Tính Nhanh:\(\frac{1999}{2011}-\frac{2011}{1999}-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
Những câu hỏi liên quan
Tính nhanh:
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
\(=\left(\frac{1999}{2011}+\frac{12}{2011}\right)+\left(-\frac{2011}{1999}+\frac{12}{1999}\right)\)
\(=\frac{2011}{2011}+\frac{-1999}{1999}=1+\left(-1\right)=0\)
\(\frac{1999}{2011}-\frac{2011}{1999}-\left(\frac{-12}{1999}-\frac{12}{2011}\right)=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
\(=\left(\frac{1999}{2011}+\frac{12}{2011}\right)-\left(\frac{2011}{1999}-\frac{12}{1999}\right)=1-1=0\)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
\(=\left(\frac{1999}{2011}+\frac{12}{2011}\right)+\left(\frac{-2011}{1999}+\frac{12}{1999}\right)\)
\(=1-1\)
\(=0\)
Học tốt
Tính nhanh: \(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
\(=\left(\frac{1999}{2011}+\frac{12}{2011}\right)+\left(\frac{-2011}{1999}+\frac{12}{1999}\right)=\frac{2011}{2011}-\frac{1999}{1999}=1-1=0\)
Đúng 0
Bình luận (0)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(-\frac{12}{1999}-\frac{12}{2011}\right)\)
\(=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
\(=\left(\frac{1999}{2011}+\frac{12}{2011}\right)+\left(-\frac{2011}{1999}+\frac{12}{1999}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
Đúng 0
Bình luận (0)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(-\frac{12}{1999}-\frac{12}{2011}\right)=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}=\frac{1999}{2011}-1+\frac{12}{2011}=-\frac{12}{2011}+\frac{12}{2011}=0\)
Đúng 0
Bình luận (0)
tính nhanh
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)\)-\(\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
= \(\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
= \(\left(\frac{1999}{2011}+\frac{12}{2011}\right)-\left(\frac{2011}{1999}+\frac{-12}{1999}\right)\)
= \(\frac{2011}{2011}-\frac{1999}{1999}\)= 1-1 =0
Đúng 0
Bình luận (0)
\(=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}=\frac{1999}{2011}+\frac{12}{2011}\)\(+\left(\frac{-2011}{1999}+\frac{12}{1999}\right)\)\(=1+\left(-1\right)=0\)
Đúng 0
Bình luận (0)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
=\(\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
=\(\left(\frac{1999}{2011}+\frac{12}{2011}\right)-\left(\frac{2011}{1999}-\frac{12}{1999}\right)\)
=\(1-1\)
=\(0\)
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
Tính nhanh:
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(\left(\frac{1999}{2011}-\frac{2011}{199}\right)-\left(-\frac{12}{1999}-\frac{12}{2001}\right)\)
=\(\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
=\(\left(\frac{1999}{2011}+\frac{12}{2011}\right)+\left(-\frac{2011}{1999}+\frac{12}{1999}\right)\)
=\(\frac{2011}{2011}+\frac{1999}{1999}\)
=1+1
=2
Đúng 0
Bình luận (0)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
=\(\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
=\(\left(\frac{1999}{2011}+\frac{12}{2011}\right)+\left(\frac{-2011}{1999}+\frac{12}{1999}\right)\)
=1-1
=-2
Đúng 0
Bình luận (1)
tính nhanh
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(=\frac{1999}{2011}-\frac{2011}{1999}-\frac{12}{1999}+\frac{12}{2011}\)
\(=(\frac{1999}{2011}+\frac{12}{2011})-(\frac{2011}{1999}-\frac{12}{1999})\)
\(=1-1=0\)
Đúng 0
Bình luận (0)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
\(=\left(\frac{1999}{2011}+\frac{12}{2011}\right)+\left(\frac{-2011}{1999}+\frac{12}{1999}\right)\)
\(=1-1\)
\(=0\)
Linz
\((\frac{1999}{2011} - \frac{2011}{1999}) - (\frac{-12}{1999} - \frac{12}{2011}) \)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
\(=\frac{2011}{2011}-\frac{1999}{1999}\)
\(=1-1=0\)
Đúng 0
Bình luận (0)
\(\left(\frac{1999}{2011}-\frac{2011}{1999}\right)-\left(\frac{-12}{1999}-\frac{12}{2011}\right)\)
\(=\frac{1999}{2011}-\frac{2011}{1999}+\frac{12}{1999}+\frac{12}{2011}\)
\(=\frac{2011}{2011}-\frac{1999}{1999}\)
\(=1-1=0\)
Đúng 0
Bình luận (0)
\(\frac{-2011}{2012}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}+\frac{1999}{2011}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}=?\)
Ai đó giúp mình giải nha, cảm ơn
Bạn chỉ giùm mình từng bước nha, cảm ơn
Đúng 0
Bình luận (0)
Mọi người giải giúp mình nha, xin cảm ơn
\(\frac{-2011}{2012}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}+\frac{1999}{2011}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}\)
\(A=\left\{\frac{1999}{2011}-\frac{2011}{1999}\right\}-\left\{\frac{-12}{1999}-\frac{12}{2011}\right\}\)
\(B=\frac{2}{5}+\left(\frac{3}{11}+\frac{-2}{5}\right)\)
\(C=\frac{-5}{7}.\frac{4}{13}+\frac{-5}{7}.\frac{9}{13}+\frac{-2}{7}\)
\(D=\frac{-9}{10}.\frac{5}{14}+\frac{1}{10}.\left(\frac{-9}{2}\right)+\frac{1}{7}.\left(\frac{-9}{10}\right)\)
