So sánh A với \(\frac{1}{3}\)
A = \(\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+....+\frac{1}{40}\)
\(S=\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+\frac{1}{24}+\frac{1}{25}+\frac{1}{26}+\frac{1}{27}+\frac{1}{28}+\frac{1}{29}+\frac{1}{30}\)\(\frac{1}{30}\)
Hãy so sánh S với \(\frac{1}{3}\)
ta có 1/3=10/30
1/21+1/22+...+1/30 có 10 p/số
mà 1/21>1/30
1/22>1/30
....
1/29>1/30
1/30=1/30
=>1/21+..1/30>1/30+....1/30 có 10 phân số
=>1/21+...1/30>1/3
Ta có: \(\frac{1}{21}< \frac{1}{30}\)
\(\frac{1}{22}< \frac{1}{30}\)
......
\(\frac{1}{29}< \frac{1}{30}\)
\(\Rightarrow S< \frac{1}{30}+\frac{1}{30}+...+\frac{1}{30}\)(có 10 p/s)
\(\Rightarrow S< \frac{1}{30}.10=\frac{10}{30}=\frac{1}{3}\)
Vậy S < 1/3
ta co 1/21+1/22+1/23>3/30
1/24+1/25+1/26>3/30
1/27+1/28+1/29>3/30
==>S>3/30+3/30+3/30+1/30
S>10/30 hay S>1/3
\(A=\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+\frac{1}{24}+...+\frac{1}{40}\)
So sánh A và B biết:
\(A=\frac{39}{40}\)
\(B=\frac{1}{21}+\frac{1}{22}+...+\frac{1}{50}\)
B = 1/21 + 1/22 + ... + 1/50 > 1/60 + 1/60 + ... + 1/60 (30 số hạng)
=> B > 30/60 = 1/2
Mà 1/2 > 39/40
=> B > A
\(B=\frac{1}{21}+\frac{1}{22}+...+\frac{1}{50}< \frac{1}{50}+\frac{1}{50}+...+\frac{1}{50}=\frac{3}{5}=\frac{24}{40}< \frac{39}{40}=A\)
\(\Rightarrow A>B\)
B=\(\frac{1}{21}\)+\(\frac{1}{22}\)+ ... +\(\frac{1}{50}\)< \(\frac{1}{50}\)+ \(\frac{1}{50}\)+\(\frac{1}{50}\)+ ... + \(\frac{1}{50}\)= \(\frac{30}{50}\)= \(\frac{3}{5}\)< \(\frac{39}{40}\)= A
hay B < A
Cho biểu thức \(A=\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+\frac{1}{24}+...+\frac{1}{40}\)
Thực hiện so sánh:\(\frac{1}{12}+\frac{1}{13}+\frac{1}{14}+\frac{1}{15}+\frac{1}{16}+\frac{1}{17}\)\(+\frac{1}{18}+\frac{1}{19}+\frac{1}{20}+\frac{1}{21}+\frac{1}{22}\)\(+\frac{1}{23}\)với \(\frac{5}{6}\)
Đặt S=1/12+1/13+1/14+1/15+...+1/23
ta có 1/12+1/13+1/14+1/15+...+1/22+1/23 = (1/12+1/13+1/14+...+1/17)+(1/18+1/19+...+1/23)
đặt A=1/12+1/13+1/14+...+1/17
ta có
1/13<1/12
1/14<1/12
..........................
.........................
1/17<1/12
=>A<1/12+1/12+1/12+....+1/12 (có 6 phân số)
=>A<1x6/12
=>A<1/2 (1)
Đặt B=1/18+1/19+...+11/23
ta có
1/19<1/18
1/20<1/18
...........................
..........................
1/23<1/18
=> B<1/18+1/18+1/18+...+1/18 (có 6 phân số)
=>B<1x 6/18
=>B<1/3 (2)
từ 1 và 2 =>S=A+B<1/2+1/3
=>S<5/6 (dpcm)
k cho mình nhé
Đặt S=1/12+1/13+1/14+1/15+...+1/23
ta có 1/12+1/13+1/14+1/15+...+1/22+1/23 = (1/12+1/13+1/14+...+1/17)+(1/18+1/19+...+1/23)
đặt A=1/12+1/13+1/14+...+1/17
ta có
1/13<1/12
1/14<1/12
..........................
