[4.(2.x-50 12]:2=16
a.(x+50):4=32
b.(4x - 16) : 2 - 12 =4000
a: =>x+50=9/4
hay x=-47,75
b: =>4x-16=(4000+12)x2=8024
=>4x=8040
hay x=2010
a) \(\left(x+50\right):4=3^2\)
\(x+50:4=9\)
\(x+50=4.9\)
\(x+50=36\)
\(x=36-50\)
\(x=-14\)
b) \(\left(4x-16\right):2-\left(-12\right)=4000\)
\(4x-16:2-12.2=4000\)
\(4x-16:2-24=4000\)
\(4x-\left(16+24\right);2=4000\)
\(4x-30:2=4000\)
\(4x-30=4000.2\)
\(4x-30=8000\)
Tìm x: (2x+1/2)*(3/4-x)=0
Tính nhanh: 2/10*12+2/12*14+2/14*16+...+2/48*50
( 2x + 1 / 2 ) * ( 3 / 4 - x ) = 0
=> 2x + 1 / 2 = 0 hoặc 3 / 4 - x = 0
2x = - 1 / 2 x = 3 / 4
x = - 1 / 4
Vậy x = -1 / 4 hoặc x = 3 / 4
2 / 10 * 12 + 2 / 12 * 14 + 2 / 14 * 16 + ... + 2 / 48 * 50
= 1 / 10 - 1 / 12 + 1 / 12 - 1 / 14 + 1 / 14 + 1 / 16 + .... + 1 / 48 - 1/ 50
= 1 / 10 - 1 / 50
= 2 / 25
Tìm x : \(\left(2x+\frac{1}{2}\right)\left(\frac{3}{4}-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x+\frac{1}{2}=0\\\frac{3}{4}-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{3}{4}\end{cases}}}\)
Tính nhanh : \(\frac{2}{10.12}+\frac{2}{12.14}+...+\frac{2}{48.50}\)
\(=2\left(\frac{1}{10.12}+\frac{1}{12.14}+...+\frac{1}{48.50}\right)\)
\(=2.\frac{1}{2}\left(\frac{1}{10}-\frac{1}{12}+\frac{1}{12}-\frac{1}{14}+...+\frac{1}{48}-\frac{1}{50}\right)\)
\(=\frac{1}{10}-\frac{1}{50}\)
\(=\frac{2}{25}\)
Tính
a) 12 : 3/4 + 75% x 1/2 - 16 x 50% b) 75% x 4 + 22,5 : 3 - 1,3/5
1,3/5 là hỗn số
a: \(12:\dfrac{3}{4}+75\%\cdot\dfrac{1}{2}-16\cdot50\%\)
\(=12\cdot\dfrac{4}{3}+\dfrac{3}{4}\cdot\dfrac{1}{2}-16\cdot0,5\)
\(=16-8+\dfrac{3}{8}\)
\(=8,375\)
b: \(75\%\cdot4+22,5:3-1\dfrac{3}{5}\)
\(=0,75\cdot4+7,5-1,6\)
\(=3+7,5-1,6\)
=10,5-1,6
=8,9
-4(5-x)=-3(6-x)
-3(x-8)-(2x-7)=35
2. Tính tổng
1+(-2)+3+(-4)+...+49+(-50)
1-2+3-4+...+99-100
2-4+6-8+...+49-50
Tính hợp lý
24(16-5)-16(24-5)
29-(19-13)-19(29*13)
31*(-18)+31*(-81)-31
(-12)*47+(-12)*52+(-12)
13(23+22)-3(17+28)
1.Phân tích đa thức thành nhân tử
a)(4x^2-7x-50)^2-16x^4-56x^3-49x^2
b)(x^2+y^2-5)^2-4.x^2.y^2-16xy-16
c)x^4+x^3+3x^2+2x+12
1/2×(2×x-3)+105/2=-137/2 A,-12×25-25×75-25×13 B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5 C,-354+265-156+125 D,-74+40-50+16-35 E,-2/3×4/5+-4/5×4/3-0,125
1/2×(2×x-3)+105/2=-137/2
1/2×(2×x-3)=-137/2-105/2
1/2×(2×x-3)=-242/2
2×x-3=-242/2:1/2
2×x-3=-242
2.x=(-242)+3
2.x=239
x=239:2
x=239/2
A,-12×25-25×75-25×13
=[(-12)-75-13].25
=(-100).25
-2500
B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5
