Ta thấy:

\(11^{1979}< 11^{1980}\)

\(11^{1980}=\left(11^3\right)^{660}=1331^{660}\)

Và:

\(37^{1320}=\left(37^2\right)^{660}=1369^{660}\)

Mà: \(1331^{660}< 1369^{660}\)

\(\Rightarrow11^{1979}< 37^{1320}\)

11^1979 và 37^1320 

11^1979 < 12.1979 = (3.2.2)^1979 = 2^1979.6^1979 
37^1320 > 36^1320 = (6^2)^1320 = 6^2640 = 6^661.6^1979 

Ta thấy 

11¹⁹⁷⁹<11¹⁹⁸⁰ = 11^3.660 = (11³)⁶⁶⁰ = 1331⁶⁶⁰

37¹³²⁰ = 37^2.660 = (37²)⁶⁶⁰ = 1369⁶⁶⁰ > 1331⁶⁶⁰

=> 37 ¹³²⁰>11¹⁹⁷⁹

< khó kieens lik e quá chỉ thiếu có 2 cáu huhu

Ta có:

\(11^{1979}< 11^{1980}=\left(11^3\right)^{660}=1331^{660}\)

\(37^{1320}=\left(32^2\right)^{660}=1369^{660}\)

Mà: \(1369^{660}>1331^{660}\)

\(\Rightarrow\)\(11^{1979}< 37^{1320}\)

\(^{11^{1979}}

\(\text{#040911}\)

\(a,\)

\(202^{303}\text{ và }303^{202}\)

Ta có:

\(202^{303}=\left(202^3\right)^{101}=\left(101^3\cdot2^3\right)^{101}=\left(101^3\cdot8\right)^{101}\)

\(303^{202}=\left(303^2\right)^{101}=\left(101^2\cdot3^2\right)^{101}=\left(101^2\cdot9\right)^{101}\)

Ta có:

\(8\cdot101^3=8\cdot101\cdot101^2=808\cdot101^2\)

Vì \(808>9\)

\(\Rightarrow808\cdot101^2>9\cdot101^2\)

\(\Rightarrow202^{303}>303^{202}\)

\(b,\)

Ta có:

\(11^{1979}< 11^{1980}=\left(11^3\right)^{660}=1331^{660}\\ 37^{1320}=\left(37^2\right)^{660}=1369^{660}\\ \text{Vì }1331< 1369\\ \Rightarrow1331^{660}< 1369^{660}\\ \Rightarrow11^{1979}< 37^{1320}\)

mình cần gấp, giúp mình với 

a) \(202^{303}=\left(202^3\right)^{101}=8242408^{101}\)

\(303^{202}=\left(303^2\right)^{101}=91809^{101}< 8242408^{101}\)

\(202^{303}>303^{202}\)

a)2^31=2.2^30=2.8^10

3^21=3.3^20=3.9^10

Vì 2.8^10<3.^10

\(\Rightarrow\)28^10<3.9^10\(\Rightarrow\)2^31<3^21

b)3^39=3^\(^{13x3}\)=159323^3

11^21=11\(^{7x3}\)=19487171^3

Vì 159323^3<19487171^3\(\Rightarrow\)3^39<11^21

c)11^1979<37^1320=(11^3)^660=1331^660

37^1320=(37^2)^660\(\Rightarrow\)11^1979<37^1320

11¹⁹⁷⁹ < 37¹³²⁰