` a/` 

` 3 1/5 : 2 1/3 : y = 12/7 `

` 48/35 : y = 12/7 `

` y = 48/35 : 12/7 `

` y = 48/35 xx 7/12 `

` y = 4/5`

Vậy ` y = 4/5` 

`b/`

` 3 : y xx 3 1/2 = 2/3 xx 3/4 `

` 3 : y xx 7/2 =  1/2`

` 3 : y = 1/2 : 7/2 `

` 3 : y = 1/2 xx 2/7 `

` 3 : y = 1/7 `

`      y = 3 : 1/7 `

`      y = 3 xx 7`

`      y = 21 `

 Vậy ` y = 21 `

`c/` 

` 3 2/3 - y + 1 3/4 = 2`

` 11/3 - y + 7/4 = 2 `

`   11/3 -y  = 2 - 7/4`

`    11/3 - y = 1/4 `

`        y = 11/3 - 1/4 `

`        y = 41/12  `

Vậy ` y = 41/12`

Hai bạn đều đúng 

Bạn B phải bỏ dấu ngoặc

(12:y):3 =4 

Hai bạn A và B đều đúng 

y x 3 = 246 – 12

y x 3 = 234

y = 234 : 3

y = 78

Y×3=246-12

Y×3=234

Y=234÷3

Y=78

y x 3 = 246 - 12
y x 3 = 234 
      y = 234 : 2
 => y = 117

yx3+y/2+y/4=11/2:y

yx3+y:2+y:4=5,5:y

yx3+y:(2+4)=5.5:y

yx3+y:6=5,5:y

yx3+yx1/6=5,5:y

yx(3+1/6)=5,5:y

yx19/6=5,5:y

...........................

bn ơi là 1\(\frac{1}{2}\)

bài 1

A)37/60

B)13/45

C)1/4

bài 2

a)42/25:y/5=5/6

y=10,08

b)27/y:9/4=3/7

y=28

Bài 1:

a,Ta có:\(\frac{3}{5}=\frac{3\times2}{5\times2}=\frac{6}{10}\)      (1)

              \(\frac{4}{5}=\frac{4\times2}{5\times2}=\frac{8}{10}\)       (2)

Từ (1) và (2)=> Một phân số tối giản nằm giữa hai phân số trên là:\(\frac{7}{10}\)

b,Ta có:\(\frac{3}{5}=\frac{3\times3}{5\times3}=\frac{9}{15}\)

               \(\frac{4}{5}=\frac{4\times3}{5\times3}=\frac{12}{15}\)

=> hai phân số ở giữa là:\(\frac{10}{15}=\frac{2}{3};\frac{11}{12}\)

 Yx(7+1-3+5)=7800
Yx10=7800
Y=7800:10
Y=780
 

\(a,2\dfrac{2}{5}:y\times1\dfrac{3}{4}=\dfrac{7}{8}\\ \dfrac{12}{5}:y\times\dfrac{7}{4}=\dfrac{7}{8}\\ \dfrac{12}{5}:y=\dfrac{7}{8}:\dfrac{7}{4}\\ \dfrac{12}{5}:y=\dfrac{1}{2}\\ y=\dfrac{12}{5}:\dfrac{1}{2}=\dfrac{24}{5}\\ b,3\dfrac{2}{5}:y:1\dfrac{1}{4}=2\dfrac{3}{5}\\ \dfrac{17}{5}:y:\dfrac{5}{4}=\dfrac{13}{5}\\ y:\dfrac{5}{4}=\dfrac{17}{5}:\dfrac{13}{5}\\ y:\dfrac{5}{4}=\dfrac{17}{13}\\ y=\dfrac{17}{13}\times\dfrac{5}{4}=\dfrac{85}{52}\)

\(c,\dfrac{12}{5}-2\dfrac{2}{5}\times y=1\dfrac{1}{4}\\ \dfrac{12}{5}-\dfrac{12}{5}\times y=\dfrac{5}{4}\\ \dfrac{12}{5}\times y=\dfrac{12}{5}-\dfrac{5}{4}\\ \dfrac{12}{5}\times y=\dfrac{23}{20}\\ y=\dfrac{23}{20}:\dfrac{12}{5}\\ y=\dfrac{23}{48}\)

a, 2\(\dfrac{2}{5}\): y \(\times\)1\(\dfrac{3}{4}\) = \(\dfrac{7}{8}\)

     \(\dfrac{12}{5}\) : y   \(\times\dfrac{7}{4}\)    = \(\dfrac{7}{8}\)

   \(\dfrac{12}{5}\)  : y         = \(\dfrac{7}{8}\) : \(\dfrac{7}{4}\)

          \(\dfrac{12}{5}\) : y        = \(\dfrac{1}{2}\)       

                  y         = \(\dfrac{12}{5}\) : \(\dfrac{1}{2}\)

                  y         =    \(\dfrac{24}{5}\)

b, 3\(\dfrac{2}{5}\): y : 1\(\dfrac{1}{4}\) = 2\(\dfrac{3}{5}\) 

     \(\dfrac{17}{5}\): y: \(\dfrac{5}{4}\)    = \(\dfrac{13}{5}\)

       \(\dfrac{17}{5}\):y         = \(\dfrac{13}{5}\times\dfrac{5}{4}\)

       \(\dfrac{17}{5}\) : y       = \(\dfrac{13}{4}\)

               y        =   \(\dfrac{17}{5}\) : \(\dfrac{13}{4}\)

               y        =  \(\dfrac{68}{65}\)

c, \(\dfrac{12}{5}\) - 2\(\dfrac{2}{5}\)\(\times y\) = 1\(\dfrac{1}{4}\)

     \(\dfrac{12}{5}\) - \(\dfrac{12}{5}\)\(\times\)y = \(\dfrac{5}{4}\)

            \(\dfrac{12}{5}\times y\) =  \(\dfrac{12}{5}\) - \(\dfrac{5}{4}\)

           \(\dfrac{12}{5}\) \(\times\) y =    \(\dfrac{23}{20}\)

                     \(y\)  = \(\dfrac{23}{20}\): \(\dfrac{12}{5}\)

                     y   = \(\dfrac{23}{48}\)