\(\frac{3}{4}.26\frac{1}{5}.\frac{3}{4}.44\frac{1}{5}=\frac{3}{4}.\frac{131}{5}.\frac{3}{4}.\frac{221}{5}=651,3975\)

  \(\dfrac{37}{4}+\dfrac{44}{7}\) + \(\dfrac{38}{5}\) + \(\dfrac{26}{3}\) + \(\dfrac{1}{3}\) + \(\dfrac{5}{7}\) + \(\dfrac{3}{4}\)

= ( \(\dfrac{37}{4}+\) \(\dfrac{3}{4}\)) + ( \(\dfrac{26}{3}+\dfrac{1}{3}\)) + (\(\dfrac{44}{7}+\dfrac{5}{7}\)) + \(\dfrac{38}{5}\)

= \(\dfrac{40}{4}\) + \(\dfrac{27}{3}\) + \(\dfrac{49}{7}\) + \(\dfrac{38}{5}\)

= 10 + 9 + 7 + \(\dfrac{38}{5}\)

=26 + 7,6

= 33,6 

\(=\frac{3}{20}\left(44-26\right)=\frac{3}{20}\cdot18=\frac{27}{10}\)

Bài làm

      \(-\frac{3}{4}.26\frac{1}{5}+\frac{3}{4}.44\frac{1}{5}\)

\(=\frac{3}{4}.\left(-\frac{131}{5}\right)+\frac{3}{4}.\left(\frac{221}{5}\right)\)

\(=\frac{3}{4}.\left(-\frac{131}{5}+\frac{221}{5}\right)\)

\(=\frac{3}{4}.\frac{90}{5}\)

\(=\frac{3}{2}.18\)

\(=27\)

# Học tốt #

\(-\frac{3}{4}.26\frac{1}{5}+\frac{3}{4}.44\frac{1}{5}\)

= \(\frac{3}{4}.-\frac{131}{5}+\frac{3}{4}.\frac{221}{5}\)

= \(\frac{3}{4}.\left(-\frac{131}{5}+\frac{221}{5}\right)\)

= \(\frac{3}{4}.\frac{90}{5}\)

= \(\frac{27}{2}\)

Chúc bạn học tốt !!!

=  -27/2 nha bn

học tốt

\(\frac{3}{4}\cdot26\frac{1}{5}-\frac{3}{4}\cdot44\frac{1}{5}\)

\(=\frac{3}{4}\cdot\frac{131}{5}-\frac{3}{4}\cdot\frac{221}{5}\)

\(=\frac{3}{4}\cdot\left(\frac{131}{5}-\frac{221}{5}\right)\)

\(=\frac{3}{4}\cdot\left(-18\right)\)

\(=-\frac{27}{2}\)

\(\frac{3}{4}.26\frac{1}{5}-\frac{3}{4}.44\frac{1}{5}\)

\(=\frac{3}{4}.\left(26\frac{1}{5}-44\frac{1}{5}\right)\)

\(=\frac{3}{4}.\left(-18\right)\)\(=\frac{-27}{2}\)

\(\frac{3}{4}.26\frac{1}{5}-\frac{3}{4}.44\frac{1}{5}\)

= \(\frac{3}{4}.\left(26\frac{1}{5}-44\frac{1}{5}\right)\)

= \(\frac{3}{4}\) . (-18)

= \(\frac{-27}{2}\)

\(\frac{3}{4}.26\frac{1}{5}-\frac{3}{4}44\frac{1}{5}\)

= \(\frac{3}{4}\left(26\frac{1}{5}-44\frac{1}{5}\right)\)

= \(\frac{3}{4}\left(26+\frac{1}{5}-44-\frac{1}{5}\right)\)

=\(\frac{3}{4}.\left(-18\right)\)

=-13,5

Ta có: 3/4. 26/1/5 - 3/4.44/1/5

= 3/4.(26/1/5-44/1/5)

= 3/4.(26-44)

= 3/4. (-18)

= -27/2

What if I "không thể" (can't)?

a) \(\left(-8,43.25\right).0,4\)

\(=\left(-8,43\right).\left(25.0,4\right)\)

\(=\left(-8,43\right).10\)

\(=-84,3\)

b) \(\dfrac{3}{4}.26\dfrac{1}{5}-\dfrac{3}{4}.44\dfrac{1}{5}\)

\(=\dfrac{3}{4}.\left(26\dfrac{1}{5}-44\dfrac{1}{5}\right)\)

\(=\dfrac{3}{4}.\left(-18\right)\)

\(=-\dfrac{27}{2}\)

c) \(2-1,8:\left(-0,75\right)\)

\(=2-\left(-2,4\right)\)

\(=2+2,4\)

\(=4,4\)

d) \(\left(-3\right)^2.\dfrac{1}{3}-\sqrt{49}+\left(-5\right)^3:\sqrt{25}\)

\(=9.\dfrac{1}{3}-7+\left(-125\right):5\)

\(=3-7-25\)

\(=-29\)

\(a,\left(-8,43.25\right).0,4=-210,75.0,4=-84,3\)

\(b,\dfrac{3}{4}.26\dfrac{1}{5}-\dfrac{3}{4}.44\dfrac{1}{5}=\dfrac{3}{4}.26,2-\dfrac{3}{4}.44,2\)

\(=\dfrac{3}{4}.\left(26,2-44,2\right)\)

\(=\dfrac{3}{4}.\left(-18\right)\)

\(=-13,5\)

\(c,2-1,8:\left(0,75\right)=2-2,4\)

\(=-0,4\)

tìm x biết:

(3x-1) [- 1/2x+5]=0

1/4+1/3:(2x-1)=-5

[2x+3/5]² - 9/25=0

-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6

[x+1/2]x [2/3-2x]=0

17/2-|2x-3/4|=-7/4

2/3x-1/2x =5/12

(x+1/5)²+17/25=26/25

[x.44/7+3/7].11/5-3/7=-2

3[3x-1/2]+1/9=0

Toán lớp 6Tìm x

 Trả lời  Câu hỏi tương tự

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3(3x-1/2)^3+1/9=0