Ta có : 

\(\frac{21^2.14.125}{35^3.6}=\frac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}=\frac{2.3^2.5^3.7^3}{2.3.5^3.7^3}=\frac{3}{1}=3\)

Vậy \(\frac{21^2.14.125}{35^3.6}=3\)

\(\frac{21^2.14.125}{35^3.6}\)= \(\frac{21^2.2.7.125}{42875.2.3}\)= \(\frac{21^2.7.125}{125.343.3}\)= \(\frac{21^2.7.125}{125.7.49.3}\)= \(\frac{21^2}{49.3}\)= \(\frac{441}{147}\)

Mình làm rồi nhưng bạn thử tính lại cho chắc nha

Chúc bạn học tốt!

= 3 nha bạn

Tk mk nha

B=2^18/2^12=2^18:2^12=2^6

\(A=\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^3.\left(3^2\right)^5}{6^{12}}\)

\(=\frac{2^{12}.3^3.3^{10}}{6^{12}}=3^{13}.3^{12}=3^{25}\)

\(A=\frac{4^6.3^4.9^5}{6^{12}}\)

\(A=\frac{2^6.2^6.3^4.3^5.3^5}{2^{12}.3^{12}}\)

\(A=\frac{3^3.3^5}{1}\)

\(A=3^8\)
 

\(B=\frac{21^2.14.125}{35^3.6}\)

\(B=\frac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}\)

\(B=\frac{3.1.1.1.1}{1.1.1.1}\)

\(B=3\)

\(a,=15\left(\dfrac{2121}{4343}+\dfrac{222222}{434343}\right)=15\left(\dfrac{21}{43}+\dfrac{22}{43}\right)=15\cdot1=15\)

chịu

Ta có :

Tử số :

( 2005 + 1 ) . 125 + 1000

2005 . 125 + 125 + 1000

2005 . 125 +1125

Mẫu Số :

( 125 + 1 ) . 2005 - 888

125 . 2005 + 2005 - 888

125 . 2005 + 1117

Ta có phân số : \(\dfrac{2005\cdot125+1125}{125\cdot2005+1117}\) = \(\dfrac{1125}{1117}\)

phân tích hết ra bn ak , sao có cơ so chung là đc

=\(\frac{5^{62}.8^{15}.2^{15}}{8^{19}.5^{63}}\)= \(\frac{2^{15}}{8^4.5}\)= \(\frac{2^{15}}{2^{12}.5}\)= \(\frac{8}{5}\)

\(B=\frac{\left(2^4.3\right)^3.\left(2.5^2\right)^5}{\left(2^6\right)^2.\left(5^3\right)^2.\left(2.3.5\right)^3}\)

\(B=\frac{2^{12}.3^3.2^5.5^{10}}{2^{12}.5^6.2^3.3^3.5^3}\)

\(B=\frac{2^{12}.3^3.2^3.2^2.5^9.5}{2^{12}.5^9.2^3.3^3}\)

\(B=2^2.5=20\)

Vay B = 20