tim x thuocZ :-150(1352-41) / (1352-41)(150-15) < x < (2400:48)-250 / 350-(3600-12)
Những câu hỏi liên quan
\(\frac{-150.\left(1352-41\right)}{\left(1352-41\right).\left(150-15\right)}< x< \frac{\left(2400:48\right)-250}{350-\left(3600:12\right)}\)
\(\frac{-150.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}< x< \frac{2400:48-250}{350-3600:12}\)
tìm x thuộc Z
a, -150(1352-41) / (1352-41)(150-15) <x< (2400:48)-250 / 350 - (3600:12)
b, 10,07 - [ 3,927 - ( 3,63 - 3/20) ] < hoặc bằng x < hoặc bằng 1,5. (9,2-2/5) + (3,2-3,12) (41/10 -2,85 )
Đề là gì vậy bạn, x còn thêm điều kiện gì không như x ∈ Z,...v.v.
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Tìm số nguyên x biết:a)frac{-150left(1352-41right)}{left(1352-41right)left(50-45right)}xfrac{left(2400:48right)-250}{350-left(3600:12right)}b)10,07-[3,927-(3,63-frac{3}{20})lexle1,5 left(9,2-frac{2}{5}right)+(3,2-3,12).(4frac{1}{10}-2,25)
Đọc tiếp
Tìm số nguyên x biết:
a)\(\frac{-150\left(1352-41\right)}{\left(1352-41\right)\left(50-45\right)}\)<x<\(\frac{\left(2400:48\right)-250}{350-\left(3600:12\right)}\)
b)10,07-[3,927-(3,63-\(\frac{3}{20}\))\(\le\)x\(\le\)1,5 \(\left(9,2-\frac{2}{5}\right)\)+(3,2-3,12).(\(4\frac{1}{10}\)-2,25)
Rút gọn:
a,\(\frac{15.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}\)
b,\(\frac{2^{10}.6^{15}+3^{14}.15.4^{13}}{2^{18}.18^7.3^3+3^{15}.2^{25}}\)
Cần gấp ạ
Tính hợp lý:
A) 420 - ( 71+420)
b) ( 35 - 120 ) + ( 120+410-35)
c) (320 - 15 + 49) - ( 85 - 51)
d) -(312 + 59) - (41 + 400 + 88)
e) (430 - 731) - ( -731 + 430 - 56)
f) (1352 - 47) - ( 53 -1000+ 1352)
h) (-42) - (370 + 58) - ( 120 -370)
a) $420-(71+420)$
$=420-71-420$
$=-71$
b) $(35-120)+(120+410-35)$
$=35-120+120+410-35$
$=(35-35)+(-120+120)+410$
$=410$
c) $(320-15+49)-(85-51)$
$=320-15+49-85+51$
$=320+(-15-85)+(49+51)$
$=320+(-100)+100$
$=320$
d) $-(312+59)-(41+400+88)$
$=-312-59-41-400-88$
$=(-312-88)+(-59-41)-400$
$=-400+(-100)-400$
$=-500-400$
$=-900$
e) $(430-731)-(-731+430-56)$
$=430-731+731-430+56$
$=(430-430)+(-731+731)+56$
$=56$
f) $(1352-47)-(53-1000+1352)$
$=1352-47-53+1000-1352$
$=(1352-1352)+(-47-53)+1000$
$=(-100)+1000$
$=1000-100$
$=900$
h) $(-42)-(370+58)-(120-370)$
$=-42-370-58-120+370$
$=(-42-58)+(-370+370)-120$
$=-100-120$
$=-220$
$Toru$
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Các bạn ơi giúp mình với gấp lắm rồi
1.(250+x:24-15)*7=3600
2.729:(32+x-435)=150:15
3.(245:5+x-15):14-5=5
4.502-x+37-13=46+27
5.847+x*6-382=615+42
6.743-27*18-x+38:2-27=18
7.530+48-x+38:2-27=18*12
8.618+x*(386-248:4)=15846
13246 / x = 1352
bài 1:
a) 10\17+5\-13-11\25+7\17-8\13
b) 0,3-93\7-70%0-4\7
c)1\8+1\24+1\48+...+1\2400
d) 3\41-12\17+33\49
-----------------------------
12\41-48\17+132\49
a, \(\dfrac{10}{17}\) + \(\dfrac{5}{-13}\) - \(\dfrac{11}{25}\) + \(\dfrac{7}{17}\) - \(\dfrac{8}{13}\)
= ( \(\dfrac{10}{17}\) + \(\dfrac{7}{17}\)) - ( \(\dfrac{5}{13}\) + \(\dfrac{8}{13}\)) - \(\dfrac{11}{25}\)
= \(\dfrac{17}{17}\) - \(\dfrac{13}{13}\) - \(\dfrac{11}{25}\)
= 1 - 1 - \(\dfrac{11}{25}\)
= - \(\dfrac{11}{25}\)
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b, 0,3 - \(\dfrac{93}{7}\) - 70% - \(\dfrac{4}{7}\)
= 0,3 - 0,7 - ( \(\dfrac{93}{7}+\dfrac{4}{7}\))
= - 0,4 - \(\dfrac{97}{7}\)
= - \(\dfrac{2}{5}\) - \(\dfrac{97}{7}\)
= - \(\dfrac{499}{35}\)
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c, \(\dfrac{1}{8}\) + \(\dfrac{1}{24}\) + \(\dfrac{1}{48}\)+ ...+ \(\dfrac{1}{2400}\)
= \(\dfrac{1}{2\times4}\) +\(\dfrac{1}{4\times6}\) + \(\dfrac{1}{6\times8}\) +...+ \(\dfrac{1}{48\times50}\)
= \(\dfrac{1}{2}\) \(\times\) ( \(\dfrac{2}{2\times4}\) +\(\dfrac{2}{4\times6}\)+ \(\dfrac{2}{6\times8}\) +...+ \(\dfrac{2}{48\times50}\))
= \(\dfrac{1}{2}\) \(\times\) ( \(\dfrac{1}{2}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{6}\) + \(\dfrac{1}{6}\) - \(\dfrac{1}{8}\) +...+ \(\dfrac{1}{48}\) - \(\dfrac{1}{50}\))
= \(\dfrac{1}{2}\) \(\times\) ( \(\dfrac{1}{2}\) - \(\dfrac{1}{50}\))
= \(\dfrac{1}{2}\) \(\times\) \(\dfrac{12}{25}\)
= \(\dfrac{6}{25}\)
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