.........................
1/17<1/12
=>A<1/12+1/12+1/12+....+1/12 (có 6 phân số)
=>A<1x6/12
=>A<1/2 (1)
Đặt B=1/18+1/19+...+11/23
ta có
1/19<1/18
1/20<1/18
...........................
..........................
1/23<1/18
=> B<1/18+1/18+1/18+...+1/18 (có 6 phân số)
=>B<1x 6/18
=>B<1/3 (2)
từ 1 và 2 =>S=A+B<1/2+1/3
=>S<5/6 (dpcm)
k cho mình nhé
So sánh K = \(\frac{7}{12}\)
H =\(\frac{1}{21}+\frac{1}{22}+...........+\frac{1}{40}\)
Ta có : 1/21 > 1/30 ; 1/22 > 1/30 ;...; 1/29 > 1/30
=> 1/21 + 1/22 + .. + 1/29 > 1/30 + 1/30 +... + 1/30 (10 số 1/30) = 10/30 = 1/3 (**)
Lại có : 1/31 > 1/40 ; 1/32 > 1/40 ; ...; 1/39 > 1/40
=> 1/31 + 1/32 +... + 1/39 > 1/4 (**)
Đặt A =1/21 +1/22 +1/23 +... + 1/29 +1/31 + ... +1/39
Từ (*) và (**) => A > 1/3 + 1/4 => A > 7/12 (hay A>K)
Mà A<H => H>K
Chứng tỏ rằng :
a) \(\frac{11}{15}<\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+...+\frac{1}{60}<\frac{3}{2}\)
Giúp mik với
Chứng minh:
\(\frac{7}{12}
gọi A=1/21+1/22+1/23+...+1/40
chia A thành 2 nhóm A1 và A2( A1+A2=A)
ta có A1=1/21+1/22+1/23+...+1/30>1/30+1/30+1/30+...+1/30(có 10 phân số 1/30)
A1>10/30=1/3(1)
ta có A2=1/31+1/32+1/33+...+1/40>1/40+1/40+1/40+...+1/40(có 10 phân số 1/40)
A2>10/40=1/4(2)
từ (1)và (2) suy ra
A1+A2>1/3+1/4
A>7/12(3)
ta có A1=1/21+1/22+1/23+...+1/20<1/20+1/20+1/20+...+1/20(có 10 phân số 1/20)
A1<10/20=1/2(4)
ta có A2=1/31+1/32+1/33+...+1/40<1/30+1/30+1/30+...+1/30(có 10 phân số 1/30)
A2<10/30=1/3(5)
từ (4)và (5) suy ra
A1+A2<1/2+1/3
A<5/6(6)
từ (3),(6) suy ra 7/12<1/21+1/22+1/23+...+1/40<5/6
cái A1+1/21+1/22+1/23+1/24+1/25+...+1/30<1/20+1/20+1/20+1/20+...+1/20 nhé
Cho biểu thức:
A = \(\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+\frac{1}{24}+...+\frac{1}{40}\)
Hãy chứng tỏ \(\frac{1}{2}\) < A < 1
\(A=\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+...+\frac{1}{40}>\frac{1}{40}+\frac{1}{40}+\frac{1}{40}+...+\frac{1}{40}=\frac{20}{40}=\frac{1}{2}\)
=>A>\(\frac{1}{2}\) (*)
Ta có:\(A=\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+...+\frac{1}{40}< \frac{1}{20}+\frac{1}{20}+\frac{1}{20}+...+\frac{1}{20}=\frac{20}{20}=1\)
=>A<1 (**)
Từ (*) và (**) => \(\frac{1}{2}< A< 1\)
\(A=\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+\frac{1}{24}+...+\frac{1}{40}>\frac{1}{40}+\frac{1}{40}+\frac{1}{40}+...+\frac{1}{40}\)
20 phân số 1/40
\(A>20x\frac{1}{40}=\frac{1}{2}\)
\(A=\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+\frac{1}{24}+...+\frac{1}{40}< \frac{1}{20}+\frac{1}{20}+\frac{1}{20}+...+\frac{1}{20}\)
20 phân số 1/20
\(A< 20x\frac{1}{20}=1\)
Chứng tỏ 1/2 < A < 1