mình nghi thiếu dấu cộng sorry các bạn

\(c=2^3.5^3-\left\{7^2.2^3-5^2.\left[4^3::8+11^2:121-2\left(37-5.7\right)\right]\right\}\)

\(c=8.5-\left\{49.8-25.\left[8:8+121:121-2\left(37-5.7\right)\right]\right\}\)

\(c=8.5-\left\{49.8-25.\left[8:8+121:121-2\left(37-35\right)\right]\right\}\)

\(c=8.5-\left\{49.8-25.\left[8:8+121:121+2.2\right]\right\}\)

\(c=8.5-\left\{1+1+2.2\right\}\)

\(c=8.5-\left\{1+1+4\right\}\)

\(c=8.5-6\)

\(c=40-6\)

\(c=34\)

nhầm

\(c=2^3.5^3-\left\{7^2.2^3-5^2.\left[4^3:8+11^2:121-2\left(37-5.7\right)\right]\right\}\)

\(c=8.125-\left\{49.8-25.\left[8:8+121:121-2\left(37-35\right)\right]\right\}\)

\(c=8.125-\left\{49.8-25.\left[8:8+121:121-2.2\right]\right\}\)

\(c=8.125-\left\{49.8-25.\left[1+1-2.2\right]\right\}\)

\(c=8.125-\left\{49.8-25.\left[1+1-4\right]\right\}\)

\(c=8.125-\left\{49.8-25.-2\right\}\)

\(c=8.125-\left\{392+50\right\}\)

\(c=8.125-442\)

\(c=1000-442\)

\(c=558\)

Có \(A=2+2^2+2^3+...+2^{60}\)

\(\Rightarrow A=2\left(1+2+...+2^{59}\right)⋮2\)(1)

Lại có : \(A=2+2^2+2^3+...+2^{60}\)

\(A=\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{59}+2^{60}\right)\)

\(A=2\left(1+2\right)+2^3\left(1+2\right)+...+2^{59}\left(1+2\right)\)

\(A=3\left(2+2^3+...+2^{59}\right)⋮3\)(2)

Lại có :\(A=2+2^2+2^3+...+2^{60}\)

\(\Rightarrow A=\left(2+2^2+2^3\right)+...+\left(2^{58}+2^{59}+2^{60}\right)\)

\(A=2\left(1+2+2^2\right)+...+2^{58}\left(1+2+2^2\right)\)

\(A=7\left(2+...+2^{58}\right)⋮7\)(3)

Từ (1) và (3) \(\Rightarrow A⋮\left(2.7\right)=14\)(4)

Từ(1);(2);(3);(4) \(\Rightarrow A⋮2;3;7;14\)

Đề bài có phải là như vậy ko bạn:

5^x-2 - 3²= 2⁴- (6⁸ : 6⁶ - 6²) ( x^2-1)⁴ =81

( 3^x+4 )² = 19⁶ : ( 19³ x 19² ) - 3^{1x 2005}

Bạn xem hộ mik như vậy có đúng đề ko, đúng thì mik làm cho nhé!