B = 4^9.36+64^4
       16^4.100
B = 2^20.(9+16)
       2^18.5^2
B = 2^20.5^2
      2^18.5^2
B = 2^2
B = 4

D = 4^6.3^4.9^5
           6^12
D = 2^12.3^4.9^5
        2^12.3^12
D = 2^12.3^14
       2^12.3^12
D = 3^2
D = 9

\(\frac{4^9.36+64^4}{16^4.100}=\frac{4^{10}\left(9+8\right)}{4^{10}.25}=\frac{17}{25}\)

cảm ưn các bn nhìu

giup mình với mình cần gấp lắm ai giải nhanh mình cho

a, \(B=\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)

\(=\dfrac{2^{10}.\left(13+65\right)}{2^8.2^3.13}\)

\(=\dfrac{2^{10}.78}{2^{11}.13}\)\(=\dfrac{1.6}{2.1}=\dfrac{1.3}{1.1}=3\)

b: \(=\dfrac{2^{20}\cdot3^2+2^{54}}{2^{18}\cdot5^2}=\dfrac{2^{20}\left(3^2+2^{32}\right)}{2^{18}\cdot5^2}=\dfrac{2^2\left(3^2+2^{32}\right)}{25}\)

c: \(=\dfrac{2^9\cdot3^6\cdot3^6\cdot2^2}{2^8\cdot3^{12}}=\dfrac{2^{11}}{2^8}=8\)

d: \(=\dfrac{2^{12}\cdot3^4\cdot3^{10}}{2^{12}\cdot3^{12}}=9\)

Ta có : \(C=\dfrac{4^6.3^4.9^5}{6^{12}}=\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}=\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=3^{4+10-12}=3^2=9\)

\(C=\dfrac{4^6\cdot3^4\cdot9^5}{6^{12}}=\dfrac{2^{12}\cdot3^4\cdot3^{10}}{3^{12}\cdot2^{12}}=3^2=9\)

\(C=\dfrac{4^6.3^4.9^5}{6^{12}}\) 

\(C=\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}\) 

\(C=\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}\) 

\(C=\dfrac{2^{12}.3^{14}}{2^{12}.3^{12}}\) 

\(C=3^2=9\)

mấy bn lm giúp mk nha , mk tk cho 3 tk