\(P\left(x\right)=x^7-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4\)\(+...+\left(x+1\right)x+15\)

\(P\left(x\right)=x^7-x^7-x^6+x^6+...+x^2+x+15\)

\(P\left(x\right)=x+15=94\)

Vậy giá trị của P(x) tại x = 79 là 94 

ng qua ko bt lam a bn

Nguyễn Khắc Nam m khủng hả con

\(C=x^7-80x^6+80x^5-80x^4+80x^3-80x^2+80x+15\)

Ta có x=79 => 80=79+1=x+1

\(C=x^7-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+\left(x+1\right)x^3-\left(x+1\right)x^2+\left(x+1\right)x+15\)

\(C=x^7-x^7-x^6+x^6+x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x+15\)

\(C=x+15=79+15=94\)

Thay x+1=80 ta đc:

\(P\left(x\right)=x^7-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+...+\left(x+1\right)x+15\)

\(=x^7-x^7-x^6+x^6+x^5+...+x^2+x+15\)

\(79+15=94\)

\(Ta \)  \(có \) \(:\)

\(x = 79 \)\(\Rightarrow\)\(x + 1 = 80\)

\(Thay \)  \(x + 1 = 80 \) \(vào \)  \(P(x)\) \(ta\) \(được :\)

\(P ( x ) = x ^7 - ( x + 1 )x ^6 + ( x + 1 )x^5\)\(- ( x + 1 )x ^4\)\(+ ...+ ( x + 1 )x + 15\)

\(P ( x ) = x ^7 - x ^7- x^6 + x^6 + x^5 - x^ 5\)\(- x ^4 + x ^4 + ... - x^ 2 + x ^2 + x + 15\)

\(P ( x ) = x + 15\)

\(Thay x = 79 vào P ( x ) ta được :\)

\(P ( x ) = 79 + 15 = 94\)

\(C=x^7-80x^6+80x^5-80x^4+80x^3-80x^2+80x+15\)

\(=x^7-79x^6-x^6+79x^5+x^5-79x^4-x^4+79x^3+x^3-79x^2-x^2+79x+x-79+94\)

\(=x^6\left(x-79\right)-x^5\left(x-79\right)+x^4\left(x-79\right)-x^3\left(x-79\right)+x^2\left(x-79\right)-x\left(x-79\right)+\left(x-79\right)+94\)

\(=\left(x^6-x^5+x^4-x^3+x^2-x+1\right)\left(x-79\right)+94\)

Thay x = 79 \(\Rightarrow C=94\)

Vậy C = 94 khi x = 79

Thay x = 79 vào C ta có:

C =\(79^7-80.79^6+80.79^5-80.79^4+80.79^3-80.79^2+80.79+15\)

C = \(79^7-\left(79+1\right).79^6+\left(79+1\right).79^5-\left(79+1\right).79^4+\left(79+1\right).79^3-\left(79+1\right).79^2+\left(79+1\right).79+15\)

C = \(79^7-79^7+79^6-79^6+79^5-79^5+79^4-79^4+79^3-79^3+79^2-79^2+79+15\)

C = 79 + 15 = 94

\(C=x^7-80x^6+80x^5-80x^4+80x^3-80x^2+80x+15\)

Ta có: \(x=79\Rightarrow80=79+1=x+1\)

\(C=x^7-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+\left(x+1\right)x^3-\left(x+1\right)x^2+\left(x+1\right)x+15\)

\(C=x^7-x^7-x^6+x^6+x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x+15\)

\(C=x+15=79+15=94\)

Chúc bạn hok tốt!

P(x)=x7−80x6+80x5−8x4+...+80x+15

⇒P(x)=x7−(x+1).x6+(x+1).x5+...+(x+1)x+15

⇒P(x)=x7−x7−x6+x6+x5−x5+...−x3−x2+x2+x+15

⇒P(x)=x+15 (1)

Thay x=79 vào (1),ta được:

P(79)=79+15=84

~ Học tốt ~

x= 79hihi

x=79hihi

\(P\left(x\right)=x^7-80x^6+80x^5-8x^4+...+80x+15\)

\(\Rightarrow P\left(x\right)=x^7-\left(x+1\right).x^6+\left(x+1\right).x^5+...+\left(x+1\right)x+15\)

\(\Rightarrow P\left(x\right)=x^7-x^7-x^6+x^6+x^5-x^5+...-x^3-x^2+x^2+x+15\)

\(\Rightarrow P\left(x\right)=x+15\) \(^{\left(1\right)}\)

Thay \(x=79\) vào \(^{\left(1\right)}\),ta được:

\(P\left(79\right)=79+15=84\)

a)p(x)=x⁷-80x⁶+80x⁵-80x⁴+.........+80+15

=x⁷-(79+1)⁶+(79+1)⁵-(79+1)⁴+.........+(79+1)x+15

mà x=79

=> x⁷-(x+1)⁶+(x+1)⁵-(x+1)⁴+..........+(x+1)x+15

=x⁷-x⁷+x⁶-x⁶+x⁵-x⁵+........+x²+x+15

=x+15

=79+15

=94

\(P\left(x\right)=x^7-80x^6+80x^5-80x^4+80x^3-80x^2+80x+15\)

\(P\left(x\right)=x^7-\left(79+1\right)x^6+\left(79+1\right)x^5-\left(79+1\right)x^4+\left(79+1\right)x^3-\left(79+1\right)x^2+\left(79+1\right)x+15\)

\(P\left(79\right)=x^7-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+\left(x+1\right)x^3-\left(x+1\right)x^2+\left(x+1\right)x+15\)

\(P\left(79\right)=x^7-x^7-x^6+x^6+x^5-x^5-x^4+x^4-x^3+x^3-x^2+x^2+x+15\)

\(P\left(79\right)=79+15\)

\(P\left(79\right)=94\)

Vậy \(P\left(79\right)=94\)