-1 . \(\dfrac{5}{27}\) - \(\left(3x.\dfrac{7}{9^{ }}\right)^3\) = -\(\dfrac{24}{27}\)

\(\Rightarrow\) \(\dfrac{-5}{27}\) - \(\left(3x.\dfrac{7}{9^{ }}\right)^3\) = \(\dfrac{-24}{27}\)

\(\Rightarrow\) \(\left(3x.\dfrac{7}{9^{ }}\right)^3\) = \(\dfrac{-5}{27}\) - \(\dfrac{-24}{27}\) = \(\dfrac{19}{27}\)

\(\Rightarrow\) \(3^3\) . \(\dfrac{7^3}{3^6}\) = \(\dfrac{19}{3^3}\)

\(\Rightarrow\) \(\dfrac{x^3.7^3}{3^3}\) = \(\dfrac{19}{3^3}\)

\(\Rightarrow\) \(x^3\) . \(7^3\) = 19

135

-135

135

-135

27(-5)=-135

(+27)(+5)=135

(-27)(+5)=-135

(-27)(-5)=135

(+5)(-27)=-135

27.(-5)=-135

=>(+27.(+5)=135

=>(-27).(+5)=-135

=>(-27).(-5)=135

=>(+5).(-27)=-135

`1   5/27 + 7 /23 + 1/2 - 5/27 + 16/23`

` = 32/27 + 7/23 + 1/2 - 5/27 + 16/23 `

`= (32/27 - 5/27 ) + (7/23 + 16/23 ) + 1/2 `

`= 27/27 + 23/23 + 1/2 `

`= 1 + 1 + 1/2 `

`= 5/2`

` 6 1/5 - ( 2/3 . 9/10 - 7/5 )`

` = 31/5 - 2/3 . 9/10 + 7/5 `

`= ( 31/5 + 7/5 ) - ( 2/3 . 9/10 ) `

`= 38/5 - 3/5 `

`= 35/5`

`= 7`

`@ animephamdanhv.`

\(\frac{12}{27}+\frac{5}{8}+\frac{2}{5}+\frac{15}{27}+\frac{3}{5}+\frac{3}{8}\)

\(=\left(\frac{12}{27}+\frac{15}{27}\right)+\left(\frac{5}{8}+\frac{3}{8}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\)

\(=1+1+1\)

\(=3\)

(12/27+15/27)+(5/8+3/8)+3/5

=1+1+3/5

=2+3/5

=13/5

chúc em học tốt

      \(\frac{12}{27}+\frac{5}{8}+\frac{2}{5}+\frac{15}{27}+\frac{3}{5}+\frac{3}{8}\)

\(=\left(\frac{12}{27}+\frac{15}{27}\right)+\left(\frac{5}{8}+\frac{3}{8}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\)

\(=1+1+1\)

\(=3\)

(27 + 29) + (86 - 84) + 5

= 56 + 2 + 5

= 63

Chúc bạn học tốt!! ^^

\(\hept{\begin{cases}\\\end{cases}\sqrt[]{}\hept{\begin{cases}\\\end{cases}}\hept{\begin{cases}\\\\\end{cases}}\widebat{ }\phi\sqrt[]{}\sqrt[]{}\sqrt[]{}\sqrt[]{}\sqrt[]{}\sqrt[]{}}\)

kết quả =63 nhé

chúc bạn học tốt

cả hai

-2 có thể ghi bằng (-2)

Cả hai đều được nhé bạn

\(400^n+256^n-9^n-1\)

Theo hằng đẳng thức 8 và 9

\(\Rightarrow400^n+256^n-9^n-1^n⋮\left(400+256-9-1\right)=646\)

Mà \(646⋮323\Rightarrow\left(đpcm\right)\)