=(-35)-(-25)+(-13)
=-23
C,-354+265-156+125
=[(-354)-156]+(265+125)
=(-510)+277
=-233
D,-74+40-50+16-35
=(-74)+40+(-50)+16+(-35)
=[(-74)+(-35)]+[40+(-50)+16]
=(-109)+26
=-83
E,-2/3×4/5+-4/5×4/3-0,125
=-2/3.4/5+4/5.(-4/3)-0,125
=4/5.[-2/3+(-4/3)]-0,125
=4/5.(-2)-0,125
=-8/5-0,125
=(-1,6)+(-0,125)
=-1,725
Bài 13. Viết kết quả phép tính sau dưới dạng một lũy thừa
a)
5 4
x .x .x b)
4 4 4 .5 c)
6 4 2 8 a .a .b .b d)
2 5 9 .3 e)
5 3 2 4 .16 .64
f)
20 19 7 :7 g)
25 12 14 5 .5 : 25 h)
16 12 4 4 : 2 .2 i)
20 50 64 : 2
các bn ơi giúp mk với mai mk đi hc rùi
47 . ( 23 + 50 ) -23 . ( 47 + 50 )
(- 33 ) . ( - 5 ) - 33 . 4 + 33
25 . 99 + | -25 | . 99 -99 . ( -37 ) + | -13 | . 99
bài tìm x
2 . ( x - 5 ) = -12
x mũ 3 -1 =26
2 . ( x -5 ) - 3 . ( x + 7 ) =14
-7 . ( 5 - x ) - 2 . ( x - 10 ) = 15
8 . ( x - | -7 | ) - 6 . ( x- 2 ) = | -8 | . 6 - 50
12 . ( x - 4 ) + 6 . ( x- 2 ) - 16 . ( x+ 3 ) = 7 . | - 4 |
47. (23 + 50)- 23. ( 47+50 )
= 47. 23+ 47. 50- 23. 47 - 23. 50
=47. 50 - 23. 50
= 50 .( 47 -23)
=50. 24 = 1200
(-33 ). (-5) - 33 . 4 + 33
= 33 ( 5 - 4 + 1)
=33 . 2 = 66
giup minh voi
3 | + | 3 | + … + | 3 | = | |
1 x 4 | 4 x 7 | 262 x 265 |
|
1. Tính nhanh nếu có thể :
a) (-25) . (-35) . (-4)
b) 16 - 50 : 5
c) 180 - 80 : (-5) - 12 . (-3)
d) 250 - 200 : [2000 . (12-15)2 + (-2)3]
2. Tìm x, biết :
a) 60 + 2 . (12-x) = - 48
3.
Cho A = 71 + 72 + 73+74+75+76+...+716+717+718.
Chứng tỏ :
a) A \(⋮\) 8
b) A\(⋮\) 57
c) A\(⋮\) 50
d) A \(⋮\) 57
Bài 1:
a. $=(-25)(-4)(-35)=100(-35)=-3500$
b. $=16-10=6$
c. $=180-(-16)-(-36)=180+16+36=232$
d. $=250-200:[1(-3)^2+(-8)]$
$=250-200:(9-8)=250-200=50$
2.
$60+2(12-x)=-48$
$2(12-x)=60-(-48)=60+48=108$
$12-x=108:2=54$
$x=12-54=-42$
Bài 3:
$A=(7+7^2)+(7^3+7^4)+....+(7^{17}+7^{18})$
$=7(1+7)+7^3(7+1)+...+7^{17}(1+7)$
$=(1+7)(7+7^3+....+7^{17})=8(7+7^3+....+7^{17})\vdots 8$
b.
$A=(7+7^2+7^3)+(7^4+7^5+7^6)+...+(7^{16}+7^{17}+7^{18})$
$=7(1+7+7^2)+7^4(1+7+7^2)+....+7^{16}(1+7+7^2)$
$=(1+7+7^2)(7+7^4+....+7^{16})$
$=57(7+7^4+...+7^{16})\vdots 57$
c.
$A=(7+7^2+7^3+7^4)+(7^5+7^6+7^7+7^8)+(7^9+7^{10}+7^{11}+7^{12})+(7^{13}+7^{14}+7^{15}+7^{16})+(7^{17}+7^{18})$
$=7(1+7+7^2+7^3)+7^5(1+7+7^2+7^3)+7^9(1+7+7^2+7^3(+7^{13}(1+7+7^2+7^3)+7^{17}(1+7)$
$=(1+7+7^2+7^3)(7+7^5+7^9+7^{13})+8.7^{17}$
$=400(7+7^5+7^9+7^{13})+8.7^{17}$
Ta thấy $400(7+7^5+7^9+7^{13})\vdots 50$ nhưng $8.7^{17}\not\vdots 50$ nên $A\not\vdots 50$