3 . 52 - 16 : 22
mình đang cần rất gấp
504 : ( 16 - 3 . x ) = 72
( 22 . x - 52 ) . 38 = 39
\(\Rightarrow16-3x=504:72=7\\ \Rightarrow3x=16-7=9\Rightarrow x=3\\ \left(2^2\cdot x-5^2\right)\cdot3^8=3^9\\ \Rightarrow4x-25=3^9:3^8=3\\ \Rightarrow4x=28\Rightarrow x=7\)
504 : (16 - 3x) = 72 (ĐK: \(x\ne\dfrac{16}{3}\))
<=> 16 - 3x = 504 : 72
<=> 16 - 3x = 7
<=> 16 - 7 = 3x
<=> 3x = 9
<=> x = 3 (tM)
(22x - 52) . 38 = 39
<=> (4x - 25) . 6561 = 19683
<=> 4x - 25 = 19683 : 6561
<=> 4x - 25 = 3
<=> 4x = 3 + 25
<=> 4x = 28
<=> x = 7
16 x 25 24 x 75
316-(52 x 22 x 9) : 23 - 3 x 23
tớ cần gấp ạ
Bài 2:
a. $=58(75+50-25)=58.100=5800$
b. $=27.8+4.9-5=216+36-5=247$
Bài 3:
a.
$(x-38):16=12$
$x-38=16\times 12=192$
$x=192+38 = 230$
b.
$10+2x=4^5:4^3=4^2=16$
$2x=16-10=6$
$x=6:2=3$
c.
$440+2(125-x)=546$
$2(125-x)=546-440=106$
$125-x=106:2=53$
$x=125-53=72$
d.
$(x-15):5+20=22$
$(x-15):5=22-20=2$
$x-15=2\times 5=10$
$x=10+15=25$
e.
$2x-138=2^3.3^2=8.9=72$
$2x=72+138 = 210$
$x=210:2=105$
Bài 3:
f.
$2.3^x-5=7^2$
$2.3^x=7^2+5=54$
$3^x=54:2=27=3^3$
$\Rightarrow x=3$
g.
$7x-3^3=2^7:2^4$
$7x-27=2^3=8$
$7x=27+8=35$
$x=35:7=5$
h.
$427-(x+100)=227$
$x+100=427-227 = 200$
$x=200-100=100$
i.
$2x-138=2^3.3^2=8.9=72$
$2x=72+138 = 210$
$x=210:2=105$
k.
$(6x-18):3+25.2=78$
$(2x-6)+50=78$
$2x-6=78-50=28$
$2x=28+6=34$
$x=34:2=17$
Bài Toàn 16 : Tính tổng
a) S = 1 + 2 + 22 + 23 + … + 22017
b) S = 3 + 32 + 33 + ….+ 32017
c) S = 4 + 42 + 43 + … + 42017
d) S = 5 + 52 + 53 + … + 52017
a.
$S=1+2+2^2+2^3+...+2^{2017}$
$2S=2+2^2+2^3+2^4+...+2^{2018}$
$\Rightarrow 2S-S=(2+2^2+2^3+2^4+...+2^{2018}) - (1+2+2^2+2^3+...+2^{2017})$
$\Rightarrow S=2^{2018}-1$
b.
$S=3+3^2+3^3+...+3^{2017}$
$3S=3^2+3^3+3^4+...+3^{2018}$
$\Rightarrow 3S-S=(3^2+3^3+3^4+...+3^{2018})-(3+3^2+3^3+...+3^{2017})$
$\Rightarrow 2S=3^{2018}-3$
$\Rightarrow S=\frac{3^{2018}-3}{2}$
Câu c, d bạn làm tương tự a,b.
