Question

Tìm x :

1) ( 5x - 1 ) ( x + 1) - 2 ( x - 3 )² = ( x + 2 ) ( 3x - 1 ) - ( x + 4 )² + ( x² - x )

2) ( 3x + 4 ) ( 3x - 4 ) - ( 2x + 5 )² = ( x - 5 )² + ( 2x + 1 )² - ( x² - 2x ) + ( x - 1 )²

3) ( x - 5 ) ( x + 5 ) - ( x - 2 )³ - 7x² + ( x + 1 )( x² - x + 1 ) = ( x + 3 )³ - ( x³ + 9x² )

4) ( x - 6 )( x² + 6x + 36 ) - ( x + 4 )³ = ( x - 2 )³ + ( x + 5 )( x² - 10x + 25 ) - ( 2x³ + 6x² )

5) ( 2x + 3 )³ - ( 2x + 5 )( 4x² - 10x + 25 ) = ( 6x - 1 )² - ( x - 2 )( x² + 2x + 4 ) + x³

CÁC BẠN GIẢI NHANH CHO MÌNH NHA . BẠN NÀO GIẢI CHI TIẾT NHANH , ĐÚNG MÌNH TICK CHO.

Answer 1

1: \(\Leftrightarrow5x^2+4x-1-2x^2+12x-18=3x^2+5x-2-x^2-8x-16+x^2-x\)

\(\Leftrightarrow3x^2+16x-19=3x^2-4x-18\)

=>20x=1

hay x=1/20

2: \(\Leftrightarrow5x^2-20x-41=x^2-10x+25+4x^2+4x+1-\left(x^2-2x\right)+\left(x-1\right)^2\)

\(\Leftrightarrow5x^2-20x-41=4x^2-4x+26+x^2-2x+1\)

\(\Leftrightarrow-20x-41=-6x+27\)

=>-14x=68

hay x=-34/7