1, ( 37 . 13 - 13 . 1 ) : ( 24 + 37 . 12 )

    [ 13 . ( 37 - 1 ) ] : ( 12 . 2 + 37 . 12 )

    ( 13 . 36 ) : [ 12 ( 2 + 37 ) ]

   ( 13 . 36 ) : ( 12 . 36 )

    36

chắc z ^^ 

lm bừa ko cần mt

chac dung do 

bạn michial làm sai rồi phải biến đổi số bị chia để được số chia và đáp số là 1

1 ) 1996.1037 - 1996.37

= 1996.( 1037 - 37 )

= 1996.1000

= 1996000

2 ) ( 260 - 13 ) : 13

= 247 : 13

= 19

3 ) ( 23.35 + 35.37 ) : 60

= 35.( 23 + 37 ) : 60

= 35.60 : 60

= 2100 : 60

= 35

Đáp số : 1 ) 1996000

2 ) 19

3 ) 35
 

a) Ta có: \(37^2+2\cdot37\cdot13+13^2\)

\(=\left(37+13\right)^2=50^2=2500\)

b) Ta có: \(201^2=\left(200+1\right)^2\)

\(=200^2+2\cdot200+1\)

\(=40000+200+1=40201\)

c) Ta có: \(37\cdot43=\left(40+3\right)\cdot\left(40-3\right)\)

\(=40^2-3^2=1600-9=1591\)

Ta có: \(B=\dfrac{11}{13}\cdot\dfrac{40}{13}+\dfrac{37}{5}:\dfrac{7}{33}-\left(\dfrac{11}{13}+\dfrac{33}{7}:\dfrac{5}{2}\right)\)

\(=\dfrac{440}{169}+\dfrac{37}{5}\cdot\dfrac{33}{7}-\dfrac{11}{13}-\dfrac{33}{7}\cdot\dfrac{2}{5}\)

\(=\dfrac{297}{169}+\dfrac{33}{7}\cdot\left(\dfrac{37}{5}-\dfrac{2}{5}\right)\)

\(=\dfrac{297}{169}+\dfrac{33}{7}\cdot7\)

\(=\dfrac{297}{169}+33=\dfrac{5874}{169}\)

\(37^2+2\times37+13^2.\)

\(=37\times37+2\times37+13^2\)

\(=37\times\left(37+2\right)+13^2\)

\(=37\times39+13^2\)

\(=37\times39+169\)

\(=1443+169=1612\)

\(37^2+2.37.13+13^2=\left(37+13\right)^2=2500\)

\(37^2+2.37.13+13^2\) ( áp dụng Hằng đẳng thứ thứ nhất )

\(=\left(37+13\right)^2=50^2=2500\)

P/s xong rồi easy

Sửa đề : \(-\dfrac{19}{37}=\dfrac{19}{37}\)

\(\dfrac{19}{37}-\dfrac{31}{24}-\dfrac{19}{37}+1\dfrac{7}{24}-\dfrac{2}{13}\)

\(=\dfrac{19}{37}-\dfrac{31}{24}+\dfrac{19}{37}+\dfrac{31}{24}-\dfrac{2}{13}\)

\(=\left(\dfrac{19}{37}-\dfrac{19}{37}\right)+\left(-\dfrac{31}{24}+\dfrac{31}{24}\right)-\dfrac{2}{13}=-\dfrac{2}{13}\)

Sửa đề: \(\dfrac{19}{37}-\dfrac{31}{24}+\dfrac{-19}{37}+1\dfrac{7}{24}-\dfrac{2}{13}\)

Ta có: \(\dfrac{19}{37}-\dfrac{31}{24}+\dfrac{-19}{37}+1\dfrac{7}{24}-\dfrac{2}{13}\)

\(=\left(\dfrac{19}{37}+\dfrac{-19}{37}\right)+\left(\dfrac{-31}{24}+1+\dfrac{7}{24}\right)-\dfrac{2}{13}\)

\(=\dfrac{-2}{13}\)

\(\dfrac{19}{37}-\dfrac{31}{24}-\dfrac{-19}{37}+1\dfrac{7}{24}-\dfrac{2}{13}=\dfrac{19}{37}-\dfrac{31}{24}+\dfrac{19}{37}+\dfrac{31}{24}-\dfrac{2}{13}=\left(\dfrac{19}{37}+\dfrac{19}{37}\right)+\left(\dfrac{-31}{24}+\dfrac{31}{24}\right)-\dfrac{2}{13}=\dfrac{38}{31}+0-\dfrac{2}{13}=\dfrac{122}{403}\)

\(8697-\left[3^7:3^5+2\left(13-3\right)\right]=8697-\left(3^2+2.10\right)=8697-\left(9+20\right)=8697-29=8668\)

8697-\([\)(3⁷:3⁵+2(13-3)\(]\)=8697-\([\)3²+2x10\(]\)=8697-29=8668