a)2021+2020x2022/2021x2022-1
b)2022+2021x2023/2022x2023-1
Ai giúp mình nhanh nhanh với!SOS!
2021x2022-1/2020x2022+2021
Các bạn giải giúp mình nhé ❤
[/ nghĩa là phần]
\(\dfrac{2022\times2021-1}{2020\times2022+2021}\)
\(=\dfrac{2022\times2021-1}{2021\times2022-2022+2021}\)
\(=\dfrac{2022\times2021-1}{2021\times2022-1}\)
\(=1\)
Thực hiện phép tính bằng cách thuận tiện nhất ( nếu có thể )
a, 50% + 7/12 - 1/2
b, 2022 x 67 + 2022 x 43 - 2022 x 10
c, 125 - 25 : 3 x 12
d, ( 1/2019x2021 + 1/2020x2022 + 2/2021x2023 ) x ( 1/5 - 1/20 + 1/4 )
\(a,50\%+\dfrac{7}{12}-\dfrac{1}{2}\\ =\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}\\ =\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}\\ =\dfrac{7}{12}\\ b,2022\times67+2022\times43-2022\times10\\ =2022\times\left(67+43-10\right)\\ =2022\times100\\ =202200.\\ c,125-25:3\times12\)
\(=25\times5-25:3\times12\\ =25\times\left(5-\dfrac{1}{3}\right)\times12\\ =25\times\dfrac{14}{3}\times12\\ =1400\)
a,50%+127−21=21+127−21=(21−21)+127=127b,2022×67+2022×43−2022×10=2022×(67+43−10)=2022×100=202200.c,125−25:3×12
tính
a) 1-2-3+4+5-6-7+...+2021-2022-2023
giúp mình nhanh với. tối 8h mình phải nộp rồi. ai đúng mình tick cho nhé
=(1-2)-(3-4)+(5-6)-(7-8)+...+(2021-2022)-2023
=(-1)-(-1)+(-1)-...+(-1)-2023
=0-2023
=-2023
Cho da thuc f(x)=a.x2+b.x+c Tinh f(1)?
tu do hay tinh tong cac he so cua da thuc g(x) sau khi rut gon:
g(x)=(2021x2022-2022x2021+2)2021.(2022x2021-2021x2022-2)2022
f(1)=a+b+c
g(1)=(2021-2022+2)^2021*(2022-2021-2)^2022=1
=>tổng các hệ số của g(x) là 1
(5^2022:5^2021):5^2021
TRL nhanh giúp mình nhé
\(\left(5^{2022}:5^{2021}\right):5^{2021}\)
\(=5^{2022-2021}:5^{2021}\)
\(=5^1:5^{2021}\)
\(=\dfrac{5}{5^{2021}}\)
\(=\dfrac{1}{5^{2021-1}}\)
\(=\dfrac{1}{5^{2020}}\)
So sánh
a, 2020/2021 và 2021/2022
b, 0,5-(2/3)^2 và 24/-36+21/28
ai giúp mik với mik đang cần gấp ai làm nhanh mk tick cho
a)=<
b)=-1/6<1/12
giúp mk, please :)
\(\dfrac{\dfrac{1}{6}+\dfrac{1}{7}+...+\dfrac{1}{2022}}{2017+\dfrac{2016}{6}+\dfrac{2015}{7}+...+\dfrac{1}{2021}}\)
A. \(\dfrac{1}{2020}\)
B. \(\dfrac{1}{2021}\)
C. \(\dfrac{1}{2019}\)
D. \(\dfrac{1}{2022}\)
chọn ra 3 ngừi nhanh nhứt:>>
giải thích cho những ng ko hỉu ;-;
\(=\dfrac{\dfrac{1}{6}+\dfrac{1}{7}+...+\dfrac{1}{2022}}{\left(\dfrac{2016}{6}+1\right)+\left(\dfrac{2015}{7}+1\right)+...+\left(\dfrac{1}{2021}+1\right)+1}\)
\(=\dfrac{\dfrac{1}{6}+\dfrac{1}{7}+...+\dfrac{1}{2022}}{\dfrac{2022}{6}+\dfrac{2022}{7}+...+\dfrac{2022}{2021}+\dfrac{2022}{2022}}\)
\(=\dfrac{\dfrac{1}{6}+\dfrac{1}{7}+...+\dfrac{1}{2022}}{2022.\left(\dfrac{1}{6}+\dfrac{1}{7}+...+\dfrac{1}{2022}\right)}=\dfrac{1}{2022}\)
2022x2023-123/1900+2021x2023
\(\dfrac{2022\times2023-123}{1900+2021\times2023}=\dfrac{\left(2021+1\right)\times2023-123}{2021\times2023+1900}\\ =\dfrac{2021\times2023+2023-123}{2021\times2023+1900}\\ =\dfrac{2021\times2023+1900}{2021\times2023+1900}=1\)