\(\dfrac{4}{5}\times\dfrac{3}{7}\times\dfrac{4}{5}\times\dfrac{6}{7}\times\dfrac{4}{14}=\dfrac{4}{5}\times\dfrac{3}{7}+\dfrac{4}{5}\times\dfrac{6}{7}-\dfrac{4}{5}\times\dfrac{2}{7}=\dfrac{4}{5}\times\left(\dfrac{6}{7}+\dfrac{3}{7}-\dfrac{2}{7}\right)=\dfrac{4}{5}\)

a, 2.9.5.7.4.25=(2.5).(25.4).(7.9)

=10.100.63=63000

câu b làm tương tự tích giúp mình nha

`4/5 xx 3/7 + 4/5 xx 6/7 - 4/5 xx 4/14`

`= 4/5 xx ( 3/7 + 6/7-4/14)`

`= 4/5 xx 1`

`= 4/5`

a) 4 giờ 22 phút x 4 + 5 giờ 38 phút x 4

= ( 4 giờ 22 phút + 5 giờ 38 phút ) x 4

= 10 giờ x 4

=40 giờ

b) 7 phút 30 giây x 7 - 6 phút 30 giây x 7

= ( 7 phút 30 giây - 6 phút 30 giây ) x 7

= 1 phút x 7

= 7 phút

Kết bn với mik nha!

= 4/5 x ( 3/7 + 6/7 - 4/14 )

= 4/5 x ( 3/7 + 6/7 - 2/7 )

= 4/5 x 7/7

= 4/5

1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)

\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)

=0

2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)

\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)

\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)

3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)

\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)

\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)

\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)

\(=\dfrac{52546}{15}\)

4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)

\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)

\(=\dfrac{4}{7}\)

1) Tính biểu thức:

Đặt biểu thức cần tìm =A

Theo bài ra ta có:

A=2.1+3.(-1)+...+199(-1)+200.1

 =2-3+4-5+...-199+200

 =(-1)+(-1)+...+(-1)+200(có [(200-2):2=99 số -1]

 =-99+200

 =101

Đặt \(A=2x^2+3x^3+4x^4+....+199x^{199}+200x^{200}\)

\(=\left(2x^2+4x^4+...+200x^{200}\right)+\left(3x^3+5x^5+...+199x^{199}\right)\)

vì \(x=-1\)

\(\Rightarrow A=\left(2+4+...+200\right)-\left(3+5+...+199\right)\)

\(A=10100-9999=101\)

p/s:1cách nữacủa bài này =))

đúng rồi

a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)

   = \(\frac{11}{21}\)x 3

  = \(\frac{33}{21}\)

b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)

    = 1 x \(\frac{6}{13}\)

    = \(\frac{6}{13}\)

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a, 2x9x5x7x4x25

=2x5x4x25x9x7

=10x100x63

=63000

b,6x14x5x25x3x4

=6x5x3x4x25x14

=90x100x14

=9000x14

=126000

~HT~

\(2\times9\times5\times7\times4\times\)\(25\)

\(=\left(2\times5\right)\times\left(25\times4\right)\)\(\times\left(9\times7\right)\)

\(=10\times1000\times63\)

\(=630000\)