chả biết tính kiểu gì

=4024043 nhé

CHÚC BẠN HỌC GIỎI

TK MÌNH NHÉ

2004*2007+6/2005*2005+2009

=4022028+6+2009

=4022034+2009

=4024043

k cho minh nhe

4024037

2004x2007+6/2005x2005-2009=4020025

\(\frac{2004\times2007+6}{2005\times2005-2009}\)

\(=\frac{4022028+6}{4020025-2009}\)

\(=\frac{4022034}{4018016}.\)

a) Ta có:\(\frac{2005}{2007}=1-\frac{2}{2007}\)    \(;\)\(\frac{2007}{2009}=1-\frac{2}{2009}\)

Do\(\frac{2}{2007}>\frac{2}{2009}\Rightarrow1-\frac{2}{2007}< 1-\frac{2}{2009}\Rightarrow\frac{2005}{2007}< \frac{2007}{2009}\)

b) Ta có: \(\frac{2010}{2007}=1+\frac{3}{2007}\)\(;\)\(\frac{2007}{2004}=1+\frac{3}{2004}\)

Do\(\frac{3}{2007}< \frac{3}{2004}\Rightarrow1+\frac{3}{2007}< 1+\frac{3}{2004}\Rightarrow\frac{2010}{2007}< \frac{2007}{2004}\)

+ 2005/2007 = 1 - 2/2007

2007/2009 = 1 - 2/2009

Vì 2/2007 > 2/2009

=> 1 - 2/2007 < 1 - 2/2009

=> 2005/2007 < 2007/2009

+ 2010/2007 = 1 + 3/2007

2007/2004 = 1 + 3/2004

Vì 3/2007 < 3/2004

=> 1 + 3/2007 < 1 + 3/2004

=> 2010/2007 < 2007/2004

cảm ơn nha

Tham khảo

Ta có:

2004×2007+6

=(2005-1)×2007+6

=2005×2007-2007+6

=2005×(2005+2)-2007+6

=2005×2005+2005×2-2007+6

=2005×2005+4010-2007+6

=2005×2005+9

Vậy 

\(=4022028+6+2009\)

\(=4022034+2099\)

\(=4024043\)

\(\dfrac{2004\text{×}2007+6}{2005\text{×}2005+2009}\)

\(=\dfrac{\left(2005-1\right)\text{×}2007+6}{2005\text{×}2005+2009}\)

\(=\dfrac{2005\text{×}2007-2007+6}{2005\text{×}2005+2009}\)

\(=\dfrac{2005\text{×}\left(2005+2\right)-2007+6}{2005\text{×}2005+2009}\)

\(=\dfrac{2005\text{×}2005+2005\text{×}2-2007+6}{2005\text{×}2005+2009}\)

\(=\dfrac{2005\text{×}2005+2009}{2005\text{×}2005+2009}=1\)

`#PhuonggYaa.`

2001 x 2002 x 2003 x 2004 có tận cùng là 4

2005 x 2006 x 2007 x 2008 x 2009 có tận cùng là 0

=> 2001 x 2002 x 2003 x 2004 + 2005 x 2006 x 2007 x 2008 x 2009 có tận cùng là 4 + 0 = 4

2001 x 2002 x 2003 x 2004 + 2005 x 2006 x 2007 x 2008 x 2009

= .....1 x ....2 x ...3 x .....4 + .....5 x ....6 x ....7 x ....8 x....9

= ...2 x...3 x,...4 + ....0 x .....7 x .....8x ....9

= ......6x ....4 + ....0 x ......9

= .....4 + ......0

= ........4 

Vậy : 2001 x 2002 x 2003 x 2004 + 2005 x 2006 x 2007 x 2008 x 2009 có chữ số tận cùng là 4.

vì 1 x 2 x 3 x 4 có tận cùng là 4

    5 x 6 x 7 x 8 x 9 có tận cùng là 0

nên 2001 x 2002 x 2003 x 2004 + 2005 x 2006 x 2007 x 2008 x 2009 có tận cùng là chữ số 4

2003x2005+200=4016215

2004x2004+199=4016215

= 4016215

=4016215

2001³ + 2002³ + 2003³ + 2004³ + 2005³ + 2006³ + 2007³ + 2008³ + 2009³ =  \(\sum\limits^{2009}_{2001}x^3\) = 72541712030