c. Nhân S với 4. Kết quả: $S=\frac{4^{2018}-4}{3}$
d. Nhân S với 5. Kết quả: $S=\frac{5^{2018}-5}{4}$
tim tỉ số A/B biết
A=34/7*13+51/13*22+85/22*37+68/37*49
B=39/7*16+65/16*31+52/31*43+26/43*49
tinh a/b biet a=24/7*13+51/13*22+85/22*37+68/37*49
b=39/7*16+65/16*31+52/31*43+26/43*49
Thực hiện phép tính:
a, 36:{336:[200–(12+8.20)]}
b, {145–[130–(246–236)]:2}.5
c, 100:{250:[450–(4. 5 3 – 2 2 .25]}
d, 798+100:[16–2.( 5 2 –22)]
e, (6954+1525:5+47.19).(29–58.2)
f, 2 4 .157– 2 4 .58+16
a, 36:{336:[200–(12+8.20)]}
= 36:{336:[200–(12+160)]}
= 36:{336:[200–172]}
= 36:{336:28}
= 36:12 = 3
b, {145–[130–(246–236)]:2}.5
= {145–[130–10:2]}.5
= {145–130}.5
= 20.5 = 100
c, 100:{250:[450–(4. 5 3 – 2 2 .25]}
= 100:{250:[450–400]}
= 100:{250:50}
= 100:5 = 20
d, 798+100:[16–2.( 5 2 –22)]
= 798+100:10
= 798+10 = 808
e, (6954+1525:5+47.19).(29–58.2)
= (6954+1525:5+47.19).0 = 0
f, 2 4 .157– 2 4 .58+16
= 16.(157–58+1) = 1600
a) 513 : 510 – 25.22
b) 20 : 22 + 59 : 58
c) 100 : 52 + 7.32
d) 84 : 4 + 39 : 37 + 50
e) 29 – [16 + 3.(51 – 49)]
f) 5.22 + 98:72
g) 311 : 39 – 147 : 72
h) 295 – (31 – 22.5)2
718 : 716 +22.33
\(a)\) \(5^{13}:5^{10}-25.2^2=5^3-25.4=125-100=25\)
\(b)\) \(20:2^2+5^9:5^8=20:4+5^1=5+5=10\)
\(c)\) \(100:5^2+7.3^2=100:25+7.9=4+36=40\)
\(d)\) \(84:4+3^9:3^7+5^0=84:4+3^2+1=21+9+1=31\)
\(e)\)
\(29-\left[16+3.\left(51-49\right)\right]=29-\left[16+3.2\right]=29-\left[16+6\right]=29-22=7\)
\(f)\) \(5.2^2+98:7^2=5.4+98:49=20+2=22\)
\(g)\) \(3^{11}:3^9-147:7^2=3^2-147:49=9-3=6\)
\(295-\left(31-2^2.5\right)^2=295-\left(31-4.5\right)^2=295-\left(31-20\right)^2=295-11^2=295-121=174\)
\(7^{18}:7^{16}+2^2.3^2=7^2+4.9=49+36=85\)
a: \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^3-25\cdot4\)
=125-100
=25
b: \(20:2^2+5^9:5^8\)
\(=20:4+5\)
=5+5
=10
Bài 2
a) 12+ 22 + 32 + 42+52 và (1+2+3+4+5)2
b) 13+ 23+33 +43 và (1+2+3+4)3
c) 16 . 5200 và 5202
d) 18 . 4500 và 21004
e) 2022 . 2023 2024 + 20232024 và 20232025
a: \(12+2^2+3^2+4^2+5^2\)
\(=12+4+9+16+25\)
\(=16+50=66\)
\(\left(1+2+3+4+5\right)^2=15^2=225\)
=>\(12+2^2+3^2+4^2+5^2< \left(1+2+3+4+5\right)^2\)
b: \(1^3+2^3+3^3+4^3=\left(1+2+3+4\right)^2< \left(1+2+3+4\right)^3\)
c: \(5^{202}=5^2\cdot5^{200}=25\cdot5^{200}>16\cdot5^{200}\)
d: \(18\cdot4^{500}=18\cdot2^{1000}\)
\(2^{1004}=2^4\cdot2^{1000}=16\cdot2^{1000}\)
=>\(18\cdot4^{500}>2^{1004}\)
e: \(2022\cdot2023^{2024}+2023^{2024}=2023^{2024}\left(2022+1\right)\)
\(=2023^{2025}\)
492 - 49 . (-52) - 49________________
12 . (-47) + 12 . (-19) + (-66) . 88____________________
1 - 4 - 7 + 10 + 13 - 16 - 19 + 22 - 25_________
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