a,abc.126=15abc

abc.126=15000+abc

abc.125=15000

abc=15000:125

abc=120

b,1abc.2=abc8

(1000+abc).2=10.abc+8

2000+2.abc=10.abc+8

1992=8.abc

abc=1992:8

abc=249

Ta có:

15abc : abc = `101

(15000 +abc) : abc = 101

15000 : abc + abc : abc = 101

15000 : abc + 1 = 101

15000 : abc = 100

abc = 15000 : 100

abc = 150

Vậy số dó là 150

Theo đề ta có :

\(\overline{15abc}:\overline{abc}=101\)

\(\Rightarrow\overline{15abc}=101.\overline{abc}\)

Có : \(\overline{15abc}=10000+5000+100a+10b+c=15000+\overline{abc}\)

\(\Rightarrow15000+\overline{abc}=101.\overline{abc}\)

\(\Rightarrow15000=101.\overline{abc}-\overline{abc}\)

\(\Rightarrow15000=\overline{abc}.\left(101-1\right)\)

\(\Rightarrow15000=\overline{abc}.100\)

\(\Rightarrow\overline{abc}=15000:100=150\)

Tick mik nhé!

À mình bị nhầm đề nha

Làm lại:

Ta có:

\(\overline{15abc}:\overline{abc}=101\)

\(\Rightarrow\left(15000+\overline{abc}\right):\overline{abc}=101\)

\(\Rightarrow15000:\overline{abc}+\overline{abc}:\overline{abc}=101\)

\(\Rightarrow15000:\overline{abc}+\overline{abc}:\overline{abc}=101\)

\(\Rightarrow15000:\overline{abc}+1=101\)

\(\Rightarrow15000:\overline{abc}=100\)

\(\Rightarrow\overline{abc}=150\)

Ta có:

15abc : abc = `101

(15000 +abc) : abc = 101

15000 : abc + abc : abc = 101

15000 : abc + 1 = 101

15000 : abc = 100

abc = 15000 : 100

abc = 150

Vậy số dó là 150

https://hoc24.vn/hoi-dap/question/425092.html

\(15abc:abc=121\)

\(\left(15000+abc\right):abc=121\)

\(15000:abc+abc:abc=121\)

\(15000:abc+1=121\)

\(15000:abc=120\)

\(abc=15000:120\)

\(abc=125\)

125

125

125

abc = 120

\(\overline{abc}\times126=\overline{15abc}\)

\(\Leftrightarrow\overline{abc}\times126=15000+\overline{abc}\)

\(\Leftrightarrow\overline{abc}\times\left(126-1\right)=15000\)

\(\Leftrightarrow\overline{abc}\times125=15000\)

\(\Rightarrow\overline{abc}=15000\div125=120\)

Hiệu của 2 số đã cho là:

               15abc - abc = 15000 

Số abc là:

               15000 : (126 - 1) = 120

                         Đáp số: 120

Viết sai 1 dấu, làm lại :

Ta có:
 abc x 126 = 15abc
 => (a.100+b.10+c) .126 = 15(a.100+b.10+c)
 => (a.100+b.10+c) .126 = 15000+ a.100 + b.10 + c
 => (a.100+b.10+c).126 - (a.100 + b.10 + c) = 15000
 => (a.100+b.10+c).(126 - 1) = 15000
 => (a.100+b.10+c). 125 = 15000 
 => abc=15000 : 125
 => abc=120
                            Vậy abc là 120

Ta có:
 abc x 126 = 15abc
 (a.100+b.10+c) .126 = 15(a.100+b.10+c)
 (a.100+b.10+c) .126 = 15000+ a.100 + b.10 + c
 (a.100+b.10+c).126 - (a.100 + b.10 + c) = 15000
 =(a.100+b.10+c).(126 - 1) = 15000
 (a.100+b.10+c). 125 = 15000 
 abc=15000 : 125
 abc=120
                            Vậy abc là 120

Móng tay nhọn có bật móng tay

a) abcabc + abc = 321642 

abc x 1001 + abc = 321321 + 321

-> abc = 321

b) 30abc : abc= 241

abc =125

c)15abc0 : abc =1010

abc = 150

d) 15abc : abc = 121

abc = 125

a) abcabc + abc = 321642

abc x 1001 + abc = 321321 + 321

=> abc = 321

b) 30abc : abc = 241

abc = 125

c) 15abc0 : abc = 1010

abc = 150

d) 15abc : abc = 121

abc = 125