\(B=\frac{1}{2}x\frac{2}{3}x\frac{3}{4}x\frac{4}{5}x...x\frac{2002}{2003}x\frac{2003}{2004}\)

\(B=\frac{1x2x3x4x...x2002x2003}{2x3x4x5x...x2003x2004}\)

Rút gọn các thừa số ở tử và mẫu ta được:

\(B=\frac{1}{2004}\)

                                                                              Đ/S:\(\frac{1}{2004}\)

Ta có:

\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right)....\left(1-\frac{1}{2003}\right).\left(1-\frac{1}{2004}\right)\)

\(=\frac{1}{2}.\frac{2}{3}....\frac{2002}{2003}.\frac{2003}{2004}\)

\(=\frac{1.2....2002.2003}{2.3....2003.2004}\)

Đơn giản hết sẽ là:

\(=\frac{1}{2004}\)

B = \(\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x\left(1-\frac{1}{5}\right)x......x\left(1-\frac{1}{2003}\right)x\left(1-\frac{1}{2004}\right)\)

B = \(\frac{1}{2}x\frac{2}{3}x\frac{3}{4}x\frac{4}{5}x.........x\frac{2002}{2003}x\frac{2003}{2004}\)

B = \(\frac{1x2x3x4x..........x2002x2003}{2x3x4x5x.....x2003x2004}\)

Sau khi trực tiêu các số thì ta có:

B = \(\frac{1}{2004}\)

A=1/2 x 2/3 x 3/4 x ... x 2002/2003 x 2003/2004

=1/2004

XEM LẠI GIÙM MÌNH NHA!

bo ko bt

\(A=\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).\left(1-\dfrac{1}{5}\right)...\left(1-\dfrac{1}{2003}\right).\left(1-\dfrac{1}{2004}\right)\)

\(A=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}....\dfrac{2002}{2003}.\dfrac{2003}{2004}\)

\(A=\dfrac{1}{2004}\)

khó wá ko giải đc 

=1/2x2/3x/3/4/.................x2003/2004

= 1x2x3x................x2003

    ___________________

2x3x4x................x 2004

=1/2004

(1 - 1/2) . (1 - 1/3 ). (1- 1/4) . (1- 1/5).  ....  . (1- 1/2004)

\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot...\cdot\frac{2003}{2004}\)

\(=\frac{1\cdot\left(2\cdot3\cdot4\cdot...\cdot2003\right)}{\left(2\cdot3\cdot4\cdot5\cdot....\cdot2003\right)\cdot2004}\)

\(=\frac{1}{2004}\)

1) =1/2 x 2/3 x 3/4 x 4/5 x .... x 2002/2003 x 2003/2004

=1/2004

2) 1/2 x X-3/4=5/6

1/2 x X =3/4+5/6

1/2 x X =19/12

X=19/6

\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2003}\right).\left(1-\frac{1}{2004}\right)\)

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{2002}{2003}.\frac{2003}{2004}\)

\(=\frac{1.2.3...2002.2003}{2.3.4...2003.2004}=\frac{1}{2004}\)

\(\frac{1}{2}.x-\frac{3}{4}=\frac{5}{6}\)

\(\frac{1}{2}.x=\frac{5}{6}+\frac{3}{4}\)

\(\frac{1}{2}.x=\frac{10}{12}+\frac{9}{12}=\frac{19}{12}\)

\(x=\frac{19}{12}:\frac{1}{2}\)

\(x=\frac{19}{12}.2=\frac{19}{6}\)

(1-1/2) x (1-1/3) x (1-1/4) x...x (1-1/2004)

=1/2 x 2/3 x 3/4 x ... x 2002/2003 x 2003/2004 = 1/2004

1/2 x X -3/4 = 5/6

=> 1/2 x X = 5/6 +3/4 = 19/12

=> x= 19/12 : 1/2

=> x=19/6

16,94 bạn nhé .Kết bạn với nha chấp tay lạy 3 lạy

( 1,6 x 3,5 ) + ( 2,1 x 5,4 ) = 16,94

=16,94 nha