tính nhanh
60\(\frac{7}{13}x\)+50\(\frac{8}{13}x\)- 11\(\frac{2}{13}x\)với x= -8\(\frac{7}{10}\)
Những câu hỏi liên quan
Tính giá trị của các biểu thức sau bằng cách hợp lý nhất :
a)\(\left(4\frac{5}{37}-3\frac{4}{5}+8\frac{15}{29}\right)-\left(3\frac{5}{37}-6\frac{14}{29}\right)\)
b)\(60\frac{7}{13}x+50\frac{8}{13}x-11\frac{2}{13}x\)với \(x=-8\frac{7}{10}\)
Tinh
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\(60\frac{7}{13}x+50\frac{8}{13}x-11\frac{2}{13}x\) voi \(x=-8\frac{7}{10}\)
\(60\frac{7}{13}x+50\frac{8}{13}x-11\frac{2}{13}x=x.\left(60\frac{7}{13}+50\frac{8}{13}-11\frac{2}{13}\right)\)
\(=x.\left(60+\frac{7}{13}+50+\frac{8}{13}-11-\frac{2}{13}\right)\)
\(=-8\frac{1}{7}.\left(99+1\right)\)
\(=\frac{-57}{7}.100=\frac{-5700}{7}\)
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1. Tìm x:
a;\(\frac{x+1}{3}=\frac{x-2}{4}\)
b;\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
c;\(\frac{x+3}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
a) \(\frac{x+1}{3}=\frac{x-2}{4}\)
=> (x+1).4 = (x - 2) . 3
=> 4x + 4 = 3x - 6
=> 4x - 3x = - 6 - 4
=> x = - 10
b) \(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
\(\Rightarrow\left(\frac{x-6}{7}+1\right)+\left(\frac{x-7}{8}+1\right)+\left(\frac{x-8}{9}+1\right)=\left(\frac{x-9}{10}+1\right)+\left(\frac{x-10}{11}+1\right)+\left(\frac{x-11}{12}+1\right)\)
\(\Rightarrow\frac{x+1}{7}+\frac{x+1}{8}+\frac{x+1}{9}=\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}\)
\(\Rightarrow\frac{x+1}{7}+\frac{x+1}{8}+\frac{x+1}{9}-\frac{x+1}{10}-\frac{x+1}{11}-\frac{x+1}{12}\) = 0
\(\Rightarrow\left(x+1\right).\left(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\right)\)
Vì \(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\ne0\) nên x + 1 =0
=> x = -1
c) Xem lại đề
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Tìm x, biết: \(\frac{x+2}{17}+\frac{x+4}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}+\frac{x+12}{7}\)
(x+2)/17+(x+4)/15+(x+6)/13=(x+8)/11+(x+10)/9+(x+12)/7
=>(x+2+17)/17+(x+4+15)/15+(x+6+13)/13=(x+8+11)/11+(x+10+9)/9+(x+12+7)/7
=>(x+19)/17+(x+19)/15+(x+19)/13=(x+19)/11+(x+19)/9+(x+19)/7
=>(x+19)/17+(x+19)/15+(x+19)/13-(x+19)/11-(x+19)/9-(x+19)/7=0
=>(x+19)*(1/17+1/15+1/13-1/11-1/9-1/7)=0
=>x+19=0
=>x=19
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áp dụng tc tỉ lệ thức ta có :
\(\Leftrightarrow\frac{671x+2804}{3315}=\frac{239x+2462}{693}\Rightarrow\left(671x+2804\right)693=3315\left(239x+2462\right)\)
=>(671x+2804)693=693(671x+2804) (VT)
<=>693(671x+2804)=3315(239x+2462)
=>465003x+1943172=792285x+8161530
=>-327282x=621835
=>x=621835:(-327282)
=>x=-19
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tìm biết :
\(\frac{x+2}{17}+\frac{x+14}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}\frac{x+12}{7}\)
vế trái có bị sai ko em. chị nghĩ câu hỏi nên là: x+2/17 + x+4/15 + x+6/13=x+8/11 + x+10/9 + x+12/7
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Đúng ghi Đ, sai ghi S vào chỗ chấm:a) frac{3}{7}+frac{1}{3}xfrac{3}{7}frac{16}{21}xfrac{3}{7}frac{16}{49} ......b)frac{5}{9}+frac{1}{5}xfrac{5}{6}frac{5}{9}xfrac{1}{6}frac{13}{18} ......c)frac{13}{9}-frac{7}{9}:frac{2}{3}frac{6}{9}:frac{3}{2}1 ......d)frac{11}{8}-frac{5}{8}:frac{3}{4}frac{11}{8}-frac{5}{8}xfrac{4}{3}frac{11}{8}-frac{10}{24}frac{23}{24} ......
