>x=1
| 38 x 2 = ? | 77 x 3 = ? |
| 26 x 4 = ? | 54 x 6 = ? |
| 42 x 5 = ? | 48 x 3 = ? |
38x2=76
26x4=104
42x5=210
77x3=231
54x6=324
48x3=144
38x2=76 ;77x3=231 ;26x4=104 ;54x6=324 ;42x5=210 ;48x3=144
38 x 2 = 76
26 x 4 = 104
42 x 5=210
77 x 3 = 231
54 x 6 = 324
48 x 3 =144
HOK TỐT -_-
tìm x biết: 3^x+3^x+2=2430
2^x+3-2^x=224
3^x+2-3^x+1+3^=189
vậy mà bạn cuxg ghi nx . có nguwoif khác mik sẽ cho họ
tìm x biết: 3^x+3^x+2=2430
2^x+3-2^x=224
3^x+2-3^x+1+3^=189
a: \(\Leftrightarrow3^x\left(1+3^2\right)=2430\)
\(\Leftrightarrow3^x=243\)
hay x=5
b: \(\Leftrightarrow2^x\left(2^8-1\right)=224\)
=>2x=32
hay x=5