+)   (5x-1). (2x+3)-3. (3x-1)=0

10x^2+15x-2x-3 - 9x+3=0

10x^2 +8x=0

2x(5x+4)=0

=> x=0 hoặc x= -4/5

+)    x^3 (2x-3)-x^2 (4x^2-6x+2)=0

2x^4 -3x^3 -4x^4 + 6x^3 - 2x^2=0

-2x^4 + 3x^3-2x^2=0

x^2(-2x^2+x-2)=0

-2x^2(x-1)^2=0

=> x=0 hoặc x=1

+)   x (x-1)-x^2+2x=5

x^2 -x -x^2+2x=5

x=5

+)     8 (x-2)-2 (3x-4)=25

8x - 16-6x+8=25

2x=33

x=33/2

a) \(\sqrt[]{x^2-4x+4}=x+3\)

\(\Leftrightarrow\sqrt[]{\left(x-2\right)^2}=x+3\)

\(\Leftrightarrow\left|x-2\right|=x+3\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=x+3\\x-2=-\left(x+3\right)\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}0x=5\left(loại\right)\\x-2=-x-3\end{matrix}\right.\)

\(\Leftrightarrow2x=-1\Leftrightarrow x=-\dfrac{1}{2}\)

b) \(2x^2-\sqrt[]{9x^2-6x+1}=5\)

\(\Leftrightarrow2x^2-\sqrt[]{\left(3x-1\right)^2}=5\)

\(\Leftrightarrow2x^2-\left|3x-1\right|=5\)

\(\Leftrightarrow\left|3x-1\right|=2x^2-5\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-1=2x^2-5\\3x-1=-2x^2+5\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}2x^2-3x-4=0\left(1\right)\\2x^2+3x-6=0\left(2\right)\end{matrix}\right.\)

Giải pt (1)

\(\Delta=9+32=41>0\)

Pt \(\left(1\right)\) \(\Leftrightarrow x=\dfrac{3\pm\sqrt[]{41}}{4}\)

Giải pt (2)

\(\Delta=9+48=57>0\)

Pt \(\left(2\right)\) \(\Leftrightarrow x=\dfrac{-3\pm\sqrt[]{57}}{4}\)

Vậy nghiệm pt là \(\left[{}\begin{matrix}x=\dfrac{3\pm\sqrt[]{41}}{4}\\x=\dfrac{-3\pm\sqrt[]{57}}{4}\end{matrix}\right.\)

1: \(\Leftrightarrow5x^2+4x-1-2x^2+12x-18=3x^2+5x-2-x^2-8x-16+x^2-x\)

\(\Leftrightarrow3x^2+16x-19=3x^2-4x-18\)

=>20x=1

hay x=1/20

2: \(\Leftrightarrow5x^2-20x-41=x^2-10x+25+4x^2+4x+1-\left(x^2-2x\right)+\left(x-1\right)^2\)

\(\Leftrightarrow5x^2-20x-41=4x^2-4x+26+x^2-2x+1\)

\(\Leftrightarrow-20x-41=-6x+27\)

=>-14x=68

hay x=-34/7

a) \(\dfrac{1}{3x-2}-\dfrac{1}{3x+2}-\dfrac{3x-6}{9x^2-4}\)

\(=\dfrac{3x+2-3x+2-3x+6}{\left(3x-2\right)\left(3x+2\right)}\)

\(=\dfrac{-3x+10}{\left(3x-2\right)\left(3x+2\right)}\)

b) \(\dfrac{x+25}{2x^2-50}-\dfrac{x+5}{x^2-5x}-\dfrac{5-x}{2x^2+10x}\)

\(=\dfrac{x+25}{2\left(x-5\right)\left(x+5\right)}-\dfrac{x+5}{x\left(x-5\right)}+\dfrac{x-5}{2x\left(x+5\right)}\)

\(=\dfrac{x^2+25x-2\left(x+5\right)^2+\left(x-5\right)^2}{2x\left(x-5\right)\left(x+5\right)}\)

\(=\dfrac{x^2+25x-2x^2-20x-50+x^2-10x+25}{2x\left(x-5\right)\left(x+5\right)}\)

\(=\dfrac{-5x-25}{2x\left(x-5\right)\left(x+5\right)}\)

\(=\dfrac{-5\left(x+5\right)}{2x\left(x-5\right)\left(x+5\right)}=\dfrac{-5}{2x\left(x-5\right)}\)

c) Ta có: \(\dfrac{1-2x}{2x}-\dfrac{4x}{2x-1}-\dfrac{3}{2x-4x^2}\)

\(=\dfrac{-\left(2x-1\right)^2-8x^2+3}{2x\left(2x-1\right)}\)

\(=\dfrac{-\left(4x^2-4x+1\right)-8x^2+3}{2x\left(2x-1\right)}\)

