(47 - 52). 3 + 27

= -5. 3 + 27

= -15 + 27

= 12

-4(39 - 19) + 30(-5 - 15)

= -4. 20 + 30. (-20)

= -80 - 600

= -680

36. (-9) + 9. (-64)

= -9(36 + 64)

= -9. 100

= -900

\(\dfrac{15}{17}+\dfrac{32}{17}=\dfrac{15+32}{17}=\dfrac{47}{17}\)

47 - 52). 3 + 27

= -5. 3 + 27

= -15 + 27

= 12

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bạn viết khó hiểu quá

                         =(-5)² .(7/45+11/45)

                          =25 . 2/5

                                =10

\(\left(-5\right)^2.\frac{7}{45}+\left(-5\right)^2.\frac{11}{45}\)

\(=\left(-5\right)^2.\left(\frac{7}{45}+\frac{11}{45}\right)\)

\(=25.\frac{2}{5}\)

\(=10\)

[(27^4:9^5)+(625^3:125^4)]-2^3

=[(531441:59049)+(244140625:244140625)]-8

=[9+1]-8

=10-8

=2

Nếu dk thì cko mik nhoa

\(\left(5.2^2-20\right):\left(5+3^2:6\right)\\ =\left(5.4-20\right):\left(5+9:6\right)\\ =\left(20-20\right):\left(5+\dfrac{3}{2}\right)\\ =1:\dfrac{13}{2}=\dfrac{2}{13}\)

(5*2^2-20):5+3^2/6

=(20-20):5+9/6

=3/2

a)\(x^{15}=x\Rightarrow x\in\left\{0;1\right\}\)                                            d)Là ý b

b)\(\left(2x+1\right)^3=125\\ \left(2x+1\right)^3=5^3\Rightarrow2x+1=5\\ 2x=4\\ x=2\)                       e)\(\left(x-3\right)^2=25\\ \Rightarrow\left(x-3\right)^2=5^2\\ \Rightarrow\hept{\begin{cases}x-3=5\Rightarrow x=8\\x-3=-5\Rightarrow x=-2\end{cases}}\)

c)\(\left(x-5\right)^4=\left(x-5\right)^6\\ \Rightarrow x-5\in\left\{0;1\right\}\Rightarrow x\in\left\{5;6\right\}\)

-3/4+3/4* (x-1/2)+1/6=-1

=0*(x-1/2)=-7/6

nên ko tìm đc x

[x+1]+[x+2]+[x+3]+[x+4]+[x+5]=45

=[x+x+x+x+x]+[1+2+3+4+5]=45

=5x+15=45

5x=30

x=30:5

x=6

Vậy x=6

(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45

(x+x+x+x+x)+1+2+3+4+5=45

5x+15=45

5x=45-15

5x=30

x=30:5

x=6

vậy x=6