1/(j - 4) + 1/(4 * 7) + 1/(7 * 10) + 1/(10 * 13) +...+ 1 97*100
Tính:
a)1*4*7+4*7*10+7*10*13+....+100*103*106
b)1*4+4*7+7*10+.....+100*103
c)1*1*1+4*4*4+7*7*7+....+99*99*99
d)1*3*3*3+3*5*5*5+5*7*7*7+.....+49*51*51*51
e)1*99+2*98+3*97+......+50*50
f)1*99+3*97+5*95+....+49*51
Giúp mình nhé!
(1-3/4)*(1-3/7)*(1-3/10)*(1-3/13)*........*(1-3/97)*(1-3/100)
(1-3/4)(1-3/7)(1-3/10)(1-3/13)....(1-3/97)(1-3/100) = ?
\(\left(1-\frac{3}{4}\right)\left(1-\frac{3}{7}\right)\left(1-\frac{3}{10}\right)...\left(1-\frac{3}{97}\right)\left(1-\frac{3}{100}\right)\)
\(=\frac{1}{4}.\frac{4}{7}.\frac{7}{10}.....\frac{94}{97}.\frac{97}{100}\)
\(=\frac{1.4.7.....94.97}{4.7.10.....97.100}\)
\(=\frac{1}{100}\)
1-3/4*1-3/7*1-3/10*1-3/13*............*1-3/97*1-3/100
1+4-7+10-13+16+.....-97+100-103
1+4-7+10-13+16-....-97+100-103
=1 + ( 4-7 ) + ( 10-13 ) + (16-19) + .... +( 94- 97) + (100 - 103)
= 1 -(3 + 3 +.....+ 3)
= 1 - 3*17 = -50
1+4-7+10-13+16+.....-97+100-103
Bl:1+(4-7)+(10-13)+...+(100-103)
=1+(-2)+(-2)+...+(-2)
Có tất cả 34 số -2 nên:
=1+[(-2).34]
=1+(-68)
=-(68-1)
=-67(âm sáu bảy)
Theo đề ta có :
1+4-7+10-13+16-....-97+100-103
suy ra: 1+(4-7)+(10-13)+...+(100-103)=1+(-3)+(-3)+...+(-3). Có tất cả 34 số nên ta có: 1+(-3).34=1+(-112)=(-111).
-1+4-7+10-13+16-.....-97+100-103
-1 + 4 - 7 + 10 - 13 + 16 - ... - 97 + 100 - 103
= (-1 + 4) + (-7 + 10) + (-13 + 16) + ... + (-97 + 100) - 103
= 3 + 3 + 3 + ... + 3 - 103
= 51 - 103
= -52
S1=1-4+7-10+13-16+....+97-100
S1=1-4+7-10+13-16+...+97-100
S1=(1+7+13+...+97)-(4+10+16+...+100)
S1=\(\frac{\left[\left(97-1\right):6+1\right].\left(97+1\right)}{2}-\frac{\left[\left(100-4\right):6+1\right].\left(100+4\right)}{2}\)
S1=\(\frac{17.98}{2}-\frac{17.104}{2}\)
S1=17.49-17.52
S1=17.(49-52)
S1=17.(-3)
S1=-51
Vậy S1=-51
1.Tính
a)-1+4-7+10-13+16-...-97+100-103