a: =25x100-150=2500-150=2350

c: \(=520:\left\{515\cdot25\right\}\)

=104/2575

Tách từng câu ra giùm, như này ai giải nổi:)))))

Bài 1:

a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\)  + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)

=  \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)

= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)

= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)

= 0 + 1 - \(\dfrac{5}{8}\)

= \(\dfrac{3}{8}\)

b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))

= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)

= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)

= 0 + 0 + 0 - \(\dfrac{7}{5}\)

= - \(\dfrac{7}{5}\)

Bài 1 c;

   \(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))

=  \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)

= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)

= 0 + 0 - 1 + \(\dfrac{80}{87}\)

= - \(\dfrac{7}{87}\)

Bài 1 d; 

   \(\dfrac{1}{25}\) - \(\dfrac{4}{27}\) + (-\(\dfrac{23}{27}\) + \(\dfrac{-1}{25}\) - \(\dfrac{5}{43}\)) + \(\dfrac{5}{43}\) - \(\dfrac{4}{7}\)

= \(\dfrac{1}{25}\) - \(\dfrac{4}{27}\) - \(\dfrac{23}{27}\) - \(\dfrac{1}{25}\) - \(\dfrac{5}{43}\) + \(\dfrac{5}{43}\) - \(\dfrac{4}{7}\)

= (\(\dfrac{1}{25}\) - \(\dfrac{1}{25}\)) - (\(\dfrac{4}{27}\) + \(\dfrac{23}{27}\)) - (\(\dfrac{5}{43}\) - \(\dfrac{5}{43}\)) - \(\dfrac{4}{7}\)

= 0 - 1 - 0 - \(\dfrac{4}{7}\)

= \(\dfrac{-11}{7}\)

15 - (-15 + 2) = 15 + 13 = 28

(-14) - (17 - 8) = -14 - 9 = -23

15 - (21- 7) = 15 - 14 = 1

34 + (-15) - 17 = 19 - 17 = 2

(-34) + (-12) + 18 = -46 + 18 = -28

27 - 15 - 19 = 12 - 19 = -7

34 - (-15) + 8 = 49 + 8 = 57

-37 + 13 - 25 = -24 - 25 = -49

40 - 17 + (-25) = 23 + (-25) = -2

16 + (-15) - 18 = 1 - 18 = -17

15 - 14 - 13 = 1 - 13 = -12

-27 + 15 - 17 = -12 - 17 = -29

34 - 71 = -37

28 - 125 = -97

13 + (-27) = -14

14 - (-34) = 48

28 - (-16) = 44

-15 - 8 = -23

-27 - 34 = -61

-25 - (-18) = -7

46 - 25 - (-25) = 21 + 25 = 46

-37 - (-24) = -13

46 - (-15) = 61

-26 - 6 + 7 = -32 + 7 = -25

@linhcute

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37

=(1+37)x37:2

=703

lop 1 khong co cau nay

Kết quả là 703 nha bạn

a) Ta có:

C = 5/18 + 8/19 - 7/21 + (-10/36 + 11/19 + 1/3) - 5/8

C = 5/18 + 8/19 - 1/3 - 5/18 + 11/19 + 1/3 - 5/8

C = (5/18 - 5/18) + (8/19 + 11/19) - (1/3  - 1/3) - 5/8

C = 1 - 5/8

c = 3/8

b) F = 15/14 - (17/23 - 80/87 + 5/4) + (17/23 - 15/14 + 1/4)

F = 15/14 - 17/23 + 80/87 - 5/4 + 17/23 - 15/14 + 1/4

F = (15/14 - 15/14) - (17/23 - 17/23) + 80/87 - (5/4 - 1/4)

F = 80/87 - 1

F = -7/87

c) G = 1/25 - 4/27 + (-23/27 + -1/25 - 5/43) + 5/43 - 4/7

G = 1/25 - 4/27 - 23/27 - 1/25 - 5/43 + 5/43 - 4/7

G = (1/25 - 1/25) - (4/27 + 23/27) - (5/43 - 5/43) - 4/7

G = -1 - 4/7 = -11/7

1)tính

a)\(-17+\left(-19\right)+25\)

\(=-17-19+25\)

\(=-\left(17+19\right)+25\)

\(=-36+25\)

\(=-\left(36-25\right)\)

\(=-11\)

b)\(-26+\left(-25\right)-18\)

\(=-26-25-18\)

\(=-\left(26+25\right)-18\)

\(=-51-18\)

​\(=-\left(51+18\right)\)​

\(=-69\)

c)\(35-\left(-19\right)-19-8\)

\(=35+19-19-8\)

\(=35+\left(19-19\right)-8\)

\(=35+0-8\)

\(=35-8\)

\(=27\)

d)\(1963-\left(-180\right)-1990\)

\(=1963+180-1990\)

\(=2143-1990\)

\(=153\)

2)Tìm x thuộc z biết

a)\(x-\left(-18\right)=25+\left(-17\right)\)

\(\Leftrightarrow x+18=25-17\)

\(\Leftrightarrow x+18=8\)

\(\Leftrightarrow x=8-18\)

\(\Leftrightarrow x=-10\)

Vậy x=-10

b)\(x-28=-27-30\)

\(\Leftrightarrow x-28=-\left(27+30\right)\)

\(\Leftrightarrow x-28=-57\)

\(\Leftrightarrow x=-57+28\)

\(\Leftrightarrow x=-\left(57-28\right)\)

\(\Leftrightarrow x=-29\)

Vậy x=-29

c)\(35-\left(-x\right)=27-18-\left(-8\right)\)

\(\Leftrightarrow35+x=27-18+8\)

\(\Leftrightarrow35+x=9+8\)

\(\Leftrightarrow35+x=17\)

\(\Leftrightarrow x=17-35\)

\(\Leftrightarrow x=-18\)

Vậy x=-18

d)\(40+\left(-x\right)=35-\left(-27\right)\)

\(\Leftrightarrow40-x=35+27\)

\(\Leftrightarrow40-x=62\)

\(\Leftrightarrow x=40-62\)

\(\Leftrightarrow x=-22\)

Vậy x=-22

Ta có: P > 0 (vì âm nhân âm = dương)

Q < 0 (vì âm nhân âm nhân âm nhân dương = âm)

M = 0 (vì có thừa số 0/17)

Vậy Q<M<P

A

C

c