\(=\dfrac{-4x^2+4x-1-8x^2+3}{2x\left(2x-1\right)}\)

\(=\dfrac{-12x^2+4x+2}{2x\left(2x-1\right)}\)

a/ 2x\(^{^{ }3}\)-3\(^{^{ }3}\)-2x\(^3\)-1\(^{^{ }3}\)=-28

b/x\(^{^{ }3}\)+2\(^{^{ }3}\)-x\(^3\)+2=10

c/3x\(^3\)+5\(^3\)-3x(3x\(^2\)-1)=3x\(^3\)+5\(^3\)-3x\(^3\)+3x=125+3x

d/ x\(^6\)-(x\(^3\)+1)(x\(^2\)-x+1)= x\(^6\)-(x\(^6\)-x\(^4\)+x\(^3\)+x\(^2\)-x+1)=x\(^4\)-x\(^3\)-x\(^2\)+x-1

a) x = 72

b) x = 15

c) x = 34

d) x = 6

e)

f) x =  2 , x =3

g) x=1,x=-3

h)x=3,x=-2

mik chỉ bt giải thế thôi

CHÚC BẠN HỌC TỐT

Bài làm

a) ( x - 15 ) : 3 = 19

x - 15 = 19 . 3

x - 15 = 57

x        = 57 + 15

x        = 72

Vậy x = 72.

b) ( 5x - 45 ) . 15 = 450

5x - 45 = 450 : 15

5x - 45 = 30

5x        = 75

  x        = 15

Vậy x = 15.

c) 187 - 3( x  + 4 ) = 34

              3( x + 4 ) = 187 - 34

              3( x + 4 ) = 153

                  x + 4   = 153 : 3

                  x + 4   = 51

                  x         = 47

Vậy x = 47.

d) 9x - 45 = 3⁷ : 3⁵ 

    9x - 45 = 3²

    9x - 45 = 9

 9( x - 5 ) = 9

      x - 5   = 9 : 9

      x - 5   = 1

      x        = 6

Vậy x = 6.

e ) ( 12x - 4³ ) . 8³ = 4 . 8⁴ 

     ( 12x - 64 )        = 4 . 8⁴ : 8³

        12x - 64          = 4 . 8

        12x - 64          = 32

        12x                  = 96

            x                  = 8

Vậy x = 8.

f ) Đề bài không rõ ràng.

g ) ( x + 1 )² = 4

=> ( x + 1 )² = 2² 

=> x + 1 = 2

=> x = 1

Vậy x = 1.

h ) ( 2x - 1 )² = 25

=> ( 2x - 1 )² = 5² 

=> 2x - 1 = 5

=> 2x = 6

=> x = 3

Vậy x = 3

k ) ( 2x - 1 )⁵ = 243

=> ( 2x - 1 )⁵ = 3⁵

=> 2x - 1 = 3

=> 2x = 4

=> x = 2

Vậy x = 2

# Học tốt #

a) ( x - 15 ) : 3 = 19

    ( x - 15 )      = 19 . 3

      x - 15        = 57

             x        = 57 + 15

             x        = 72

b) ( 5x - 45 ) x 15 = 450

      5x - 45           = 450 : 15

      5x - 45           = 30

      5x                  = 30 + 45

      5x                  = 75

c) 187 - 3( x + 4 ) = 34

             3( x + 4 ) = 187 - 34

             3( x + 4 ) = 153

                 x + 4   = 153 : 3

                 x + 4   = 51

                 x         = 51 - 4

                 x         = 47

d) 9x - 45 = 3⁷ : 3⁵

    9x - 45 = 3²

    9x - 45 = 9

           9x = 9 + 45

           9x = 54

             x = 54 : 9

             x = 6

e) ( 12x - 4³ ) x 8³ = 4 x 8⁴

    ( 12x - 64 ) x 512 = 4 x 4096

    ( 12x - 64 ) x 512 = 16384

      12x - 64             = 16384 : 512

      12x - 64             = 32

      12x                    = 32 + 64

      12x                    = 96

          x                    = 96 : 12

          x                    = 8

f) x² = 4

   x² = 2²

=> x = 2

   x³ = 27

   x³ = 3³

=> x = 3

g) ( x + 1 )² = 4

    ( x + 1 )² = 2²

=> x + 1 = 2

     x        = 2 - 1

     x        = 1

h) ( 2x - 1 )² = 25

    ( 2x - 1 )² = 5²

=> 2x - 1 = 5

     2x       = 5 + 1

     2x       = 6

       x       = 6 : 2

       x       = 3

k) ( 2x - 1 )⁵ = 243

    ( 2x - 1 )⁵ = 3⁵

=> 2x - 1 = 3

     2x       = 3 + 1

     2x       = 4

       x       = 4 : 2

       x       = 2

Chúc bn hok tốt