Lỗi hình ảnh rồi nha

mất ảnh gòi bn ơi :^

a, \(\sqrt{x^2-6x+9}=2\)

\(\Leftrightarrow\sqrt{\left(x-3\right)^2}=2\)

\(\Leftrightarrow\left|x-3\right|=2\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=2\\x-3=-2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=1\end{matrix}\right.\)

a: Ta có: \(\sqrt{x^2-6x+9}=2\)

\(\Leftrightarrow\left(x-5\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=1\end{matrix}\right.\)

Bài 1: 

1: 

a: \(\sqrt{12}+3\sqrt{48}-5\sqrt{75}\)

\(=2\sqrt{3}+12\sqrt{3}-25\sqrt{3}\)

\(=-11\sqrt{3}\)