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Ánh Ngọc
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Hà Linh
28 tháng 6 2017 lúc 21:16

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

2P=\(24.\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^{16}-1\right)\left(5^{16}+1\right)=5^{32}-1\)

\(P=\dfrac{5^{32}-1}{2}\)

Trần Minh Anh
28 tháng 6 2017 lúc 22:30

P=\(12.\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

2P=24\(\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

2P=\(\left(5^{16}-1\right)\left(5^{16}+1\right)\)

2P=\(3^{32}-1\)

Cheewin
29 tháng 6 2017 lúc 10:28

\(P=\dfrac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow P=\dfrac{1}{2}.\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow P=\dfrac{1}{2}.\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow P=\dfrac{1}{2}.\left(5^{32}-1\right)=\dfrac{5^{13}-1}{2}\)

le van thang
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Không Tên
30 tháng 7 2018 lúc 20:44

\(P=12.\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(=\frac{5^{32}-1}{2}\)

Ayakashi
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MrKakashi
17 tháng 7 2016 lúc 14:00

\(A=\frac{1}{2}\left(5^2-1\right)\) \(\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\) 

A= 1/2(5^4-1)(5^4+1)(5^8+1)(5^16+1)

Làm tương tự còn:

A=1/2(5^16-1)(5^16+1)=1/2(5^32-1)

pham thi thu thao
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Không Tên
3 tháng 7 2018 lúc 16:12

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(=\frac{5^{32}-1}{2}\)

Hoàng Thị Cẩm Hà
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NHỮNG MẢNH GHÉP CẢM XÚC
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Viên đạn bạc
25 tháng 6 2016 lúc 16:22

dặt tổng là P

P= 12.(52+1)(54+1)(58+1)(516+1)

=>2P=24.(52+1)(54+1)(58+1)(516+1)

=(52-1)(52+1)(54+1)(58+1)(516+1)

=(54-1)(58+1)(516+1)

=(58-1)(58+1)(516+1)

=(516-1)(516-1)

=532-1

=>(532-1 ):2

Le Thi Khanh Huyen
25 tháng 6 2016 lúc 16:22

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(2P=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(=5^{32}-1\)

Viên đạn bạc
25 tháng 6 2016 lúc 16:25

đặt tổng là P

P= 12.(52+1)(54+1)(58+1)(516+1)

=>2P=24.(52+1)(54+1)(58+1)(516+1)

=(52-1)(52+1)(54+1)(58+1)(516+1)

=(54-1)(58+1)(516+1)

=(58-1)(58+1)(516+1)

=(516-1)(516-1)

=532-1

=>P=\(\frac{5^{32}-1}{2}\)

Nguyễn Thị Kim Phương
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KWS
24 tháng 8 2018 lúc 14:06

2p=24(5^2+1)(5^4+1)(5^8+1)(5^16+1)
=(5^2-1)(5^2+1)(5^4+1)(5^8+1)(5^16+1)
=(5^4-1)(5^4+1)(5^8+1)(5^16+1)
=(5^8-1)(5^8+1)(5^16+1)
=(5^16-1)(5^16+1)
=5^32-1
~> p=5^32-1/2

Phương Kuro
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Minh Anh
19 tháng 9 2016 lúc 18:02

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^{32}-1\right)\)

Trương Nguyên Hạo
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Võ Đông Anh Tuấn
6 tháng 7 2016 lúc 10:28

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

Ta có : 

\(2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(5^{32}-1\)

\(\Rightarrow P=\frac{5^{32}-1}{2}\)

Nguyễn Thị Anh
6 tháng 7 2016 lúc 10:35

ta có : P=\(12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)=\frac{12\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{\left(5^2-1\right)}\)

=> P=\(\frac{5^{32}-1}{2}\)