2006 : \(x\) + 1955 = 2014

2006 : \(x\)            = 2014 - 1955

2006 : \(x\)            = 59

           \(x\)            = 2006 : 59

           \(x\)           = 34

 \(x\times35\) - 35 = 1225

\(x\) \(\times\) 35        = 1225 + 35

\(x\times\) 35         = 1260

\(x\)                = 1260 : 35

\(x\)                = 36

981 \(\times\) ( \(x\) + 189) = 185409

            \(x\) + 189 = 185409 : 981

            \(x\) + 189 = 189 

           \(x\)             = 189 - 189 

           \(x\)             = 0

a/ \(2006.|x-1|+1.\left(x-1\right)^2=2005.|1-x|.\)

\(\Rightarrow2006.|x-1|+\left(x-1\right)^2-2005.|1-x|=0\)

Vì \(\hept{\begin{cases}|x-1|\ge0\\|1-x|\ge0\end{cases}}\)

mà \(|x-1|=x-1\)

\(|1-x|=x-1\)\(\Rightarrow|x-1|=|1-x|\)

Thay vào ta được:

\(2006.\left(x-1\right)+\left(x-1\right)^2-2005.\left(x-1\right)=0\)

\(\Rightarrow\left(x-1\right).\left(2006-2005\right)+\left(x-1\right)^2=0\)

\(\Rightarrow\left(x-1\right)+\left(x-1\right)^2=0\)

Vì \(\left(x-1\right)^2\ge0\)với mọi x

nên \(\Rightarrow\hept{\begin{cases}x-1=0\\\left(x-1\right)^2\end{cases}\Rightarrow\hept{\begin{cases}x=1\\x=1\end{cases}}}\)(t/m)

Vậy x = 1

b/ Vì \(\left(x-2014\right)^{2014}\ge0\)với mọi x

\(\left(y-2015\right)^{2014}\ge0\)với mọi y

Để \(\left(x-2014\right)^{2014}+\left(y-2015\right)^{2014}=0\)

\(\Rightarrow\hept{\begin{cases}\left(x-2014\right)^{2014}=0\\\left(y-2015\right)^{2014}=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x-2014=0\\y-2015=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=2014\\y=2015\end{cases}}\)

Vậy : .......

Nhớ k nhé! Thank you!!!

73099

đúng ko

k mk nhé

~Mio~

\(x-67421=5687\)

\(x=5687+67421\)

\(x=73108\)

x-67421=5687

    x=5687+67421

    x=73108

Trả lời:

\(\frac{1}{2004}\times\left(1-\frac{1}{2005}\right)\times\left(1-\frac{1}{2006}\right)\times...\times\left(1-\frac{1}{2014}\right)\)

\(=\frac{1}{2004}\times\frac{2004}{2005}\times\frac{2005}{2006}\times...\times\frac{2013}{2014}\)

\(=\frac{1}{2014}\)

cảm ơn bạn

= 2003/2004 x 2004/2005 x 2005/2006 x .... x 2013/2014

=

= 2003/2014

Chúc bạn học tốt!

456 + (x - 357) = 1362

=> x - 357 = 1362 - 456

=> x - 357 = 906

=> x = 906 + 357

=> x = 1263

c) (x - 2005) . 2006 = 0

=> x - 2005 = 0 : 2006

=> x - 2005 = 0

=> x = 0 + 2005 

=> x = 2005

a) 456 + ( x - 357 ) = 1362

=> x - 357 = 906

=> x = 1263

b) ( 2345 - x ) - 183 = 2014

=> 2345 - x = 2197

=> x = 148

c) ( x - 2005 ) . 2006 = 0

=> x - 2005 = 0

=> x = 2005

còn lại làm tương tự

\(\Leftrightarrow\frac{x-1}{2011}+1+\frac{x-2}{2012}+1+\frac{x-3}{2013}+1+\frac{x-4}{2014}+1-\left(x+2010\right)=0\)

\(\Leftrightarrow\frac{x+2010}{2011}+\frac{x+2010}{2012}+\frac{x+2010}{2013}+\frac{x+2010}{2014}-\left(x+2010\right)=0\)

\(\Leftrightarrow\left(x+2010\right)\left(\frac{1}{2011}+\frac{1}{2012}+\frac{1}{2013}+\frac{1}{2014}-1\right)=0\)

\(\Leftrightarrow x=-2010\)

\(\frac{x-1}{2011}+\frac{x-2}{2012}+\frac{x-3}{2013}+\frac{x-4}{2014}=x+2006\)

\(\Leftrightarrow\frac{x+2010}{2011}+\frac{x+2010}{2012}+\frac{x+2010}{2013}+\frac{x+2010}{2014}=x+2010\)

\(\Leftrightarrow\left(x+2010\right)\left(\frac{1}{2011}+\frac{1}{2012}+\frac{1}{2013}+\frac{1}{2014}\right)=x+2010\)

\(\Leftrightarrow\frac{1}{2011}+\frac{1}{2012}+\frac{1}{2013}+\frac{1}{2014}=1\left(\text{Vô lí}\right)\)

\(\text{Vậy phương trình vô nghiệm.}\)

1. a. 1234.2014+2014.8766

= 2014.(1234+8766)

= 2014.10000

= 20140000

b. 1357.2468-2468.357

= 2468.(1357-357)

= 2468.1000

= 2468000

c. (14678:2+2476).(2576-2575)-> (nếu hợp lí thì chỗ này phải là 2576)

= (7339+2476).1

= 9815.1

= 9815

d. (195-13.15) : (1945+1014)

= (195-195) : (1945+1014)

= 0 : (1945+1014)

= 0

2. a. 456+(x-357)=1362

=> x-357=1362-456

=> x-357=906

=> x=906+357

=> x=1263

b. (2345-x)-183=2014

=> 2345-x=2014+183

=> 2345-x=2197

=> x=2345-2197

=> x=148

c. (x-2005).2006=0

=> x-2005=0:2006

=> x-2005=0

=> x=2005+0

=> x=2005

d. 480+45.4=(x+125):5+260

=> 480+180=(x+125):5+260

=> 660=(x+125):5+260

=> (x+125):5=660-260

=> (x+125):5=400

=> x+125=400.5

=> x+125=2000

=> x=2000-125

=> x=1875

e. 2005.(x-2006)=2005

=> x-2006=2005:2005

=> x-2006=1

=> x=1+2006

=> x=2007

g. [(x+50).50-50]:50=50

=> (x+50).50-50=50.50

=> (x+50).50-50=2500

=> (x+50).50=2500+50

=> (x+50).50=2550

=> x+50=2550:50

=> x+50=51

=> x=51-50

=> x=1

Đúng rồi đây các bạn hihi.....