\(=\dfrac{5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)

\(=\dfrac{2^{29}\cdot3^{18}\left(5\cdot2-9\right)}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}=2\)

\(\dfrac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}=\dfrac{5.2^{30}.3^{18}-2^{29}.3^{20}}{2^{28}.3^{19}.5-7.2^{29}.3^{18}}=\dfrac{2^{29}.3^{18}\left(5.3+3^2\right)}{2^{28}.3^{18}\left(3.5+7.2\right)}=\dfrac{2.24}{29}=\dfrac{48}{29}\)

ʇɐɥʇ ɥuɐɹ uɐq ɔɐɔ ɐl ƃunp ıɥʇ ʎɐp uǝp ɔonp ɔop uɐq ɔɐɔ ɐl ʇǝıq ɥuıɯ ƃunɥu 'ɔonp ɔop ıoɯ ıɐl ɔonƃu ʎɐox ıɐɥd ɐʌ ɔop oɥʞ ɐl ʇɐɹ ıɥʇ ʎɐu ǝɥʇ ʇǝıʌ ɐl ʇǝıq ɥuıɯ

mjk dịch đc nè''

mình ko cần xoay ngược cũng đọc đc

bằng 2. nhấn đúng cho mih nha

tố uyên sai rồi

\(\frac{5.2^{30}.3^{18}-2^{^2}.3^{^{20}}.2^{^{27}}}{5.2^{^9}.6^{^{19}}-7.2^{^{29}}.27^{^6}}\)

\(=\frac{5.2^{^{30}}.3^{^{18}}-2^{^{29}}.3^{^{20}}}{5.2^{^9}.2^{^{19}}.3^{^{19}}-7.2^{^{29}}.\left(3^{^3}\right)^6}\)

\(=\frac{5.2.2^{^{29}}.3^{^{18}}-2^{^{29}}.3^{^2}.3^{^{18}}}{5.2^{^{28}}.3^{^{19}}-7.2^{^{29}}.3^{^{18}}}\)

\(=\frac{2^{^{29}}.3^{^{18}}\left(2.5-3^{^2}\right)}{5.2^{^{28}}.3.3^{^{18}}-7.2.2^{^{28}}.3^{^{18}}}\)

\(=\frac{2^{^{29}}.3^{^{18}}.\left(10-9\right)}{2^{^{28}}.3^{^{18}}.\left(5.3-7.2\right)}\)

\(=\frac{2^{^{29}}.3^{^{18}}}{2^{^{28}}.3^{^{18}}}=2\)

Học tốt

#Gấu

\(A=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.6^{19}-7.2^{29}.3^{18}}\)

\(A=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

\(A=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)

\(A=\frac{2^{29}.3^{18}.\left(5.2.1-9\right)}{2^{28}.3^{18}.\left(5.1.3-7.2.1\right)}\)

\(A=\frac{2.1}{1}=2\)

thank you bạn nha, Le Quang Phúc. 

A=2²⁷ .3¹⁸(5.2³-4.3²)

2²⁸.3¹⁸(5.3-7.2) 

( 40-36)

2(15-14)

=4/2=2

CÂU TRẢ LỜI CỦA TUI CÓ DẤU GẠCH GIỮA PS NHÉ

\(\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{2^{29}.3^{18}\left(5.2-9\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)

\(\frac{5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)

\(\frac{2^{28}\cdot3^{18}\left(5\cdot2^2-2\cdot3^2\right)}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}\)

\(\frac{5\cdot2^2-2\cdot3^2}{5\cdot3-7\cdot2}\)

\(\frac{5\cdot4-2\cdot9}{15-14}\)

\(\frac{20-18}{1}\)

\(\frac{2}{1}=2\)

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