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Đúng ghi Đ, sai ghi S vào chỗ chấm:
a) \(\frac{3}{7}+\frac{1}{3}x\frac{3}{7}=\frac{16}{21}x\frac{3}{7}=\frac{16}{49}\) ......
b)\(\frac{5}{9}+\frac{1}{5}x\frac{5}{6}=\frac{5}{9}x\frac{1}{6}=\frac{13}{18}\) ......
c)\(\frac{13}{9}-\frac{7}{9}:\frac{2}{3}=\frac{6}{9}:\frac{3}{2}=1\) ......
d)\(\frac{11}{8}-\frac{5}{8}:\frac{3}{4}=\frac{11}{8}-\frac{5}{8}x\frac{4}{3}=\frac{11}{8}-\frac{10}{24}=\frac{23}{24}\) ......
Mai Hồng Ngọc? Vũ Thị Thu Hằng? Ai đúng dzậy -_-*
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Xem thêm câu trả lời
Bài 1: A= \(\frac{1}{3}-\frac{3}{5}+\frac{5}{7}-\frac{7}{9}+\frac{9}{11}-\frac{11}{13}+\frac{13}{15}+\frac{11}{13}-\frac{9}{11}+\frac{7}{8}-\frac{5}{7}+\frac{3}{5}-\frac{1}{3}\)
Bài 2:Tìm x , 3x.\(\left(x-\frac{2}{3}\right)=0\)
\(3x.\left(x-\frac{2}{3}\right)=0\)
\(\Leftrightarrow3x=0\)hoặc \(x-\frac{2}{3}=0\)
\(3x=0\Rightarrow x=0\)
\(x-\frac{2}{3}=0\Rightarrow x=0+\frac{2}{3}=\frac{2}{3}\)
Vậy..
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a, left(12-frac{7}{18}-10frac{13}{18}right):x-1frac{7}{13}1frac{2}{3}
b,left[left(6frac{3}{7}-frac{0,75x-2}{0,35}right).2,8+1,75right]:0,05235
c.frac{3-x}{5-x}left(frac{3}{5}right)^2
d,left(1-frac{3}{10}-xright):left(frac{19}{10}-1-frac{2}{5}right)+frac{4}{5}1
e,left(12frac{7}{18}-10frac{13}{18}right):x-1frac{7}{33}:frac{8}{11}1frac{2}{3}
các bạn ơi giúp tớ với
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a, \(\left(12-\frac{7}{18}-10\frac{13}{18}\right):x-1\frac{7}{13}=1\frac{2}{3}\)
b,\(\left[\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right).2,8+1,75\right]:0,05=235\)
c.\(\frac{3-x}{5-x}=\left(\frac{3}{5}\right)^2\)
d,\(\left(1-\frac{3}{10}-x\right):\left(\frac{19}{10}-1-\frac{2}{5}\right)+\frac{4}{5}=1\)
e,\(\left(12\frac{7}{18}-10\frac{13}{18}\right):x-1\frac{7}{33}:\frac{8}{11}=1\frac{2}{3}\)
các bạn ơi giúp tớ với
Tính a) (4 frac{5}{37}- 3frac{4}{5}+8frac{15}{29}) - (3frac{5}{37}- 6frac{14}{29}b) 60 frac{7}{13}x (8frac{7}{10}) +50frac{8}{13}x (-8 frac{7}{10}) - 11 frac{2}{13}x (-8 frac{7}{10}c) (2 frac{5}{6}+ 1frac{4}{9}) : ( 10 frac{1}{2}- 9 frac{1}{2}d) 1 frac{5}{18}- frac{5}{18}x (frac{1}{15}+1frac{1}{12})e)frac{-1}{7}x (9 frac{1}{2} - 8,75) :frac{2}{7} +0,625 :1 frac{2}{3}
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Tính a) (4 \(\frac{5}{37}\)- 3\(\frac{4}{5}\)+8\(\frac{15}{29}\)) - (3\(\frac{5}{37}\)- 6\(\frac{14}{29}\)
b) 60 \(\frac{7}{13}\)x (8\(\frac{7}{10}\)) +50\(\frac{8}{13}\)x (-8 \(\frac{7}{10}\)) - 11 \(\frac{2}{13}\)x (-8 \(\frac{7}{10}\)
c) (2 \(\frac{5}{6}\)+ 1\(\frac{4}{9}\)) : ( 10 \(\frac{1}{2}\)- 9 \(\frac{1}{2}\)
d) 1 \(\frac{5}{18}\)- \(\frac{5}{18}\)x (\(\frac{1}{15}\)+1\(\frac{1}{12}\))
e)\(\frac{-1}{7}\)x (9 \(\frac{1}{2}\) - 8,75) :\(\frac{2}{7}\) +0,625 :1 \(\frac{2}{3}\)